Problem 10
Question
\(\lim _{x \rightarrow 0} \frac{\sin ^{2} x}{\sqrt{2}-\sqrt{1+\cos x}}\) equals: \(\quad\) [April 8, 2019 (I)] (a) \(4 \sqrt{2}\) (b) \(\sqrt{2}\) (c) \(2 \sqrt{2}\) (d) 4
Step-by-Step Solution
Verified Answer
The limit equals \(2 \sqrt{2}\) which corresponds to option (c).
1Step 1: Identify the Limit to Evaluate
We are given the limit expression \( \lim_{x \rightarrow 0} \frac{\sin^2 x}{\sqrt{2} - \sqrt{1+\cos x}} \). Our task is to find the value of this limit as \( x \) approaches 0.
2Step 2: Simplify the Expression
Starting with the denominator \( \sqrt{2} - \sqrt{1+\cos x} \), we rationalize it by multiplying the numerator and the denominator by the conjugate \( \sqrt{2} + \sqrt{1+\cos x} \).
3Step 3: Rationalize the Denominator
Multiply \( \frac{\sin^2 x}{\sqrt{2} - \sqrt{1+\cos x}} \) by \( \frac{\sqrt{2} + \sqrt{1+\cos x}}{\sqrt{2} + \sqrt{1+\cos x}} \). The expression becomes \( \frac{\sin^2 x (\sqrt{2} + \sqrt{1+\cos x})}{2 - (1+\cos x)} \).
4Step 4: Simplify the Fraction
The denominator simplifies to \( 1 - \cos x \), and \( 1 - \cos x \) can be expressed as \( 2\sin^2(\frac{x}{2}) \) using the trigonometric identity.
5Step 5: Substitute Trigonometric Identity
The whole expression is \( \frac{\sin^2 x (\sqrt{2} + \sqrt{1+\cos x})}{2\sin^2(\frac{x}{2})} \). Now, substitute \( \sin^2 x = (2\sin(\frac{x}{2})\cos(\frac{x}{2}))^2 \).
6Step 6: Cancel out Common Terms
After substitution, calculate and simplify the terms to cancel out \( \sin(\frac{x}{2}) \) between numerator and denominator. It reduces the expression to \( \frac{(2\cos(\frac{x}{2}))^2(\sqrt{2} + \sqrt{1+\cos x})}{2} \).
7Step 7: Evaluate the Limit
As \( x \rightarrow 0 \), \( \cos(\frac{x}{2}) \rightarrow 1 \) and \( \sqrt{1+\cos x} \rightarrow \sqrt{2} \). So the limit evaluates to \( \frac{4 \sqrt{2}}{2} = 2\sqrt{2} \).
Key Concepts
Trigonometric LimitsRationalizing TechniquesTrigonometric Identities
Trigonometric Limits
Understanding trigonometric limits is crucial in calculus, particularly when dealing with functions involving sine, cosine, tangents, etc. Limits help us determine the behavior of functions as they approach a given point. In this exercise, the limit is evaluated as \( x \rightarrow 0 \).
When dealing with trigonometric functions, it’s important to remember some key limits. For instance:
When dealing with trigonometric functions, it’s important to remember some key limits. For instance:
- \( \lim_{x \to 0} \frac{\sin(x)}{x} = 1 \)
- \( \lim_{x \to 0} \frac{1 - \cos(x)}{x} = 0 \)
Rationalizing Techniques
Rationalizing is a technique used to eliminate roots from the denominator. It simplifies the function and makes finding limits more manageable.
In this exercise, the denominator \( \sqrt{2} - \sqrt{1+\cos x} \) can be tricky due to the root. To handle this, we use the conjugate \( \sqrt{2} + \sqrt{1+\cos x} \). Multiplying the original expression by this conjugate over itself changes our expression to: \[ \frac{\sin^2 x (\sqrt{2} + \sqrt{1+\cos x})}{(\sqrt{2} - \sqrt{1+\cos x})(\sqrt{2} + \sqrt{1+\cos x})}\]
By doing this, the denominator simplifies to a difference of squares: \( 2 - (1+\cos x) = 1 - \cos x \). This is a common strategy and often paves the way for further simplification using identities or transformations.
In this exercise, the denominator \( \sqrt{2} - \sqrt{1+\cos x} \) can be tricky due to the root. To handle this, we use the conjugate \( \sqrt{2} + \sqrt{1+\cos x} \). Multiplying the original expression by this conjugate over itself changes our expression to: \[ \frac{\sin^2 x (\sqrt{2} + \sqrt{1+\cos x})}{(\sqrt{2} - \sqrt{1+\cos x})(\sqrt{2} + \sqrt{1+\cos x})}\]
By doing this, the denominator simplifies to a difference of squares: \( 2 - (1+\cos x) = 1 - \cos x \). This is a common strategy and often paves the way for further simplification using identities or transformations.
Trigonometric Identities
Trigonometric identities are invaluable tools in simplifying expressions and solving calculus problems. They allow us to transform tricky trigonometric expressions into simpler forms that are more manageable.
In the problem at hand, we recognize that the expression \( 1 - \cos x \) can be rewritten using the identity:\[1 - \cos x = 2\sin^2\left(\frac{x}{2}\right)\] This identity is crucial because it allows us to cancel terms and simplify the original expression. Additionally, the identity \( \sin^2 x = (2\sin(\frac{x}{2})\cos(\frac{x}{2}))^2 \) helps further simplify our expression after substituting into the equation: \[\frac{\sin^2 x (\sqrt{2} + \sqrt{1+\cos x})}{2\sin^2\left(\frac{x}{2}\right)}\] By substituting and simplifying, trigonometric identities reduce the complexity of the problem, making it easier to compute or evaluate as \( x \to 0 \). Recognizing and applying the right identity is a key skill when working with trigonometric limits.
In the problem at hand, we recognize that the expression \( 1 - \cos x \) can be rewritten using the identity:\[1 - \cos x = 2\sin^2\left(\frac{x}{2}\right)\] This identity is crucial because it allows us to cancel terms and simplify the original expression. Additionally, the identity \( \sin^2 x = (2\sin(\frac{x}{2})\cos(\frac{x}{2}))^2 \) helps further simplify our expression after substituting into the equation: \[\frac{\sin^2 x (\sqrt{2} + \sqrt{1+\cos x})}{2\sin^2\left(\frac{x}{2}\right)}\] By substituting and simplifying, trigonometric identities reduce the complexity of the problem, making it easier to compute or evaluate as \( x \to 0 \). Recognizing and applying the right identity is a key skill when working with trigonometric limits.
Other exercises in this chapter
Problem 8
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