Problem 10
Question
Rewrite the given power series so that its general term involves \(x^{k}\). $$ \sum_{n=3}^{\infty}(2 n-1) c_{n} x^{n-3} $$
Step-by-Step Solution
Verified Answer
\(\sum_{k=0}^{\infty} (2k + 5) c_{k+3} x^k\).
1Step 1: Identify the General Term
The given power series is \( \sum_{n=3}^{\infty} (2n-1) c_n x^{n-3} \). Let's identify the general term, which is \((2n-1) c_n x^{n-3}\). We are asked to rewrite it in terms of \(x^k\).
2Step 2: Re-index the Series
To rewrite in terms of \(x^k\), we set \(k = n - 3\). This implies that \(n = k + 3\). As \(n\) starts at 3, substituting this into the expression gives \(k = 0\).
3Step 3: Substitute and Simplify
Replace \(n\) with \(k+3\) in the general term: \((2(k+3)-1) c_{k+3} x^{k}\). Simplifying this expression gives \((2k + 6 - 1) c_{k+3} x^k = (2k + 5)c_{k+3}x^k\).
4Step 4: Rewrite the Series
Substitute the re-indexed term back into the series, starting from \(k = 0\):\[\sum_{k=0}^{\infty} (2k + 5) c_{k+3} x^k\] This is the power series rewritten in terms of \(x^k\).
Key Concepts
Re-indexing SeriesGeneral Term IdentificationMathematical Series Simplification
Re-indexing Series
Re-indexing a series is a crucial technique used when you want to change the variables in a series to make calculations or interpretations easier.
In the given exercise, the series is initially in the form:
In other words:
In the given exercise, the series is initially in the form:
- \( \sum_{n=3}^{\infty} (2n-1) c_n x^{n-3} \)
In other words:
- Let \(k = n-3\), giving: \(n = k + 3\)
- If \(n\) starts from 3, then \(k\) must start from 0
General Term Identification
Identifying the general term of a series is like finding the building blocks of a series. Each series has a specific pattern that repeats for every term, and your goal is to find this pattern.
The original series in our case:
By recognizing these coefficients, we know what manipulates each term's power of \(x\) and what multiplies the part involving \(c_n\).
This makes it possible to re-structure or transform the series effectively.
The original series in our case:
- \((2n-1) c_n x^{n-3}\)
By recognizing these coefficients, we know what manipulates each term's power of \(x\) and what multiplies the part involving \(c_n\).
This makes it possible to re-structure or transform the series effectively.
- For the rewritten series, the new general term is: \((2k + 5) c_{k+3} x^k\)
- This is obtained by substituting \(n\) with \(k + 3\) and simplifying the expression
Mathematical Series Simplification
Simplifying a mathematical series primarily involves reducing complexity to make further calculations more straightforward.
After re-indexing and identifying the general term, the next step is to substitute and simplify the expressions within to obtain a cleaner, more understandable form of the series.
After re-indexing and identifying the general term, the next step is to substitute and simplify the expressions within to obtain a cleaner, more understandable form of the series.
- Insert \(n = k + 3\) into the identified general term \((2n-1) c_n x^{n-3}\)
- This substitution yields: \((2(k+3)-1) c_{k+3} x^{k}\)
- Upon simplifying, it results to \((2k+5)c_{k+3}x^k\)
- Thus, the series now reads: \(\sum_{k=0}^{\infty} (2k + 5) c_{k+3} x^k\)
Other exercises in this chapter
Problem 10
In Problems 9 and 10 , rewrite the given power series so that its general term involves \(x^{k}\) $$ \sum_{n=3}^{\infty}(2 n-1) c_{n} x^{n-3} $$
View solution Problem 10
Use an appropriate infinite series method about \(x=0\) to find two solutions of the given differential equation. $$ y^{\prime \prime}-x y^{\prime}-y=0 $$
View solution Problem 11
Put the given differential equation into the form (3) for each regular singular point of the equation. Identify the functions \(p(x)\) and \(q(x)\). $$ \left(x^
View solution Problem 11
In Problems, use the indicated change of variable to find the general solution of the given differential equation on the interval \((0, \infty)\). $$ x^{2} y^{\
View solution