Problem 10
Question
The \(3^{\prime}\)-exonuclease activity of \(E\). coli DNA polymerase I was found to show no discrimination between correctly and incorrectly base-paired nucleotides at the \(3^{\prime}\)-terminus; properly and improperly base-paired nucleotides are cleaved at equal rates there. How can this observation be reconciled with the fact that the \(3^{\prime}\)-exonuclease activity increases the accuracy with which template DNA is copied?
Step-by-Step Solution
Verified Answer
3'-Exonuclease increases accuracy by removing terminal nucleotides, allowing for correction of mismatches.
1Step 1: Understand the Function of the 3'-Exonuclease
The 3'-exonuclease activity of DNA polymerase I is an enzymatic function that removes nucleotides from the 3'-end of a DNA strand. This activity is important for the proofreading and correction of errors during DNA replication, thus contributing to the overall fidelity of the process.
2Step 2: Analyze the Non-Discriminative Cleavage
The observation that the 3'-exonuclease does not discriminate between correct and incorrect base pairs means that it removes nucleotides regardless of whether they are mismatched or correctly paired. This suggests a generalized removal process rather than a selective one.
3Step 3: Identify the Role in Accuracy Improvement
Despite its non-discriminative nature, the 3'-exonuclease activity aids in increasing accuracy by continuously excising nucleotides from the 3'-end. This allows for the correct base pair to be re-added by the polymerase, thereby correcting any mismatches that do occur, leading to improved fidelity.
4Step 4: Reconcile Non-Discrimination with Increased Fidelity
The increase in accuracy arises because the 3'-exonuclease removes the terminal nucleotide, irrespective of correctness, allowing the polymerase another chance to add the correct base. This mechanism ensures that mismatches are less likely to be propagated, effectively reducing the error rate during DNA replication.
Key Concepts
3'-Exonuclease ActivityE. coli DNA Polymerase IProofreading MechanismNucleotide Excision
3'-Exonuclease Activity
DNA replication is a complex process where accuracy is crucial. The 3'-exonuclease activity plays a vital role in maintaining this accuracy. It refers to the enzymatic function of removing nucleotides from the 3'-end of a DNA strand, one at a time.
This action is essential for proofreading during DNA replication. Despite its lack of discrimination between correctly and incorrectly paired nucleotides, this activity contributes significantly to maintaining replication fidelity.
This action is essential for proofreading during DNA replication. Despite its lack of discrimination between correctly and incorrectly paired nucleotides, this activity contributes significantly to maintaining replication fidelity.
- The removal of nucleotides from the DNA strand's end is a key function.
- This indiscriminate removal paves the way for adding the correct nucleotide.
- 3'-exonuclease activity thus ensures errors are minimized, correcting mistakes dynamically.
E. coli DNA Polymerase I
E. coli DNA Polymerase I is an enzyme found in the bacterium E. coli. It is an essential player in DNA replication, repair, and recombination. This enzyme doesn't just synthesize DNA; it also acts as a quality checker because of its dual function.
It's remarkably effective due to its three key activities:
It's remarkably effective due to its three key activities:
- Polymerase activity: Adds nucleotides to growing DNA strands, facilitating replication.
- 3'-exonuclease activity: Enacts the proofreading mechanism by removing nucleotides from the DNA strand's 3'-end.
- 5'-exonuclease activity: Participates in removing RNA primers and aiding DNA repair.
Proofreading Mechanism
The proofreading mechanism is an error-correcting process during DNA replication. It ensures that DNA polymerase very rarely makes mistakes, maintaining high genetic accuracy. Here’s how it works:
The process involves the 3'-exonuclease activity, where any nucleotide potentially misplaced during replication is removed. This activity is neither selective, only recognizing terminal nucleotides without identifying mismatches, nor infallible.
However, this indiscriminately providing another chance for the polymerase to add the correct base is essential.
The process involves the 3'-exonuclease activity, where any nucleotide potentially misplaced during replication is removed. This activity is neither selective, only recognizing terminal nucleotides without identifying mismatches, nor infallible.
However, this indiscriminately providing another chance for the polymerase to add the correct base is essential.
- Errors made during DNA synthesis are fixed.
- The polymerase continuously checks the accuracy of each base added.
- Re-selection and insertion of the correct nucleotide enhance fidelity.
Nucleotide Excision
Nucleotide excision is a process that removes a few nucleotides surrounding a damaged site on DNA to ensure its integrity. It is different from exonuclease activity in that it generally targets larger DNA sections.
Primarily, it is involved in DNA repair. For instance, when nucleotides are damaged due to UV radiation, the excision mechanism kicks in to remove and replace these damaged segments. This repair method is not directly connected to the proofreading activity of 3'-exonuclease but plays a crucial role in overall genomic maintenance.
Primarily, it is involved in DNA repair. For instance, when nucleotides are damaged due to UV radiation, the excision mechanism kicks in to remove and replace these damaged segments. This repair method is not directly connected to the proofreading activity of 3'-exonuclease but plays a crucial role in overall genomic maintenance.
- Recognizes and excises damaged DNA sections.
- Paths a way for fresh synthesis cycles to repair or accommodate changes.
- Works in synergy with other repair mechanisms to protect the DNA sequence.
Other exercises in this chapter
Problem 8
Suppose that a replicative DNA polymerase had its \(3^{\prime}\) exonuclease site \(1.5 \mathrm{~nm}\) from the polymerase site, rather than the \(3.0 \mathrm{~
View solution Problem 9
Although DNA polymerases require both a template and a primer, the following single-stranded polynucleotide was found to serve as a substrate for DNA polymerase
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What information would you need to tell whether the leading and lagging strands in yeast are replicated with equal fidelity?
View solution Problem 13
It takes 40 minutes to completely replicate the \(E\) coli chromosome, even in an optimally nourished cell. However, bacterial cells can divide as frequently as
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