Problem 10
Question
Solve each equation. \(5 x+1=12\)
Step-by-Step Solution
Verified Answer
The solution is \(x = \frac{11}{5}\).
1Step 1: Move the Constant
To solve for the variable \(x\), we must first isolate the terms that contain \(x\). Currently, the equation is \(5x + 1 = 12\). To do this, subtract \(1\) from both sides of the equation:\[5x + 1 - 1 = 12 - 1\]This simplifies to:\[5x = 11\]
2Step 2: Isolate the Variable
Now that we have \(5x = 11\), divide both sides of the equation by \(5\) to solve for \(x\):\[\frac{5x}{5} = \frac{11}{5}\]This simplifies to:\[x = \frac{11}{5}\]
3Step 3: Simplify the Solution
The solution to the equation is currently \(x = \frac{11}{5}\). This fraction cannot be simplified further, so \(x = \frac{11}{5}\) remains our final solution.
Key Concepts
Solving Linear EquationsAlgebraic ManipulationVariable Isolation
Solving Linear Equations
When faced with a linear equation, the ultimate goal is to find the value of the variable that makes the equation true. Linear equations, like the one in this problem, typically take the form of: \(ax + b = c\). In this format, \(a\), \(b\), and \(c\) are constants, and \(x\) is the variable we are trying to solve for.
Solving linear equations involves several steps that help simplify and balance the equation, ensuring that the equality remains when adjusting either side. These steps include:
Solving linear equations involves several steps that help simplify and balance the equation, ensuring that the equality remains when adjusting either side. These steps include:
- Eliminating constants from one side
- Ensuring all variable terms are on one side of the equation
- Solving for the variable by dividing or multiplying as needed
Algebraic Manipulation
Algebraic manipulation is all about re-arranging and simplifying an equation to solve for the unknown. This process involves performing the same arithmetic operation on both sides of an equation to keep it balanced. In our exercise, we start with the equation \(5x + 1 = 12\).
Our first step involves subtracting \(1\) from both sides. This is algebraic manipulation where we ensure the balance of the equation remains intact while simplifying it to bring us one step closer to isolating the variable \(x\). This produces: \[5x = 11\]
Remember, every manipulation aims to maintain equality. Maintaining balance is crucial as imbalance would result in incorrect solutions.
Our first step involves subtracting \(1\) from both sides. This is algebraic manipulation where we ensure the balance of the equation remains intact while simplifying it to bring us one step closer to isolating the variable \(x\). This produces: \[5x = 11\]
Remember, every manipulation aims to maintain equality. Maintaining balance is crucial as imbalance would result in incorrect solutions.
Variable Isolation
Variable isolation means getting our desired variable, here \(x\), by itself on one side of the equation. This is achieved by removing other terms from one side of the equation.
In our example, after simplifying to \(5x = 11\), the next step to isolate \(x\) is dividing both sides of the equation by \(5\). This is direct and straightforward because our goal is to have \(x\) by itself.
As you perform this operation, you get:
In our example, after simplifying to \(5x = 11\), the next step to isolate \(x\) is dividing both sides of the equation by \(5\). This is direct and straightforward because our goal is to have \(x\) by itself.
As you perform this operation, you get:
- Divide each term by the coefficient of \(x\) (which is \(5\))
- The equation becomes: \[x = \frac{11}{5}\]
Other exercises in this chapter
Problem 10
Solve each equation. \(s=2.1+0.6 s\)
View solution Problem 10
Solve each equation. \(\frac{3 a}{7}-1=\frac{a}{3}\)
View solution Problem 11
Solve each inequality and graph the solutions. \(|x+2|>1\)
View solution Problem 11
Solve each of the inequalities and express the solution sets in interval notation. \(\frac{4 x-3}{6}-\frac{2 x-1}{12}
View solution