Problem 10
Question
On May 9,2007, CBS Evening News had a \(4.3\) point rating. (Ratings measure the number of viewers.) News executives estimated that a \(0.1\) drop in the ratings for the CBS Evening News corresponds to a \(\$ 5.5\) million drop in revenue. \({ }^{9}\) Express this information as a derivative. Specify the function, the variables, the units, and the point at which the derivative is evaluated.
Step-by-Step Solution
Verified Answer
\(\frac{dR}{dN} = -55\), evaluated at \(N(t) = 4.3\) with units millions of dollars per rating point.
1Step 1: Identify the Variables and Function
First, we need to define our variables. Let \( R(t) \) represent the revenue in millions of dollars and \( N(t) \) represent the ratings score of the news. The problem describes how changes in the ratings affect the revenue, suggesting a rate of change relationship or derivative between these two variables.
2Step 2: Explain the Given Relationship
According to the problem, a \(0.1\) point drop in ratings \(N(t)\) results in a \(5.5\) million dollars decrease in revenue \(R(t)\). This can be interpreted as a rate of change \(\frac{dR}{dN}\), which is the derivative of revenue with respect to the ratings score.
3Step 3: Formulate the Derivative
The relationship implies \(\frac{dR}{dN} = \frac{-5.5}{0.1}\). This simplifies to \(\frac{dR}{dN} = -55\). Thus, the derivative \(\frac{dR}{dN}\) represents the rate at which revenue changes with respect to changes in the ratings score.
4Step 4: Identify Units and Evaluation Point
The derivative \(\frac{dR}{dN} = -55\) has units of millions of dollars per rating point. Given the initial ratings of \(4.3\), this is the point at which the derivative is described. So, we evaluate this derivative at \(N(t) = 4.3\).
Key Concepts
Rate of ChangeRatings and Revenue RelationshipUnits of Measurement in Calculus
Rate of Change
In calculus, the concept of the rate of change is essential for understanding how one quantity varies with respect to another. In the context of the given problem, we are looking at how revenue, a function denoted as \( R(t) \), changes with the number of viewers, represented by the rating \( N(t) \). The rate of change can be seen as the derivative, \( \frac{dR}{dN} \), which informs us how a small change in ratings affects the revenue. To make sense of what a rate of change means:
- Think of it as how swiftly or slowly something is changing over time.
- It gives you insight into the nature of relationships between variables.
Ratings and Revenue Relationship
The relationship between ratings and revenue in this exercise showcases a direct correlation between the viewership and financial success of a media program. Given it is a linear relationship, calculus allows us to break it down using the derivative. As provided, a 0.1 point drop in ratings results in a \(\\)5.5$ million loss, translating to the derivative \( \frac{dR}{dN} = -55 \). Here's how it breaks down:
- Ratings \( N(t) \) decline, revenue \( R(t) \) tends to drop correspondingly.
- This specific calculation shows financial repercussions tied to viewership metrics.
- The negativity indicates loss in revenue with each decrease in ratings, suggesting how sensitive revenue is to changes in ratings.
Units of Measurement in Calculus
Units of measurement in calculus are critical for understanding the real-world implications of mathematical solutions. In this example:The derivative calculated, \( \frac{dR}{dN} = -55 \), carries with it units reflecting millions of dollars per rating point. Understanding the units:
- It indicates how much the revenue changes with a one-point change in ratings.
- The negative sign shows a decrease of \(\\)55$ million for each point dropped in ratings.
- Units ensure clarity on what precisely is changing and how it affects other variables.
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