Problem 10
Question
The \(n\) th term of an arithmetic sequence is given. (a) Find the first five terms of the sequence, (b) What is the common difference \(d\) ? (c) Graph the terms you found in part (a). $$a_{n}=\frac{1}{2}(n-1)$$
Step-by-Step Solution
Verified Answer
First five terms: 0, \(\frac{1}{2}\), 1, \(\frac{3}{2}\), 2. Common difference \(d = \frac{1}{2}\). Graph by plotting these points on a coordinate plane.
1Step 1: Understand the Formula
The formula given for the nth term of the arithmetic sequence is \(a_n = \frac{1}{2}(n-1)\). This formula will help us find the terms of the sequence, and the common difference.
2Step 2: Find the First Term
To find the first term, substitute \(n = 1\) into the formula: \(a_1 = \frac{1}{2}(1-1) = \frac{1}{2} \times 0 = 0\). So, the first term \(a_1 = 0\).
3Step 3: Find the Second Term
Substitute \(n = 2\) into the formula to find the second term: \(a_2 = \frac{1}{2}(2-1) = \frac{1}{2} \times 1 = \frac{1}{2}\). So, the second term \(a_2 = \frac{1}{2}\).
4Step 4: Find the Third Term
Substitute \(n = 3\) into the formula: \(a_3 = \frac{1}{2}(3-1) = \frac{1}{2} \times 2 = 1\). Hence, \(a_3 = 1\).
5Step 5: Find the Fourth Term
For the fourth term, substitute \(n = 4\) into the formula: \(a_4 = \frac{1}{2}(4-1) = \frac{1}{2} \times 3 = \frac{3}{2}\). Thus, \(a_4 = \frac{3}{2}\).
6Step 6: Find the Fifth Term
Calculate the fifth term by substituting \(n = 5\): \(a_5 = \frac{1}{2}(5-1) = \frac{1}{2} \times 4 = 2\). So, \(a_5 = 2\).
7Step 7: Verify Sequence and Find Common Difference
The first five terms are: \(0, \frac{1}{2}, 1, \frac{3}{2}, 2\). The common difference \(d\) can be calculated as the difference between consecutive terms. Thus, \(d = \frac{1}{2}\).
8Step 8: Graph the Sequence
Plot the terms \((1,0), (2,\frac{1}{2}), (3,1), (4,\frac{3}{2}), (5,2)\) on a graph. The x-axis represents the terms index \(n\), and the y-axis represents the term value \(a_n\). Connect these points to form a straight line.
Key Concepts
Common DifferenceSequence Graphingn-th Term Formula
Common Difference
In an arithmetic sequence, the common difference \(d\) is the constant amount that you add to each term to get to the next term. This constant difference is what makes the sequence "arithmetic." To find \(d\), simply subtract any term from the term that comes after it. In our example, the sequence starts with the terms \(0, \ \frac{1}{2}, \ 1, \ \frac{3}{2}, \ \text{and} \ 2\). By subtracting each term from the subsequent term:
- \(\frac{1}{2} - 0 = \frac{1}{2}\)
- \(1 - \frac{1}{2} = \frac{1}{2}\)
- \(\frac{3}{2} - 1 = \frac{1}{2}\)
- \(2 - \frac{3}{2} = \frac{1}{2}\)
Sequence Graphing
Graphing an arithmetic sequence can help you visualize the growth of the sequence over time. To graph, simply create a set of coordinate points using the term's index \(n\) as the x-value and the term's value \(a_n\) as the y-value. In our sequence
- The point for \(n=1\) is \((1, 0)\)
- The point for \(n=2\) is \((2, \frac{1}{2})\)
- The point for \(n=3\) is \((3, 1)\)
- The point for \(n=4\) is \((4, \frac{3}{2})\)
- The point for \(n=5\) is \((5, 2)\)
n-th Term Formula
The n-th term formula \(a_n = \frac{1}{2}(n-1)\) allows you to find any term in the arithmetic sequence without having to list all the previous terms. In this formula:
- \(a_n\) is the term number \(n\)
- \(n-1\) represents how many common differences are added to the first term
- \(\frac{1}{2}\) is the common difference \(d\)
- If \(n = 1\), \(a_1 = \frac{1}{2}(1-1) = 0\)
- If \(n = 2\), \(a_2 = \frac{1}{2}(2-1) = \frac{1}{2}\)
- If \(n = 3\), \(a_3 = \frac{1}{2}(3-1) = 1\)
Other exercises in this chapter
Problem 9
Pascal's Triangle Use Pascal's triangle to expand the expression. $$(x-1)^{5}$$
View solution Problem 9
Use mathematical induction to prove that the formula is true for all natural numbers \(n\) $$1^{3}+2^{3}+3^{3}+\cdots+n^{3}=\frac{n^{2}(n+1)^{2}}{4}$$
View solution Problem 10
Saving How much money should be invested monthly at \(6 \%\) per year, compounded monthly, to have \(\$ 2000\) in 8 months?
View solution Problem 10
Find the \(n\) th term of the geometric sequence with given first term \(a\) and common ratio \(r .\) What is the fourth term? $$a=-3, \quad r=-2$$
View solution