Problem 10
Question
Sketch the graph of the given function \(f\). Find the \(y\) -intercept and the horizontal asymptote of the graph. State whether the function is increasing or decreasing. $$ f(x)=9-e^{x} $$
Step-by-Step Solution
Verified Answer
Y-intercept: (0, 8), Horizontal asymptote: \( y = 9 \), Function is decreasing.
1Step 1: Identify the Function Type
The function is in the form of a transformation of the exponential function. The base function is \( e^x \), and this function is shifted and flipped due to transformation rules.
2Step 2: Find the Y-intercept
To find the y-intercept, set \( x = 0 \) in the function \( f(x) = 9 - e^x \). Calculate \( f(0) = 9 - e^0 = 9 - 1 = 8 \). Hence, the y-intercept is \( (0, 8) \).
3Step 3: Determine the Horizontal Asymptote
Exponential functions of the form \( f(x) = a - e^x \) have horizontal asymptotes. As \( x \to \infty \), \( e^x \to \infty \) hence \( f(x) = 9 - e^x \to -\infty \). As \( x \to -\infty \), \( e^x \to 0 \) hence \( f(x) = 9 - 0 = 9 \). Thus, the horizontal asymptote is \( y = 9 \).
4Step 4: Analyze the Function's Behavior (Increasing/Decreasing)
The derivative of \( f(x) \) is \( f'(x) = -e^x \). Since \( e^x \) is always positive for all real \( x \), \( f'(x) \) is always negative. Therefore, \( f(x) = 9 - e^x \) is a decreasing function.
5Step 5: Sketch the Graph
Based on the previous steps, sketch the graph of \( f(x) = 9 - e^x \):- Start at (0, 8) for the y-intercept.- As \( x \to \infty \), the graph goes downwards infinitely due to the decreasing nature of the function and nears -\infty.- As \( x \to -\infty \), the graph approaches the horizontal asymptote \( y = 9 \).
Key Concepts
Horizontal AsymptoteDecreasing FunctionY-intercept
Horizontal Asymptote
When dealing with exponential functions like \( f(x) = 9 - e^x \), understanding horizontal asymptotes is crucial. A horizontal asymptote is a horizontal line that the graph of a function approaches as \( x \) heads towards infinity or negative infinity.
The function \( f(x) = 9 - e^x \) tends towards a stable value, which occurs because the exponential part \( e^x \) changes drastically as \( x \) changes.
For example:
The function \( f(x) = 9 - e^x \) tends towards a stable value, which occurs because the exponential part \( e^x \) changes drastically as \( x \) changes.
For example:
- As \( x \to -\infty \): \( e^x \to 0 \), thus \( f(x) = 9 - 0 = 9 \). Hence, the function approaches a horizontal line at \( y = 9 \) on the left.
- As \( x \to \infty \): \( e^x \to \infty \), thus \( f(x) \to -\infty \). Therefore, there is no horizontal asymptote on the right as \( f(x) \) diminishes indefinitely downwards.
Decreasing Function
Exponential functions can either increase or decrease, and for \( f(x) = 9 - e^x \), the function is decreasing. This means as \( x \) increases, the value of \( f(x) \) decreases.
The key to understanding why this happens lies in the derivative. The derivative of \( f(x) \) is \( f'(x) = -e^x \), which is always negative since \( e^x \) is always positive. A negative derivative indicates function values are getting smaller as \( x \) moves towards larger values:
This behavior confirms that the function decreases without bound as \( x \to \infty \), impacting how its graph looks and behaves.
The key to understanding why this happens lies in the derivative. The derivative of \( f(x) \) is \( f'(x) = -e^x \), which is always negative since \( e^x \) is always positive. A negative derivative indicates function values are getting smaller as \( x \) moves towards larger values:
- When \( x \to 0 \), \( f'(x) = -e^0 = -1 \) (a small but consistent decrease).
- As \( x \to \infty \), \( f'(x) \) becomes more negative, accelerating the decrease of \( f(x) \).
This behavior confirms that the function decreases without bound as \( x \to \infty \), impacting how its graph looks and behaves.
Y-intercept
The y-intercept of a function is where the graph crosses the y-axis, i.e., the value of the function when \( x = 0 \). For the function \( f(x) = 9 - e^x \), let's learn how you find this point.
Simply substitute \( x = 0 \) into the function:
\( f(0) = 9 - e^0 = 9 - 1 = 8 \).
Thus, the y-intercept is the point \((0, 8)\).
This calculation means that the graph will intersect the y-axis at this point.
The y-intercept is essential in giving context to what happens as the graph moves horizontally along the axis.
Simply substitute \( x = 0 \) into the function:
\( f(0) = 9 - e^0 = 9 - 1 = 8 \).
Thus, the y-intercept is the point \((0, 8)\).
This calculation means that the graph will intersect the y-axis at this point.
- It's a useful reference point for sketching the graph since it shows the starting height when \( x \) is zero.
- This point reflects that at zero input (where x is zero), the output (y-value) is 8.
The y-intercept is essential in giving context to what happens as the graph moves horizontally along the axis.
Other exercises in this chapter
Problem 9
In Problems \(7-12\), rewrite the given logarithmic expression as an equivalent exponential expression. $$ \log _{\sqrt{3}} 81=8 $$
View solution Problem 10
Solve the given exponential equation. $$ \frac{1}{4}\left(10^{-2 x}\right)=25\left(10^{x}\right) $$
View solution Problem 10
In Problems \(7-12\), rewrite the given logarithmic expression as an equivalent exponential expression. $$ \log _{16} 2=\frac{1}{4} $$
View solution Problem 11
Solve the given exponential equation. $$ 5-10^{2 x}=0 $$
View solution