Problem 10
Question
Solve the following quadratic equations. \(y^{2}+64=0\)
Step-by-Step Solution
Verified Answer
y = 8i, y = -8i
1Step 1: Isolate the quadratic term
Subtract 64 from both sides of the equation: y^{2} = -64
2Step 2: Solve for y
Take the square root of both sides to solve for y. Remember to include both the positive and negative solutions:y = \pm \sqrt{-64}Notice that \(\sqrt{-64}\) can be simplified using imaginary numbers:
3Step 3: Simplify the square root of a negative number
Recall that \(\sqrt{-1} = i\) (where i is the imaginary unit). Then:\(\sqrt{-64} = \sqrt{-1 \cdot 64} = \sqrt{-1} \cdot \sqrt{64} = i \cdot 8 = 8i\)Therefore, the solutions are:y = \pm8i
Key Concepts
Imaginary NumbersSolving Quadratic Equations
Imaginary Numbers
Imaginary numbers are numbers that result from taking the square root of a negative number. The imaginary unit is denoted as \(i\), where \(i = \sqrt{-1}\). These numbers are essential when dealing with quadratic equations that do not have real solutions.
For instance, in the given problem, we have \(\sqrt{-64}\). Since the square root of a negative number isn't a real number, we use the imaginary unit \(i\):
\[\sqrt{-64} = \sqrt{-1 \cdot 64} = \sqrt{-1} \cdot \sqrt{64} = i \cdot 8 = 8i\]
This allows us to represent solutions for equations that otherwise wouldn't have one in real numbers.
For instance, in the given problem, we have \(\sqrt{-64}\). Since the square root of a negative number isn't a real number, we use the imaginary unit \(i\):
\[\sqrt{-64} = \sqrt{-1 \cdot 64} = \sqrt{-1} \cdot \sqrt{64} = i \cdot 8 = 8i\]
This allows us to represent solutions for equations that otherwise wouldn't have one in real numbers.
- Imaginary numbers broaden the scope of quadratic equations.
- They help solve equations where traditional methods fail.
Solving Quadratic Equations
To solve quadratic equations, follow these general steps:
1. **Isolate the Quadratic Term**: Get the quadratic term by itself on one side of the equation.
2. **Take the Square Root**: Apply the square root to both sides, remembering to consider both positive and negative roots.
3. **Simplify**: If the square root includes a negative number, convert it to an imaginary number.
Let's use these steps to solve our equation \(y^2+64=0\):
1. **Isolate the Quadratic Term**:
\
1. **Isolate the Quadratic Term**: Get the quadratic term by itself on one side of the equation.
2. **Take the Square Root**: Apply the square root to both sides, remembering to consider both positive and negative roots.
3. **Simplify**: If the square root includes a negative number, convert it to an imaginary number.
Let's use these steps to solve our equation \(y^2+64=0\):
1. **Isolate the Quadratic Term**:
\
Other exercises in this chapter
Problem 7
Solve the following quadratic equations. \(4 m^{2}=36\)
View solution Problem 9
Solve the following quadratic equations. \(x^{2}+20=0\)
View solution Problem 11
Solve the following quadratic equations. \(\frac{2}{5} a^{2}+3=11\)
View solution Problem 13
Solve the following quadratic equations. \(7 p^{2}+10=26\)
View solution