Problem 10
Question
Solve the equation. $$9^{2 x} \cdot\left(\frac{1}{3}\right)^{x+2}=27 \cdot\left(3^{x}\right)^{-2}$$
Step-by-Step Solution
Verified Answer
The solution is \(x = 1\).
1Step 1: Understand the problem
The given equation is \(9^{2x} \cdot \left(\frac{1}{3}\right)^{x+2} = 27 \cdot \left(3^{x}\right)^{-2}\). Our task is to find the value of \(x\). To make the problem easier, we'll rewrite the terms with the same base.
2Step 2: Rewrite terms with a common base
Notice that 9, 27, and \(\frac{1}{3}\) can be rewritten with base 3.- \(9 = 3^2\) so \(9^{2x} = (3^2)^{2x} = 3^{4x}\)- \(\frac{1}{3} = 3^{-1}\) so \(\left(\frac{1}{3}\right)^{x+2} = (3^{-1})^{x+2} = 3^{-(x+2)}\)- \(27 = 3^3\)- \(\left(3^{x}\right)^{-2} = 3^{-2x}\)After rewriting, we get:\[3^{4x} \cdot 3^{-(x+2)} = 3^3 \cdot 3^{-2x}\]
3Step 3: Simplify using properties of exponents
Use the property of exponents that states \(a^m \cdot a^n = a^{m+n}\). Combine the powers of 3 on the left side:\[3^{4x - (x+2)} = 3^{3 - 2x}\]This simplifies to:\[3^{3x - 2} = 3^{3 - 2x}\]
4Step 4: Equate the exponents
Since the bases are the same, we can equate the exponents:\[3x - 2 = 3 - 2x\]
5Step 5: Solve the equation for x
Rearrange the equation to find \(x\):\[3x + 2x = 3 + 2\]\[5x = 5\]Divide both sides by 5:\[x = 1\]
Key Concepts
Rewriting BasesProperties of ExponentsEquating Exponents
Rewriting Bases
The foundation of solving exponential equations often involves rewriting numbers to have a common base. This is key because it simplifies the equation, allowing direct comparison of exponents. In our exercise, the numbers 9, 27, and \(\frac{1}{3}\) can all be expressed as powers of 3.
- 9 is rewritten as \(3^2\), which becomes \((3^2)^{2x} = 3^{4x}\).
- \(\frac{1}{3}\) is rewritten as \(3^{-1}\), so \((\frac{1}{3})^{x+2} = (3^{-1})^{x+2} = 3^{-(x+2)}\).
- 27 is \(3^3\).
- Finally, \((3^x)^{-2}\) becomes \(3^{-2x}\).
Properties of Exponents
The next logical step in solving the problem is to simplify the expression using the properties of exponents. These properties are mathematical rules that describe how exponents work. They help you manipulate exponential expressions easily. A fundamental property we use is:
- \(a^m \cdot a^n = a^{m+n}\)
- On the left side, \(3^{4x} \cdot 3^{-(x+2)}\) simplifies to \(3^{4x - (x+2)} = 3^{3x - 2}\).
- On the right side, \(3^3 \cdot 3^{-2x}\) simplifies to \(3^{3 - 2x}\).
Equating Exponents
Once the bases are the same, you can equate the exponents because if \(a^m = a^n\), then \(m = n\). This is crucial as it translates an exponential equation into a simple linear equation. In our problem, the equation simplifies to:
- \(3x - 2 = 3 - 2x\)
- Rearranging the terms: \(3x + 2x = 3 + 2\)
- Simplifying it to \(5x = 5\)
- Dividing both sides by 5, which gives us \(x = 1\)
Other exercises in this chapter
Problem 10
Exer. 5-10: Solve for \(t\) using logarithms with base \(a\). $$ L=M a^{t / N}-P $$
View solution Problem 10
Exer. 5-16: Determine whether the function \(f\) is one-to-one. $$ f(x)=\sqrt[3]{x} $$
View solution Problem 11
Write the expression as one logarithm. $$ 2 \log _{a} x+\frac{1}{3} \log _{a}(x-2)-5 \log _{a}(2 x+3) $$
View solution Problem 11
$$ e^{\left(x^{2}\right)}=e^{7 x-12} $$
View solution