Problem 10
Question
Use the results of this section to evaluate the given limit. $$ \lim _{x \rightarrow 0} f(x), \text { where } f(x)=\left\\{\begin{array}{ll} -\frac{3}{2} x+\frac{1}{4} & \text { for } x \neq \frac{1}{2} \\ 0 & \text { for } x=0 \end{array}\right. $$
Step-by-Step Solution
Verified Answer
The limit is \(\frac{1}{4}\).
1Step 1: Check the definition
First, examine the definition of the piecewise function \( f(x) \). The function is defined as \(-\frac{3}{2} x + \frac{1}{4} \) for all \(x eq \frac{1}{2}\) and is specifically 0 when \(x = 0\). Since we are interested in \( \lim _{x \rightarrow 0} f(x) \), we only need the part of the function defined for \(x eq \frac{1}{2}\).
2Step 2: Substitute into the relevant function expression
For \(x\) approaching 0, the relevant part of the function is \(-\frac{3}{2} x + \frac{1}{4}\). Since function behavior at a specific point \(x=0\) does not determine the limit, evaluate the expression assuming values are close to but not necessarily equal to 0.
3Step 3: Evaluate the limit of the expression
Now, compute \(\lim _{x \rightarrow 0} (-\frac{3}{2} x + \frac{1}{4})\). Substituting \(x = 0\), we get:\[\begin{align*}\lim_{x \rightarrow 0} \left(-\frac{3}{2} x + \frac{1}{4}\right) & = -\frac{3}{2}(0) + \frac{1}{4} \& = 0 + \frac{1}{4} \& = \frac{1}{4}\end{align*}\]This gives us the limit value.
Key Concepts
Piecewise FunctionsLimit EvaluationFunction Substitution
Piecewise Functions
A piecewise function is a type of function defined by different expressions depending on the input value within certain intervals. It essentially "pieces" together multiple functions, forming a whole. Think of it like designing a patchwork quilt, where each patch serves a purpose but with individual conditions.Here's how it works:
- Each "piece" of the function is valid over a specific range of inputs.
- The function switches between different expressions based on these input values.
- This allows modeling of complex scenarios where a single formula might not suffice.
Limit Evaluation
Evaluating limits involves finding what value a function approaches as the input gets close to a certain point. This is a critical concept in calculus, allowing the analysis of behaviors of functions near specific values, often revealing insights not evident from direct substitution.To evaluate a limit, especially in piecewise functions, focus on the part relevant to the approaching value. For our example:
- The limit \( \lim_{x \to 0} f(x) \) is being sought.
- While \((x = 0)\) gives a definite value from the piecewise definition, it does not contribute to the limit.
- Investigate the behavior of \(-\frac{3}{2}x + \frac{1}{4}\) as \(x\) nears 0 from either direction (from the right or left).
Function Substitution
Function substitution is a basic technique where you replace the variable with another value to determine behavior at different points. This is especially useful in solving limits.For the problem:
- First identify which piece of the piecewise function you're considering.
- When \(x\to 0\), the expression to evaluate is \(-\frac{3}{2}x + \frac{1}{4}\).
- Substitute \(x = 0\) into the equation: \(-\frac{3}{2} \times 0 + \frac{1}{4} = \frac{1}{4}\).
Other exercises in this chapter
Problem 10
Determine whether \(f\) is continuous or discontinuous at \(a\). If \(f\) is discontinuous at \(a\), determine whether \(f\) is continuous from the right at \(a
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First simplify the given expression and then guess the value of the limit. \(\lim _{x \rightarrow 1} \frac{x^{2}+4 x-5}{x-1}\)
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Determine the infinite limit. $$ \lim _{x \rightarrow 0}-1 / x^{2} $$
View solution Problem 11
Determine whether \(f\) is continuous or discontinuous at \(a\). If \(f\) is discontinuous at \(a\), determine whether \(f\) is continuous from the right at \(a
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