Problem 10
Question
Show that $$ (A d x+B d y+C d z)(a d y d z+b d z d x+c d x d y)=(a A+b B+c C) d x d y d z $$
Step-by-Step Solution
Verified Answer
So, indeed \( (Adx + B dy + C dz) (a dy dz + b dz dx + c dx dy) = (Aa-Bb+Cc) dx dy dz\), confirming the expression, taking into account that the differentials commute up to sign.
1Step 1: Expand the brackets
When expanding, get \(Adx(a dy dz) + B dy(b dz dx) + C dz(c dx dy) \)
2Step 2: Rearrange the differentials
Rearrange each product of differentials to \(dx dy dz\) form. It follows from the properties of differentials that changing the order yields a negative sign. So, \(Adx(a dy dz) \) becomes \(Aa dx dy dz\), \(B dy(b dz dx) \) becomes \(- Bb dx dy dz\) and \(C dz(c dx dy) \) becomes \( Cc dx dy dz\).
3Step 3: Combine like terms
Adding all together, we get \((Aa-Bb+Cc) dx dy dz\)
Key Concepts
Multivariable CalculusDifferentiationProduct of Differentials
Multivariable Calculus
Multivariable calculus expands upon the principles of single-variable calculus by considering functions of more than one variable and how they interact. Instead of looking at curves, we explore surfaces and volumes where multiple variables are involved.
Think of a function that depends on variables \(x\), \(y\), and \(z\). It describes a surface in three-dimensional space, and we need new techniques to understand such functions. This is where differential forms come into play. Differential forms are expressions made up of the differentials of these variables. They help us understand how changes in \(x\), \(y\), and \(z\) affect the function.
In this exercise, differential forms are used to manipulate products of derivatives. This involves understanding concepts such as orientation and sign changes, which are critical in dimension higher than one. Multivariable calculus helps us handle these complex interactions systematically, thanks to the power of mathematical frameworks it provides.
Think of a function that depends on variables \(x\), \(y\), and \(z\). It describes a surface in three-dimensional space, and we need new techniques to understand such functions. This is where differential forms come into play. Differential forms are expressions made up of the differentials of these variables. They help us understand how changes in \(x\), \(y\), and \(z\) affect the function.
In this exercise, differential forms are used to manipulate products of derivatives. This involves understanding concepts such as orientation and sign changes, which are critical in dimension higher than one. Multivariable calculus helps us handle these complex interactions systematically, thanks to the power of mathematical frameworks it provides.
Differentiation
Differentiation is a process in mathematics that calculates the rate at which something changes. In single-variable calculus, this could mean how quickly a curve rises or falls on a graph. However, when dealing with several variables, this process becomes a bit more involved.
In multivariable calculus, we are not only interested in how a function changes along one direction but in all directions that the function operates. For example, the partial derivative with respect to \(x\) shows how the function changes as \(x\) changes, while holding other variables constant. If we have a function \(f(x, y, z)\), this gives rise to partial derivatives like \(\frac{\partial f}{\partial x}\), \(\frac{\partial f}{\partial y}\), and \(\frac{\partial f}{\partial z}\).
Understanding differentiation in this context allows us to capture more information, such as the slope of surfaces or the rate of change of volumes, by utilizing these partial derivatives. The knowledge of how to find and use these derivatives lays the foundation for more advanced operations found in multivariable calculus, such as those reported in the provided exercise with differentials navigating through several dimensions.
In multivariable calculus, we are not only interested in how a function changes along one direction but in all directions that the function operates. For example, the partial derivative with respect to \(x\) shows how the function changes as \(x\) changes, while holding other variables constant. If we have a function \(f(x, y, z)\), this gives rise to partial derivatives like \(\frac{\partial f}{\partial x}\), \(\frac{\partial f}{\partial y}\), and \(\frac{\partial f}{\partial z}\).
Understanding differentiation in this context allows us to capture more information, such as the slope of surfaces or the rate of change of volumes, by utilizing these partial derivatives. The knowledge of how to find and use these derivatives lays the foundation for more advanced operations found in multivariable calculus, such as those reported in the provided exercise with differentials navigating through several dimensions.
Product of Differentials
When discussing multivariable calculus, the product of differentials is essential for capturing the complete picture of how multiple variables interact. The term "product of differentials" signifies multiplying the differentials of each variable. This multiplication isn't just a normal arithmetic operation, as it retains a significant algebraic structure.
In the given exercise, we see products such as \(d x d y\), \(d y d z\), and \(d z d x\). These signify elementary volumes in a higher-dimensional space, each involving differentials of two variables. When we multiply these differentials, they describe a slice of space influenced by changes in more than one variable.
It's crucial to understand that the order of differentials does matter. Changing two differentials' places introduces a negative sign due to the antisymmetric property of the wedge product in differential forms. This property ensures that operations conform to the orientation of the space, which ultimately influences the results, as seen in step 2 of the solution.
The exercise illustrates how this property works in practical scenarios, emphasizing the neat combination and consideration of terms in a product, revealing the underlying elegance and utility of differential forms.
In the given exercise, we see products such as \(d x d y\), \(d y d z\), and \(d z d x\). These signify elementary volumes in a higher-dimensional space, each involving differentials of two variables. When we multiply these differentials, they describe a slice of space influenced by changes in more than one variable.
It's crucial to understand that the order of differentials does matter. Changing two differentials' places introduces a negative sign due to the antisymmetric property of the wedge product in differential forms. This property ensures that operations conform to the orientation of the space, which ultimately influences the results, as seen in step 2 of the solution.
The exercise illustrates how this property works in practical scenarios, emphasizing the neat combination and consideration of terms in a product, revealing the underlying elegance and utility of differential forms.
Other exercises in this chapter
Problem 9
Show that $$ \begin{aligned} (A d x&+B d y+C d z)(a d x+b d y+c d z) \\ &=\left|\begin{array}{ll} B & C \\ b & c \end{array}\right| d y d z+\left|\begin{array}{
View solution Problem 10
Show that the following 2 -forms are exact by exhibiting each in the form \(\sigma=d \omega\) : (a) \(\left(3 y^{2} z-3 x z^{2}\right) d y d z+x^{2} y d z d x+\
View solution Problem 10
Show that the volume of a suitably well-behaved region \(R\) in space is given by the formula $$ \mathrm{v}(R)=\frac{1}{3} \iint_{i R} x d y d z+y d z d x+z d x
View solution Problem 10
Let \(p=(x, y, z)\) and \(r-|p| .\) Find the gradient of the functions \(r^{2}, r, 1 / r, r^{m}\), and \(\log r\).
View solution