Problem 10
Question
Use linear combinations to solve the linear system. Then check your solution. \(m+3 n=2\) \(-m+2 n=3\)
Step-by-Step Solution
Verified Answer
After solving, we find that the solution is \(m = -1\) and \(n = 1\).
1Step 1: Add the two equations
We first add the two equations to find a new equation. Adding the left sides of the two equations: \(m + 3n + -m + 2n\) and the right sides \(2 + 3\) of the equations we get \(5n = 5\).
2Step 2: Solve for n
Next, we isolate \(n\) by dividing both sides of the equation by 5, which yields \(n = 1\).
3Step 3: Substitute n=1 in the first equation
Once \(n\) is found, we substitute \(n = 1\) into the first equation: \(m + 3*1 = 2\), which simplifies to \(m = -1\).
4Step 4: Check the solution
Finally, we verify these solutions by substituting \(m = -1\) and \(n = 1\) into the second equation. The left hand side becomes \(-(-1) + 2*1 = 3\), which equals to the right hand side, confirming that the solution is accurate.
Key Concepts
Linear SystemSolution VerificationSubstitution MethodEquation Solving
Linear System
A linear system is a collection of two or more linear equations involving the same set of variables. In this case, we have two equations with two unknowns, represented as:
- \( m + 3n = 2 \)
- \( -m + 2n = 3 \)
Solution Verification
Solution verification is an indispensable step in solving a system of equations. After obtaining a potential solution, it's crucial to verify it satisfies all original equations. This confirms the accuracy of the solutions. In our case:
- We found \( n = 1 \) and \( m = -1 \).
- Insert these values back into the original equations.
- For \( m + 3n = 2 \): Substitute \( m = -1 \) and \( n = 1 \). It simplifies to \( -1 + 3*1 = 2 \), which is true.
- For \( -m + 2n = 3 \): Substitute \( m = -1 \) and \( n = 1 \). It simplifies to \( -(-1) + 2*1 = 3 \), also true.
Substitution Method
The substitution method is one strategy to find solutions of a linear system. It involves expressing one variable from one of the equations and substituting it in the other. In this exercise:
- First, solve one equation for one variable. We did this indirectly in the step-by-step solution by adding and eliminating \( m \).
- Once \( n = 1 \) was found, substitute this value back into an equation to solve for \( m \).
- In a more typical approach, you would express \( m \) in terms of \( n \) or vice versa directly and substitute back.
Equation Solving
Equation solving involves finding specific values for variables that satisfy a given equation or set of equations. Often this requires manipulating the equations algebraically:
- Combine terms by addition or subtraction.
- Isolate terms with the variable of interest by using multiplication or division.
- Simplify equations to deduce clear solutions.
Other exercises in this chapter
Problem 10
Tell which equation you would use to isolate a variable. Explain. $$ \begin{aligned} &2 x+y=-10\\\ &3 x-y=0 \end{aligned} $$
View solution Problem 10
Check whether the ordered pair is a solution of the system of linear equations. $$ \begin{array}{c} {-5x+y=19} \\ { x-7y=3} \end{array} \quad(-4,-1) $$
View solution Problem 11
Tell which equation you would use to isolate a variable. Explain. $$ \begin{aligned} &m+4 n=30\\\ &m-2 n=0 \end{aligned} $$
View solution Problem 11
Check whether the ordered pair is a solution of the system of linear equations. $$ \begin{array}{c} {-15x+7y=1} \\ { 3x-y=1} \end{array} \quad(3,5) $$
View solution