Problem 10
Question
Simplify each trigonometric expression. $$ 1-\cos ^{2} \theta $$
Step-by-Step Solution
Verified Answer
The simplified form of the trigonometric expression \(1 - \cos^2(θ)\) is \(\sin^2(θ)\).
1Step 1: Recognize the Pythagorean Identity
Start by recognizing the Pythagorean identity. In trigonometry, the fundamental Pythagorean identity is \(\sin^2(θ) + \cos^2(θ) = 1\). It means that the square of the sine of an angle plus the square of the cosine of an angle is always equal to 1.
2Step 2: Substitute the expression with Pythagorean Identity
Now, it's time to substitute the expression \(1 - \cos^2(θ)\) with the Pythagorean identity. If you subtract \(\cos^2(θ)\) from both sides of the identity, it would give you: \(1 - \cos^2(θ) = \sin^2(θ)\).
Key Concepts
Trigonometric IdentitiesSimplify Trigonometric ExpressionsSine and Cosine Relationship
Trigonometric Identities
Trigonometric identities are equations involving trigonometric functions that hold true for all values of the involved variables. These identities are essential in mathematics as they help to simplify complex trigonometric expressions. One of the most fundamental identities is the Pythagorean identity:
- \(\sin^2(θ) + \cos^2(θ) = 1\)
Simplify Trigonometric Expressions
Simplifying trigonometric expressions can make complex mathematical problems easier to understand and solve. When given a trigonometric expression such as \(1 - \cos^2(θ)\), our goal is to express it in its simplest form using known identities.The Pythagorean identity tells us that \(\sin^2(θ) + \cos^2(θ) = 1\). By rearranging this, we see that
- \(1 - \cos^2(θ) = \sin^2(θ)\) is an equivalent form.
Sine and Cosine Relationship
The relationship between sine and cosine is a core aspect of trigonometry. These two functions are related not only through the Pythagorean identity
- \(\sin^2(θ) + \cos^2(θ) = 1\)
Other exercises in this chapter
Problem 10
Solve each trigonometric equation for \(0 \leq \theta
View solution Problem 10
Find each angle measure to the nearest tenth of a degree. \(\tan ^{-1} 0.3333\)
View solution Problem 11
Use a half-angle identity to find the exact value of each expression. $$ \cos 15^{\circ} $$
View solution Problem 11
In \(\triangle A B C, a=20 \mathrm{m}, b=14 \mathrm{m},\) and \(c=16 \mathrm{m} .\) Find \(m \angle A\)
View solution