Problem 10
Question
The following gas-chromatographic data were obtained for individual \(2-\mu \mathrm{L}\), injections of \(n\) -hexane in a gas chromatograph with a \(3-\mathrm{m}\) column. Calculate the number of plates and \(H\) at each flow rate, and plot \(H\) versus the flow rate to determine the optimum flow rate. Use the adjusted retention time \(t_{R}^{\prime}\). \( \begin{array}{cccc}\hline \text { Flow rate }(\mathrm{mL} / \mathrm{min}) & t_{M} \text { (Air Peak) (min) } &t_{R}^{\prime}(\min ) & \text { Peak Width (min) } \\ \hline 120.2 & 1.18 & 5.49 & 0.35 \\ 90.3 & 1.49 & 6.37 & 0.39 \\ 71.8 & 1.74 & 7.17 & 0.43 \\\ 62.7 & 1.89 & 7.62 & 0.47 \\ 50.2 & 2.24 & 8.62 & 0.54 \\ 39.9 & 2.58 & 9.83 & 0.68 \\ 31.7 & 3.10 & 11.31 & 0.81 \\ 26.4 & 3.54 & 12.69 & 0.95 \\\ \hline \end{array} \)
Step-by-Step Solution
VerifiedKey Concepts
Theoretical Plates
- More plates mean better resolution of compounds in a mixture.
- The larger the value of N, the sharper and more distinct the peaks on the chromatogram.
Understanding this helps chromatographers optimize separation processes for better results.
Retention Time
- It is an important parameter for identifying compounds based on known standards.
- Shorter retention times typically indicate faster separation but may affect resolution.
- Longer retention times can enhance separation but may increase analysis duration.
Optimizing retention time involves balancing these factors to achieve efficient and precise results.
Chromatographic Efficiency
- Column length: Longer columns can improve resolution but require more time.
- Flow rate: Adjusting flow rate may affect how well peaks are separated.
- Stationary phase: The choice of stationary phase material can enhance efficiency.
The objective is to find the optimal balance of these factors to achieve maximum efficiency, allowing for the most effective separation of analytes.