The maximum number of trees (7100) is planted with 11 experienced teams and 8 training teams, using all 16 trainees. The solution that uses all the trainees gives the same number of trees planted (7100).
1Step 1 - Define Variables
Let the variable x represent the number of experienced teams (two rangers per team) and the variable y represent the number of training teams (one ranger and two trainees per team).
2Step 2 - Write the Objective Function
The objective function represents the total number of trees planted by both types of teams. It is formulated as follows: Maximize: Z = 500x + 200y.
3Step 3 - Write the Constraints from Rangers
The number of rangers used in all teams must not exceed 30. This leads to the constraint from the number of experienced teams and training teams: 2x + y ≤ 30.
4Step 4 - Write the Constraints from Trainees
The number of trainees used in the training teams must not exceed 16, leading to the constraint: 2y ≤ 16 or y ≤ 8.
5Step 5 - Write the Non-Negativity Constraints
Since the number of teams cannot be negative, the non-negativity constraints are: x ≥ 0 and y ≥ 0.
6Step 6 - Solve the Linear Program to Maximize the Objective Function
Since both constraints are linear, and the objective function is to be maximized, use graphical methods or linear programming techniques such as the simplex method to find the values of x and y that maximize Z subject to the constraints.
7Step 7 - Checking the Corners of the Feasible Region
Evaluate the objective function at each corner point of the feasible region defined by the constraints. Possible corner points include (0, 8), (15, 0), and the point where the lines 2x + y = 30 and y = 8 intersect.
8Step 8 - Calculate the Intersection Point
To find the intersection of 2x + y = 30 and y = 8, substitute y into the first equation: 2x + 8 = 30, which gives x = 11. The intersection point is (11, 8).
9Step 9 - Evaluate the Objective Function at the Intersection Point
Plugging the intersection point (11, 8) into the objective function Z = 500x + 200y, we get Z = 500(11) + 200(8) = 5500 + 1600 = 7100.
10Step 10 - Choose the Maximal Value
Comparing the values of Z for each corner point, the maximal value is at the intersection point (11, 8), which is Z = 7100 trees.
11Step 11 - Find Solution that Uses all Trainees
If all trainees must be used, then y = 8. Substitute y = 8 into the ranger constraint 2x + y = 30 to find x, leading to 2x = 22, so x = 11.
12Step 12 - Calculate Number of Trees Planted Using All Trainees
Using x = 11 and y = 8 in the objective function Z = 500x + 200y gives the total number of trees planted as Z = 500(11) + 200(8) = 7100.