Problem 10
Question
Sketch the graph of the inequality. $$y^{2}-x<0$$
Step-by-Step Solution
Verified Answer
The graph of the inequality \(y^2 - x < 0\) is the region within the 'V' shape formed by the curves \(y = \sqrt{x}\) and \(y = - \sqrt{x}\). The region does not include the boundary.
1Step 1: Sketch the Boundary
The boundary of the region is given by the equality \(y^2 - x = 0\). Rearrange this equation to \(y = \pm \sqrt{x}\). Now, sketch these two functions \(y = \sqrt{x}\) and \(y = - \sqrt{x}\) on a coordinate plane. This forms a V shape.
2Step 2: Test a point
Choose a point not on the boundary to test which side of the boundary to shade. A good choice is the origin (0,0). Substituting these values into the inequality \(y^2 - x < 0\) gives \(0 - 0 < 0\) which is false. Therefore, do not shade the region that contains the origin.
3Step 3: Shade the Correct Region
Since the region containing the origin is not shaded, the region that is shaded is the one that does not contain the origin, i.e., the region within the 'V' shape formed by the two curves \(y = \sqrt{x}\) and \(y = - \sqrt{x}\).
Other exercises in this chapter
Problem 9
Use back-substitution to solve the system of linear equations. $$\left\\{\begin{aligned} x-y+z &=4 \\ 2 y+z &=-6 \\ z &=-2 \end{aligned}\right.$$
View solution Problem 10
Sketch the region determined by the constraints. Then find the minimum anc maximum values of the objective function and where they occur, subject to the indicat
View solution Problem 10
Use back-substitution to solve the system of linear equations. $$\left\\{\begin{aligned} 4 x-2 y+z &=8 \\\\-y+z &=4 \\ z &=2 \end{aligned}\right.$$
View solution Problem 11
Sketch the graph of the inequality. $$y>-1$$
View solution