Problem 10
Question
Solve each equation or inequality. Check your solutions. $$ \frac{y}{y+1}=\frac{2}{3} $$
Step-by-Step Solution
Verified Answer
The solution is \( y = 2 \).
1Step 1: Set Up the Equation
The original equation given is \( \frac{y}{y+1} = \frac{2}{3} \). We need to solve this equation for \( y \).
2Step 2: Cross-Multiply
To eliminate the fractions, we cross-multiply. This means we multiply the numerator of one fraction by the denominator of the other and set the expressions equal to each other: \( 3y = 2(y+1) \).
3Step 3: Distribute and Simplify
Distribute the 2 on the right side: \( 3y = 2y + 2 \).
4Step 4: Isolate the Variable
Subtract \( 2y \) from both sides to get \( y = 2 \).
5Step 5: Check the Solution
Substitute \( y = 2 \) back into the original equation to verify: \( \frac{2}{2+1} = \frac{2}{3} \rightarrow \frac{2}{3} = \frac{2}{3} \). The solution is correct.
Key Concepts
Cross-MultiplicationVariable IsolationEquation Verification
Cross-Multiplication
To solve equations involving fractions, one effective method is cross-multiplication. This technique eliminates the fractions.When you have an equation in the form \( \frac{a}{b} = \frac{c}{d} \), you perform cross-multiplication by multiplying the numerator of the first fraction by the denominator of the second fraction and vice versa.So, for our example equation \( \frac{y}{y+1} = \frac{2}{3} \), we need to multiply \( y \) by 3 and \( 2 \) by \( y+1 \).
- This gives us the equation \( 3y = 2(y+1) \).
- Cross-multiplication helps clear fractions, making the equation easier to solve.
Variable Isolation
Once you have an equation free of fractions, the next goal is to isolate the variable. This means getting the variable \( y \) by itself on one side of the equation.In our example, after cross-multiplication, we have the equation \( 3y = 2(y+1) \).
- First, distribute the 2 on the right side: \( 2 \times (y+1) = 2y + 2 \).
- This simplifies the equation to \( 3y = 2y + 2 \).
- Next, subtract \( 2y \) from both sides to remove it from the right side, resulting in \( y = 2 \).
Equation Verification
After finding a solution for the variable, it's essential to verify that the solution is correct. This process ensures that your answer satisfies the original equation.For the equation \( \frac{y}{y+1} = \frac{2}{3} \), we determined that \( y = 2 \).
- Substitute \( y = 2 \) back into the original equation.
- This gives us \( \frac{2}{2+1} = \frac{2}{3} \).
- Simplifying the left side results in \( \frac{2}{3} \).
Other exercises in this chapter
Problem 9
Simplify each expression. $$ \frac{6}{d^{2}+4 d+4}+\frac{5}{d+2} $$
View solution Problem 9
Simplify each expression. \(\frac{3 t+6}{7 t-7} \cdot \frac{14 t-14}{5 t+10}\)
View solution Problem 10
Suppose \(y\) varies jointly as \(x\) and \(z .\) Find \(y\) when \(x=2\) and \(z=27\) if \(y=192\) when \(x=8\) and \(z=6 .\)
View solution Problem 10
Simplify each expression. $$ \frac{a}{a^{2}-a-20}+\frac{2}{a+4} $$
View solution