Problem 10
Question
Multiply or divide as indicated. $$ \sqrt{-11} \cdot \sqrt{-3} $$
Step-by-Step Solution
Verified Answer
The result is \(-\sqrt{33}\).
1Step 1: Identify the Components
The expression given is \( \sqrt{-11} \cdot \sqrt{-3} \). Notice that both components under the square roots are negative numbers, \(-11\) and \(-3\).
2Step 2: Use the Property of Imaginary Numbers
The square root of a negative number can be expressed using the imaginary unit \(i\), where \(i = \sqrt{-1}\). Thus, \(\sqrt{-11} = \sqrt{11} \cdot i\) and \(\sqrt{-3} = \sqrt{3} \cdot i\).
3Step 3: Rewrite the Expression with Imaginary Units
Substitute the expressions from Step 2 into the original problem: \( (\sqrt{11} \cdot i) \cdot (\sqrt{3} \cdot i) \).
4Step 4: Multiply the Radicals and Imaginary Units Separately
Combine the radicals and the imaginary units: \((\sqrt{11} \cdot \sqrt{3}) \cdot (i \cdot i) = \sqrt{33} \cdot i^2\).
5Step 5: Simplify Using the Property of \(i^2\)
Since \(i^2 = -1\), replace \(i^2\) with \(-1\): \(\sqrt{33} \cdot (-1) = -\sqrt{33}\).
6Step 6: Conclusion: Final Expression
The result of multiplying \( \sqrt{-11} \cdot \sqrt{-3} \) is \(-\sqrt{33}\).
Key Concepts
Complex NumbersSquare RootsProperties of i
Complex Numbers
Complex numbers are fascinating in the world of mathematics because they extend what we know about real numbers. A complex number is expressed in the form of \(a + bi\), where \(a\) and \(b\) are real numbers, and \(i\) represents the imaginary unit. This combination of real and imaginary parts enables us to solve equations that have no solutions in the real number system alone. For example, the equation \(x^2 + 1 = 0\) has no real solution because there is no real number whose square is negative. However, using complex numbers, the solution is possible.
- Imaginary Part: The "\(bi\)" in a complex number represents the imaginary component, where \(i = \sqrt{-1}\).
- Real Part: The "\(a\)" is just a regular real number.
Square Roots
Square roots are numbers that produce a specified value when multiplied by themselves. In the context of the problem \(\sqrt{-11} \cdot \sqrt{-3}\), square roots of negative numbers are involved, which cannot be solved within the real number framework.
To tackle square roots of negative numbers, we turn to imaginary numbers. The key is the imaginary unit \(i\), defined as \(\sqrt{-1}\). With this unit in hand, we can express any negative number's square root. For example:
To tackle square roots of negative numbers, we turn to imaginary numbers. The key is the imaginary unit \(i\), defined as \(\sqrt{-1}\). With this unit in hand, we can express any negative number's square root. For example:
- \(\sqrt{-11} = \sqrt{11} \cdot i\)
- \(\sqrt{-3} = \sqrt{3} \cdot i\)
Properties of i
The imaginary unit \(i\) has unique properties that make it indispensable in mathematics, particularly in dealing with complex numbers. The core property to remember is that \(i\) squared equals -1:
This process underscores the elegance of imaginary numbers as tools for solving problems that real numbers alone cannot address. Understanding these properties equips students to navigate further challenges involving complex expressions.
- \(i = \sqrt{-1}\)
- \(i^2 = -1\)
This process underscores the elegance of imaginary numbers as tools for solving problems that real numbers alone cannot address. Understanding these properties equips students to navigate further challenges involving complex expressions.
Other exercises in this chapter
Problem 10
Add or subtract as indicated. Assume that all variables represent positive real numbers. $$ \sqrt{4 x^{7}}+9 x^{2} \sqrt{x^{3}}-5 x \sqrt{x^{5}} $$
View solution Problem 10
Use the product rule to multiply. Assume that all variables represent positive real numbers. $$ \sqrt{\frac{6}{m}} \cdot \sqrt{\frac{n}{5}} $$
View solution Problem 11
Solve. $$ \sqrt[3]{6 x}=-3 $$
View solution Problem 11
Rationalize each denominator. Assume that all variables represent positive real numbers. \(\frac{9}{\sqrt{3 a}}\)
View solution