Problem 10
Question
Show that \(G L(2, Q)\) is non-Abelian.
Step-by-Step Solution
Verified Answer
GL(2, Q) is non-Abelian because some matrices do not commute.
1Step 1: Identify the Groups Involved
First, we identify that we are dealing with the general linear group of 2x2 matrices, denoted as \(GL(2, \mathbb{Q})\), where \(\mathbb{Q}\) represents the set of rational numbers. This group consists of all 2x2 invertible matrices with rational entries.
2Step 2: Define Properties of an Abelian Group
Recall that for a group to be Abelian, or commutative, for every pair of elements \(a\) and \(b\) in the group, the equation \(ab = ba\) should hold. If we find a pair of elements in our group that do not commute, this will prove that the group is non-Abelian.
3Step 3: Choose Specific Matrices
Next, we select two specific matrices from \(GL(2, \mathbb{Q})\) to serve as our test case. Let matrix \(A = \begin{pmatrix} 0 & 1 \ 1 & 0 \end{pmatrix}\) and matrix \(B = \begin{pmatrix} 1 & 1 \ 0 & 1 \end{pmatrix}\). Both matrices are invertible, hence they belong to \(GL(2, \mathbb{Q})\).
4Step 4: Compute the Matrix Product AB
Calculate the product of matrices \(A\) and \(B\):\[AB = \begin{pmatrix} 0 & 1 \ 1 & 0 \end{pmatrix} \begin{pmatrix} 1 & 1 \ 0 & 1 \end{pmatrix} = \begin{pmatrix} 0 \cdot 1 + 1 \cdot 0 & 0 \cdot 1 + 1 \cdot 1 \ 1 \cdot 1 + 0 \cdot 0 & 1 \cdot 1 + 0 \cdot 1 \end{pmatrix} = \begin{pmatrix} 0 & 1 \ 1 & 1 \end{pmatrix}\]
5Step 5: Compute the Matrix Product BA
Now calculate the product of matrices \(B\) and \(A\):\[BA = \begin{pmatrix} 1 & 1 \ 0 & 1 \end{pmatrix} \begin{pmatrix} 0 & 1 \ 1 & 0 \end{pmatrix} = \begin{pmatrix} 1 \cdot 0 + 1 \cdot 1 & 1 \cdot 1 + 1 \cdot 0 \ 0 \cdot 0 + 1 \cdot 1 & 0 \cdot 1 + 1 \cdot 0 \end{pmatrix} = \begin{pmatrix} 1 & 1 \ 1 & 0 \end{pmatrix}\]
6Step 6: Compare Results
Observe that\[AB = \begin{pmatrix} 0 & 1 \ 1 & 1 \end{pmatrix} \quad \text{and} \quad BA = \begin{pmatrix} 1 & 1 \ 1 & 0 \end{pmatrix}\]These two matrices are not equal, meaning \(AB eq BA\).
7Step 7: Conclude Non-Abelian Nature
Since we have found a pair of matrices \(A\) and \(B\) for which \(AB eq BA\) in \(GL(2, \mathbb{Q})\), it shows that this group is non-Abelian.
Key Concepts
General Linear GroupMatrix MultiplicationInvertible MatricesRational Numbers
General Linear Group
The General Linear Group, denoted as \(GL(n, F)\), is a key concept in linear algebra, representing the set of all \(n \times n\) invertible matrices with entries from a field \(F\). Here, \(GL(2, \mathbb{Q})\) refers specifically to the group of all invertible \(2 \times 2\) matrices where the elements are rational numbers. This group is important because it encapsulates the idea of all possible transformations in a given space that can be reversed. Every matrix in this group has an inverse, which means it can be "undone."
- **Invertibility**: Every element has an inverse.
- **Closure**: The product of two invertible matrices is another invertible matrix.
- **Associativity**: Matrix multiplication is associative.
- **Identity Element**: The identity matrix serves as the neutral element.
Matrix Multiplication
Matrix multiplication is a fundamental operation used in many areas of mathematics and engineering. It involves taking two matrices and producing a third matrix by combining rows and columns from the two input matrices.To multiply a \(2 \times 2\) matrix \(A\) with another \(2 \times 2\) matrix \(B\), follow these steps:1. Multiply each element of the rows of \(A\) by the corresponding element of the columns of \(B\).2. Sum these products to get the elements of the resulting matrix.For example:If \(A = \begin{pmatrix} a & b \ c & d \end{pmatrix}\) and \(B = \begin{pmatrix} e & f \ g & h \end{pmatrix}\), then:\[AB = \begin{pmatrix} ae + bg & af + bh \ ce + dg & cf + dh \end{pmatrix}\]This operation is not commutative, meaning in general \(AB eq BA\), which is crucial in determining the properties of matrices within the context of a group like \(GL(2, \mathbb{Q})\).
Invertible Matrices
An invertible matrix, also known as a non-singular or non-degenerate matrix, is a square matrix that possesses a unique matrix inverse. Only invertible matrices belong to the general linear group.Some key characteristics include:
- **Determinant is Non-Zero**: For a matrix to be invertible, its determinant must be non-zero.
- **Existence of an Inverse**: Given a matrix \(A\), there exists another matrix \(A^{-1}\) such that \(AA^{-1} = A^{-1}A = I\), where \(I\) is the identity matrix.
Rational Numbers
Rational numbers, represented as \(\mathbb{Q}\), are numbers that can be expressed as the quotient or fraction of two integers, where the denominator is not zero. Key characteristics:
- An example is \(\frac{p}{q}\), where \(p\) and \(q\) are integers, and \(q eq 0\).
- Rational numbers include integers, fractions, and finite decimals.
Other exercises in this chapter
Problem 10
Let $$ \phi=\left(\begin{array}{llllllll} 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 \\ 3 & 8 & 4 & 1 & 6 & 7 & 2 & 5 \end{array}\right), \quad \tau=\left(\begin{array}{llll
View solution Problem 10
Find the order of the indicated element in the indicated group. $$ \cos (2 \pi / 7)+i \sin (2 \pi / 7) \in \mathrm{C}^{*} $$
View solution Problem 11
In Exercises 11 through 13 express each permutation as a product of disjoint cycles, and then calculate its order. $$ \phi=\left(\begin{array}{llllllllll} 1 & 2
View solution Problem 11
In Exercises 11 through 19 give at least two examples of a nontrivial proper subgroup of the indicated group. $$ \mathbb{Z} $$
View solution