Problem 10
Question
Prove each directly. The product of any two odd integers is odd.
Step-by-Step Solution
Verified Answer
The product of two odd integers, \(a = 2k_1 + 1\) and \(b = 2k_2 + 1\), can be computed as \(c = a \cdot b = (2k_1 + 1)(2k_2 + 1)\). Expanding and factoring out 2, we get \(c = 2(2k_1k_2 + k_1 + k_2) + 1\), which is also in the form of an odd integer \(2m + 1\) with \(m = 2k_1k_2 + k_1 + k_2\). Therefore, the product of any two odd integers is odd.
1Step 1: Define odd integers
Let's represent two odd integers as \(a = 2k_1 + 1\) and \(b = 2k_2 + 1\), where \(k_1\) and \(k_2\) are integers. It is important to note that both the odd integers follow the definition \(2k + 1\).
2Step 2: Compute the product of the odd integers
Next, we need to calculate the product of these two odd integers, which can be represented as \(c = a \cdot b\). Substituting the expressions for \(a\) and \(b\) from Step 1, we get:
\(c = (2k_1 + 1)(2k_2 + 1)\)
3Step 3: Expand the expression for the product
In order to verify whether the product of these two odd integers is odd, we need to expand the expression for \(c\):
\[c = (2k_1 + 1)(2k_2 + 1) = 4k_1k_2 + 2k_1 + 2k_2 + 1\]
4Step 4: Factor out 2 from the expression
Now, we will factor out 2 from the terms with \(k_1\) and \(k_2\):
\[c = 4k_1k_2 + 2(k_1) + 2(k_2) + 1 = 2(2k_1k_2 + k_1 + k_2) + 1\]
5Step 5: Confirm the product is odd
We can now see that the expression for \(c\) fits the definition of an odd integer, which is in the form \(2m + 1\), where \(m = 2k_1k_2 + k_1 + k_2\) is an integer.
Thus, we have proved that the product of any two odd integers is odd.
Key Concepts
Odd IntegersDirect ProofInteger PropertiesAlgebraic Expressions
Odd Integers
Odd integers are numbers that cannot be evenly divided by 2. They are numbers like 1, 3, 5, 7, and so forth. These numbers leave a remainder of 1 when divided by 2. You can represent any odd integer with the formula:
- \(a = 2k + 1\)
Direct Proof
A direct proof is a method of proving mathematical statements. It involves straightforward steps that solve or derive a mathematical truth from given premises. In the proof presented here, the goal is to show that the product of two odd integers is also odd.
To execute a direct proof:
- Start with known information or premises.
- Employ logical steps to arrive at the conclusion.
Integer Properties
Integers are a key concept in mathematics. They include whole numbers and their negatives, like -3, -2, -1, 0, 1, 2, 3. Two important properties of integers are evenness and oddness.
- Even integers can be divided by 2 with no remainder.
- Odd integers have a remainder of 1 when divided by 2.
Algebraic Expressions
Algebraic expressions allow us to generalize mathematical concepts. They use variables like \(k_1\) and \(k_2\) and constants to express arithmetic relationships. In our proof, algebraic expressions helped demonstrate that a product of odd integers results in another odd integer. Here's how it went:
- The odd integers were represented as \(a = 2k_1 + 1\) and \(b = 2k_2 + 1\).
- The product \(c = (2k_1 + 1)(2k_2 + 1)\) was expanded and simplified.
- The expression \(c = 2(2k_1k_2 + k_1 + k_2) + 1\) emerged.
Other exercises in this chapter
Problem 9
Prove each directly. The square of an odd integer is odd.
View solution Problem 10
If Peter is married, he is happy. If he is happy, then he does not read the computer magazine. He does read the computer magazine.
View solution Problem 10
Prove each directly. The product of any two odd integers is odd.
View solution Problem 11
Verify each, where \(f\) denotes a contradiction. (See Table \(1.14 . )\) $$ p \wedge(q \wedge r)=(p \wedge q) \wedge r $$
View solution