Problem 10
Question
The LCD for \(\frac{2 x+1}{x^{2}+5 x+6}\) and \(\frac{3 x}{x^{2}-4}\) is $$\mathrm{LCD}=(x+2)(x+3)(x-2)$$ If we want to subtract these rational expressions, what form of 1 should be used: a. to build \(\frac{2 x+1}{x^{2}+5 x+6} ?\) b. to build \(\frac{3 x}{x^{2}-4} ?\)
Step-by-Step Solution
Verified Answer
Use \( \frac{x-2}{x-2} \) for \( \frac{2x+1}{x^2+5x+6} \) and \( \frac{x+3}{x+3} \) for \( \frac{3x}{x^2-4} \).
1Step 1: Factor the Denominators
First, factor the denominators of the given expressions. For \( \frac{2x+1}{x^2+5x+6} \), the denominator factors into \((x+2)(x+3)\). For \( \frac{3x}{x^2-4} \), the denominator factors into \((x-2)(x+2)\).
2Step 2: Identify Missing Factors
Next, identify what factors are missing from each denominator in relation to the LCD. The LCD given is \((x+2)(x+3)(x-2)\). For the first expression, \((x-2)\) is missing. For the second expression, \((x+3)\) is missing.
3Step 3: Build the Form of 1 for the First Expression
To rewrite \( \frac{2x+1}{x^2+5x+6} \) with the LCD, multiply the numerator and the denominator by the missing factor \((x-2)\). Thus, the form of 1 to be used is \( \frac{x-2}{x-2} \).
4Step 4: Build the Form of 1 for the Second Expression
To rewrite \( \frac{3x}{x^2-4} \) with the LCD, multiply the numerator and the denominator by the missing factor \((x+3)\). Thus, the form of 1 to be used is \( \frac{x+3}{x+3} \).
Key Concepts
FactoringRational ExpressionsSubtracting Fractions
Factoring
Factoring is a fundamental process in algebra, crucial for simplifying expressions and solving equations. It involves rewriting an expression as a product of its factors. For instance, the expression \( x^2 + 5x + 6 \) can be factored into \((x+2)(x+3)\), where each factor, when multiplied together, gives the original expression. Similarly, \( x^2 - 4 \) can be factored into \((x-2)(x+2)\) using the difference of squares method.
The key to successful factoring is recognizing special patterns and using them to break down complex expressions:
The key to successful factoring is recognizing special patterns and using them to break down complex expressions:
- **Difference of Squares:** An expression of the form \(a^2 - b^2\) factors into \((a-b)(a+b)\).
- **Perfect Square Trinomials:** Expressions like \(a^2 + 2ab + b^2\) factor into \((a+b)^2\).
- **Common Factoring:** Sometimes the easiest way to factor an expression is by taking out the greatest common factor (GCF) shared among the terms.
Rational Expressions
Rational expressions are fractions where both the numerator and denominator are polynomials. Understanding their properties is essential when dealing with operations like addition, subtraction, multiplication, or division. The key similarity with numeric fractions is the necessity for a common denominator in operations involving addition or subtraction.
To work effectively with rational expressions:
To work effectively with rational expressions:
- First, always factor the numerators and denominators where possible. This simplifies the expression and helps identify common factors.
- Identifying the Least Common Denominator (LCD) is crucial. It is the least common multiple of the denominators, ensuring each rational expression can be rewritten with this common base.
- The process of finding an LCD may involve factoring, examining the factors required for each denominator, and then combining them, avoiding duplicates.
Subtracting Fractions
Subtracting fractions, including rational expressions, requires a shared denominator. This necessity stems from ensuring both fractions are "measuring" parts of the same whole, allowing their differences to be logically calculated.
The process can be broken down into key steps:
The process can be broken down into key steps:
- **Ensure a Common Denominator:** If the rational expressions don't share a common denominator, identify and use the Least Common Denominator (LCD) to rewrite them equivalently.
- **Rewrite Each Expression:** Multiply the numerator and denominator of each expression by a 'form of 1'—comprised of the factors needed to match the LCD. This doesn't change the value, just its form.
- **Subtract the Numerators:** Once the denominators are the same, subtract the numerators while keeping the denominator constant. It simplifies the operation, focusing on just the numerator adjustments.
- **Simplify the Resulting Expression:** If possible, further simplify the resulting expression by factoring again and reducing it to its simplest form.
Other exercises in this chapter
Problem 10
Fill in the blanks. For \(P(x)=x^{3}-4 x^{2}+x+6,\) suppose we know that \(P(3)=0\) Then _____ is a factor of \(x^{3}-4 x^{2}+x+6\).
View solution Problem 10
Solve equation. \(\frac{1}{3}-\frac{10}{x}=-3\)
View solution Problem 10
Complete each solution. a. Write \(5 x^{2}+35 x\) as a fraction. b. What is the reciprocal of \(5 x^{2}+35 x ?\)
View solution Problem 10
Fill in the blanks to simplify \(\frac{x-y}{y-x}\) $$ \frac{x-y}{y-x}=\frac{-y+}{y-x}=\frac{(y-x)}{(y-x)}= $$
View solution