Problem 10
Question
Suppose \(f: X \rightarrow X\) is a contraction, and \((X, d)\) is a metric space with the discrete metric, that is \(d(x, y)=1\) whenever \(x \neq y .\) Show that \(f\) is constant, that is, there exists a \(c \in X\) such that \(f(x)=c\) for all \(x \in X\).
Step-by-Step Solution
Verified Answer
The function \( f \) is constant because the contraction condition forces \( f(x) = f(y) \) for all \( x, y \in X \) with a discrete metric.
1Step 1: Define a Contraction
A function \( f: X \rightarrow X \) is called a contraction if there exists a constant \( 0 \leq k < 1 \) such that \( d(f(x), f(y)) \leq k \cdot d(x, y) \) for all \( x, y \in X \). Here, \( (X, d) \) is a metric space with the discrete metric.
2Step 2: Understand the Discrete Metric
In a discrete metric space, the distance \( d(x, y) = 1 \) when \( x eq y \) and \( d(x, x) = 0 \) by definition of a metric. This implies each pair of distinct points in \( X \) is 1 unit apart.
3Step 3: Apply the Contraction Property
Using the contraction definition, for any \( x, y \in X \), we have \( d(f(x), f(y)) \leq k \cdot d(x, y) \). If \( x eq y \), then \( d(x, y) = 1 \), so \( d(f(x), f(y)) \leq k < 1 \). But in the discrete metric, the distance can only be 0 or 1, thus \( d(f(x), f(y)) = 0 \).
4Step 4: Conclude f Is Constant
From Step 3, \( d(f(x), f(y)) = 0 \) implies that \( f(x) = f(y) \) for any \( x, y \in X \). This means \( f \) takes the same value for all elements in \( X \). Thus, there exists a \( c \in X \) such that \( f(x) = c \) for all \( x \in X \).
Key Concepts
Contraction MappingDiscrete MetricConstant FunctionReal Analysis
Contraction Mapping
In real analysis, a contraction mapping is a function that brings points closer together in a specific way. When we say a function \( f: X \to X \) is a contraction, it means there's a special number called the contraction constant, denoted as \( 0 \leq k < 1 \). For any two points \( x \) and \( y \) in our metric space \((X, d)\), the condition that defines a contraction is:
- \(d(f(x), f(y)) \leq k \cdot d(x, y)\)
Discrete Metric
A discrete metric is one of the simplest forms of a metric. In this type of metric space, the idea is quite straightforward:
- The distance \(d(x, y) = 1\) if \(x eq y\)
- The distance \(d(x, x) = 0\) always
Constant Function
A constant function is a special type of function where every input value maps to the same output value. Formally, a function \(f: X \to Y \) is constant if there exists some \( c \in Y \) such that for all \( x \in X \), \( f(x) = c \). This means that no matter what input you plug into the function, the output always remains the same.Constant functions exhibit a unique behavior:
- They significantly simplify problems, as there is no variation in their outputs.
- In the context of metric spaces with contraction properties, the discrete metric forces any nontrivial contraction to become a constant function.
Real Analysis
Real analysis is a branch of mathematics that deals with real numbers and real-valued sequences and functions. It focuses on rigorously studying concepts such as limits, continuity, differentiation, integration, and series.
In the real analysis framework, understanding how functions behave within a given metric space is crucial. This involves concepts like contraction mappings and constant functions, revealing:
- How functions can operate under different metrics, such as discrete metrics.
- The intricate relationships between point mappings that can transform dynamic inputs into uniform outputs via contraction.
Other exercises in this chapter
Problem 9
Let \((X, d)\) be a nonempty metric space and \(S \subset X\) a subset. Prove: a) \(S\) is bounded if and only if for every \(p \in X,\) there exists \(a B>0\)
View solution Problem 10
Suppose \(\left\\{S_{i}\right\\}, i \in \mathbb{N}\) is a collection of connected subsets of a metric space \((X, d) .\) Suppose there exists an \(x \in X\) suc
View solution Problem 10
Suppose \((X, d)\) is complete and suppose we have a countably infinite collection of nonempty compact sets \(E_{1} \supset E_{2} \supset E_{3} \supset \cdots .
View solution Problem 10
Take \(\mathbb{R}^{*}=\\{-\infty\\} \cup \mathbb{R} \cup\\{\infty\\}\) be the extended reals. Define \(d(x, y):=\left|\frac{x}{1+|x|}-\frac{y}{1+|y|}\right|\) i
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