Problem 10
Question
Negation of "'Manu is in class X or Anu is in class XII"is (A) Manu is not in class \(\mathrm{X}\) but Anu is in class XII. (B) Manu is not is class X but Anu is not in class XII. (C) Either Manu is not in class \(\mathrm{X}\) or Anu is not is class XII. (D) None of these
Step-by-Step Solution
Verified Answer
Option B: Manu is not in class X but Anu is not in class XII.
1Step 1: Understand the Original Statement
The original statement is "Manu is in class X or Anu is in class XII." In logical terms, this is represented as \( P \lor Q \), where \( P \) is "Manu is in class X" and \( Q \) is "Anu is in class XII."
2Step 2: Apply De Morgan's Laws to Negate the Statement
According to De Morgan's laws, the negation of \( P \lor Q \) is \( eg P \land eg Q \). So, the negation of the statement is "Manu is not in class X and Anu is not in class XII."
3Step 3: Match the Negated Statement with the Options
The negated statement "Manu is not in class X and Anu is not in class XII" corresponds to option B: "Manu is not in class X but Anu is not in class XII."
Key Concepts
De Morgan's LawsNegation in LogicLogical Statements
De Morgan's Laws
De Morgan's Laws are fundamental rules in logic that describe the relationships between conjunctions (AND) and disjunctions (OR) when they are negated. These laws are named after the mathematician Augustus De Morgan. The laws assist in transforming logical expressions and become especially vital when dealing with complex logical statements. Consider two logical statements: \( P \) and \( Q \).
- The first De Morgan's Law states that the negation of a conjunction \( eg (P \land Q) \) is equivalent to the disjunction of the negations \( eg P \lor eg Q \). This means if it is not true that both \( P \) and \( Q \) are true, then either \( P \) is false, or \( Q \) is false (or both).
- The second De Morgan's Law asserts that the negation of a disjunction \( eg (P \lor Q) \) results in the conjunction of the negations \( eg P \land eg Q \). Hence, if it is not the case that at least one of \( P \) or \( Q \) is true, both \( P \) must be false and \( Q \) must be false.
Negation in Logic
In logic, negation is a fundamental operation that inverts the truth value of a statement. If a proposition \( P \) is true, then its negation, written as \( eg P \), is false, and vice versa. Negation changes an affirmation into a denial.
- The negation of a simple statement like "The sky is blue" becomes "The sky is not blue." In Boolean logic, if the proposition is true (\( 1 \)), its negation becomes false (\( 0 \)), and if it's false (\( 0 \)), the negation is true (\( 1 \)).
- Negation plays a significant role in constructing truth tables, which are a cornerstone of understanding complex logical expressions.
Logical Statements
Logical statements are sentences that can be either true or false. They form the basis of logical reasoning and are also used in computer science, mathematics, and philosophy to construct arguments and proofs.
- Each logical statement is usually denoted by a propositional variable, like \( P \) or \( Q \), to simplify expressions and calculations.
- Logical connectives are used to combine multiple statements. These include conjunction (AND, \( \land \)), disjunction (OR, \( \lor \)), implication (IF...THEN, \( \rightarrow \)), and equivalence (IF AND ONLY IF, \( \leftrightarrow \)).
- Understanding of logical statements allows us to evaluate real-world situations and perform logical deduction.
Other exercises in this chapter
Problem 8
Negation of \(" 2+3=5\) and \(8
View solution Problem 9
Negation of the conditional: "If it rains, I shall go to school" is (A) It rains and I shall go to school. (B) It rain and I shall not go to school. (C) It does
View solution Problem 11
Truth value of the statement "if \(p\) then \(q\) " is false when (A) \(p\) is true, \(q\) is true (B) \(p\) is true, \(q\) is false (C) \(p\) is false, \(q\) i
View solution Problem 12
Truth value of the statement " \(p\) or \(q\) " is false, when (A) \(p\) is true, \(q\) is false (B) \(p\) is false, \(q\) is true (C) \(p\) and \(q\) both are
View solution