Problem 10
Question
Solve each formula for the quantity given. $$ X_{L}=2 \pi f L \text { for } f $$
Step-by-Step Solution
Verified Answer
The frequency \( f \) is given by \( f = \frac{X_{L}}{2\pi L} \).
1Step 1: Understand the Formula
The given formula is the inductive reactance formula, expressed as \( X_{L} = 2\pi f L \). Here, \( X_{L} \) is the inductive reactance, \( f \) is the frequency, and \( L \) is the inductance.
2Step 2: Isolate the Target Variable
Since we need to solve for \( f \), we start by isolating \( f \) in the equation. The given equation is:\[ X_{L} = 2\pi f L \] Divide both sides by \( 2\pi L \) to isolate \( f \):\[ f = \frac{X_{L}}{2\pi L} \]
3Step 3: Simplified Expression
The equation is now solved for \( f \). We have the frequency expressed as:\[ f = \frac{X_{L}}{2\pi L} \].
Key Concepts
Frequency CalculationIsolation of VariablesMathematical Formulas
Frequency Calculation
In the world of electrical engineering, frequency plays a crucial role, particularly when dealing with alternating current (AC) circuits. The frequency denotes how often the current changes direction per second. It is typically measured in hertz (Hz). When calculating frequency in the context of inductive reactance, we lean on the formula for inductive reactance:
The relationship between these variables illustrates how changes in inductive reactance or inductance affect frequency. By manipulating the formula and isolating \( f \), we realize the frequency's dependency on both the inductance and the inductive reactance.
- Inductive reactance
- Frequency
- Inductance
The relationship between these variables illustrates how changes in inductive reactance or inductance affect frequency. By manipulating the formula and isolating \( f \), we realize the frequency's dependency on both the inductance and the inductive reactance.
Isolation of Variables
Isolation of variables is a fundamental mathematical technique used to solve for unknown quantities in equations. In this exercise, we're tasked with isolating the frequency \( f \) from the equation \[ X_{L} = 2\pi f L \].
To isolate \( f \), we need to rearrange the equation to express \( f \) as the subject. A step-by-step method allows us to focus on each component of the equation, bringing clarity to the problem-solving process.
To isolate \( f \), we need to rearrange the equation to express \( f \) as the subject. A step-by-step method allows us to focus on each component of the equation, bringing clarity to the problem-solving process.
- Start by identifying the target variable, \( f \), in the equation.
- Consider the operations applied to \( f \) - it's currently being multiplied by \( 2\pi L \).
- To isolate \( f \), perform the inverse operation, which in this case is dividing both sides by \( 2\pi L \).
Mathematical Formulas
Mathematical formulas serve as the backbone for calculations in physics and engineering. These formulas are like recipes, guiding us through complex concepts with precision and simplicity. The formula we faced, \[ X_{L} = 2\pi f L \], is a representation of the relationship between inductive reactance, frequency, and inductance.
It embodies the principle that as frequency increases, so does the inductive reactance, if inductance stays constant. Mathematical formulas are powerful tools because they:
It embodies the principle that as frequency increases, so does the inductive reactance, if inductance stays constant. Mathematical formulas are powerful tools because they:
- Summarize complex relationships concisely.
- Allow predictions and insights into physical behavior.
- Enable computations across different parameters.
Other exercises in this chapter
Problem 9
Solve each formula for the quantity given. $$ v^{2}=2 g h \text { for } h $$
View solution Problem 10
Find the cross-sectional area of a piston head with a diameter of \(3.25 \mathrm{~cm}\).
View solution Problem 11
Find the area of a right triangle that has legs of \(4.00 \mathrm{~cm}\) and \(6.00 \mathrm{~cm}\).
View solution Problem 11
Solve each formula for the quantity given. $$ P=\frac{W}{t} \text { for } W $$
View solution