Problem 10
Question
Use the distributive property to compute each value. $$ 80 \cdot 58 $$
Step-by-Step Solution
Verified Answer
The value of \(80 \cdot 58\) is 4640.
1Step 1: Break Down the Problem
We want to compute the value of the expression \(80 \cdot 58\) using the distributive property. The distributive property states that \(a(b + c) = ab + ac\). This property can help us simplify large multiplications.
2Step 2: Rewrite the Second Number
We will rewrite 58 as a sum that is easy to work with. 58 can be rewritten as \(50 + 8\). This will allow us to distribute 80 over the sum \(50 + 8\).
3Step 3: Apply the Distributive Property
Now, let's apply the distributive property: \[80 \cdot (50 + 8) = 80 \cdot 50 + 80 \cdot 8\]
4Step 4: Calculate Each Term
Compute each term separately:1. \(80 \cdot 50 = 4000\)2. \(80 \cdot 8 = 640\)
5Step 5: Sum the Products
Add the two products we calculated:\[4000 + 640 = 4640\]
6Step 6: Verify the Solution
To ensure the calculation is correct, verify by other means such as long multiplication. Confirm \(80 \cdot 58 = 4640\).
Key Concepts
MultiplicationSimplifying ExpressionsApplication of Distributive Property
Multiplication
Multiplication is a fundamental arithmetic operation that involves combining groups of equal sizes. It is denoted by the symbol \(\cdot\) or simply by writing numbers next to each other. For instance, computing \(3 \cdot 4\) means having 3 groups of 4, which equals 12. It is a quick and efficient way to add the same number repeatedly.
In our example, we were tasked with multiplying 80 by 58. This might seem cumbersome at first glance, but breaking down numbers can simplify things significantly.
In our example, we were tasked with multiplying 80 by 58. This might seem cumbersome at first glance, but breaking down numbers can simplify things significantly.
- Understand that multiplication is associative, meaning you can change the grouping of numbers — for example, \((a \cdot b) \cdot c = a \cdot (b \cdot c)\).
- It is also commutative, so the order of numbers does not affect the result — \(a \cdot b = b \cdot a\).
- Knowing these properties helps in re-arranging numbers effectively for easier calculation.
Simplifying Expressions
Simplifying expressions involves reducing them to more manageable forms without changing their values. In arithmetic, this often means breaking down large, unwieldy numbers into parts that are simpler to handle.
In the exercise with 80 and 58, our aim was to find simpler component numbers for 58, which can be split into 50 and 8. A breakdown like this keeps calculations neat and straightforward. Here are some points to remember when simplifying expressions:
In the exercise with 80 and 58, our aim was to find simpler component numbers for 58, which can be split into 50 and 8. A breakdown like this keeps calculations neat and straightforward. Here are some points to remember when simplifying expressions:
- Look for numbers that sum up to or break down a number naturally. For instance, use numbers like 10, 50, or 100 that simplify multiplication.
- Always try to rearrange elements within expressions to align with arithmetic operations that you find simpler.
- Check that the values remain equal after simplification, ensuring accuracy.
Application of Distributive Property
The distributive property is an essential algebraic tool that allows us to multiply a single term across terms within parentheses. It enables the multiplication of each term individually and then sums the results. This is formulated as \(a(b + c) = ab + ac\).
In the given example, we used the distributive property by rewriting the multiplication of 80 with 58 as two distinct operations: multiplying 80 by 50 and 80 by 8. These results were then added together, providing the final result.
In the given example, we used the distributive property by rewriting the multiplication of 80 with 58 as two distinct operations: multiplying 80 by 50 and 80 by 8. These results were then added together, providing the final result.
- Always identify the sum or difference suitable for distribution in a composite number.
- Apply distribution step-by-step to prevent errors. Compute each resulting expression before summing up.
- Verifying the results through long multiplication or a calculator ensures the distribution was applied correctly.
Other exercises in this chapter
Problem 10
Estimate each value. After you have made an estimate, find the exact value. Results may vary. \((\) Section 8.2\() 43.06+37.94\)
View solution Problem 10
Estimate each value using the method of rounding. After you have made an estimate, find the exact value. Compare the exact and estimated values. Results may var
View solution Problem 10
Use the clustering method to estimate each sum. Results may vary. $$ 41+28+42+37 $$
View solution Problem 10
Estimate the quotient: \(221 \div 18\).
View solution