Problem 10
Question
Show that for any \(a \in \mathbb{R},-|a| \leq a \leq|a|\).
Step-by-Step Solution
Verified Answer
The inequality \(-|a| \leq a \leq |a|\) holds true for any real number \(a\).
1Step 1: Understanding the Absolute Value
The absolute value of a real number \(a\), denoted \(|a|\), is defined as the non-negative value of \(a\). Essentially, \(|a|\) is equal to \(a\) if \(a\) is positive or zero, and \(-a\) if \(a\) is negative.
2Step 2: Considering Case 1: When \(a\) is Non-Negative
For some \(a \geq 0\), we know \(|a| = a\). Thus, \(-|a| = -a\). Consequently, the inequality simplifies to \(-a \leq a \leq a\), which holds true because \(-a\) is non-positive.
3Step 3: Considering Case 2: When \(a\) is Negative
For some \(a < 0\), we know \(|a| = -a\). Therefore, \(-|a| = -(-a) = a\). The inequality becomes \(a \leq a \leq -a\), which is clearly satisfied because the first part \(a \leq a\) holds, and as \(a\) is negative, \(a < -a\), fulfilling \(a \leq -a\).
4Step 4: Combining Both Cases
Both conditions prove that in either scenario (whether \(a\) is non-negative or negative), the inequality \(-|a| \leq a \leq |a|\) holds true. We conclude that the statement is valid for any \(a \, \in \, \mathbb{R}\).
Key Concepts
Absolute ValueInequalities in MathematicsReal Numbers
Absolute Value
The concept of absolute value is central to understanding inequalities in mathematics, especially when dealing with real numbers. The absolute value of a real number \( a \), denoted as \( |a| \), represents the distance of \( a \) from zero on the real number line. This distance is always non-negative.
- When \( a \) is positive or zero, the absolute value of \( a \) is simply \( a \) itself, i.e., \( |a| = a \).
- If \( a \) is negative, the absolute value becomes the negation of \( a \), which turns it into a positive quantity: \( |a| = -a \).
Inequalities in Mathematics
Inequalities provide a way to express the size or order relations between numbers. They state that one value is greater or lesser, or at times equal to another. In mathematics, common symbols used are \(<, \leq, >, \geq\). An inequality is what connects these values within a certain constraint, often graphically represented on a number line.
- A basic inequality form we encounter here with absolute values is that \(-|a| \leq a \leq |a|\).
- This statement essentially says that for any real number \( a \), its absolute value serves as a boundary, meaning \( a \) cannot be greater than or less than its own absolute value.
Real Numbers
Real numbers \( \mathbb{R} \) encompass a vast set that includes all rational and irrational numbers. This set forms a continuous line, often referred to as the real number line. Each point on this line correspondingly represents a real number, and this continuity is what allows for a comprehensive examination of properties like absolute value and inequalities. Real numbers can be categorized as:
- Rational numbers: Numbers that can be expressed as a fraction, \( \frac{p}{q} \), where \( p \) and \( q \) are integers and \( q eq 0 \). Examples include 1/2, 3, -4.
- Irrational numbers: Numbers that cannot be written as a simple fraction, whose decimal expansions are non-repeating and non-terminating. Examples include \( \sqrt{2} \), \( \pi \), and \( e \).
Other exercises in this chapter
Problem 9
Show that if \(a, b \in \mathbb{R}\) with \(a
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Show that the supremum of a set \(A \subset \mathbb{Q},\) if it exists, is unique, and thus justify the use of the definite article in the previous definition.
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Show that there does not exist a rational number \(s\) with the property that \(s^{2}=3\).
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Show that if \(A \subset \mathbb{R}\) is nonempty and has a lower bound, then inf \(A\) exists. (Hint: You may wish to first show that inf \(A=-\sup (-A)\), whe
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