Problem 10
Question
simplify the expression. \(\frac{x^{3}+y^{3}}{x^{2}-x y+y^{2}}\)
Step-by-Step Solution
Verified Answer
The simplified expression is \(x + y\).
1Step 1: Factorizing the numerator expression
In the numerator, we have a sum of cubes. We can use the sum of cubes formula: \(a^3 + b^3 = (a + b)(a^2 - ab + b^2)\). In this case, the expression is \(x^3 + y^3\), so \(a\) is \(x\) and \(b\) is \(y\).
Using the sum of cubes formula, we have:
\(x^3 + y^3 = (x + y)(x^2 - xy + y^2)\).
2Step 2: Cancel out common terms from numerator and denominator
Now, we have the expression as follows:
\(\frac{(x + y)(x^2 - xy + y^2)}{x^2 - xy + y^2}\)
We can see that there is one common factor between the numerator and the denominator, which is \((x^2 - xy + y^2)\).
Canceling out the common factor, we get:
\(\frac{(x + y)(x^2 - xy + y^2)}{x^2 - xy + y^2} = x + y\).
3Step 3: Final simplified expression
The simplified expression is:
\(x + y\).
Other exercises in this chapter
Problem 10
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