Problem 10
Question
Let \(S=\\{(u, v): 0 \leq u \leq 1\) \(0 \leq v \leq 1\\}\) be a unit square in the uv-plane. Find the image of \(S\) in the xy-plane under the following transformations. $$T: x=2 u v, y=u^{2}-v^{2}$$
Step-by-Step Solution
Verified Answer
Answer: The image of the unit square S in the xy-plane under the given transformation is a right-angled trapezoid.
1Step 1: Find the vertices of the square S in the uv-plane
To find the vertices of the unit square S in the uv-plane, we will look at the possible combinations of u and v based on the given constraints: \(0 \leq u \leq 1\) and \(0 \leq v \leq 1\).
The four vertices of the unit square S are:
- Vertex A: \((u=0, v=0)\)
- Vertex B: \((u=1, v=0)\)
- Vertex C: \((u=1, v=1)\)
- Vertex D: \((u=0, v=1)\)
2Step 2: Apply the transformation T to the vertices of S
We will now apply the given transformation $$T: x=2 u v, y=u^{2}-v^{2}$$ to the vertices A, B, C, and D to find their images in the xy-plane.
- Image of Vertex A under T: \((x=2(0)(0), y=(0)^{2}-(0)^{2}) = (0, 0)\)
- Image of Vertex B under T: \((x=2(1)(0), y=(1)^{2}-(0)^{2}) = (0, 1)\)
- Image of Vertex C under T: \((x=2(1)(1), y=(1)^{2}-(1)^{2}) = (2, 0)\)
- Image of Vertex D under T: \((x=2(0)(1), y=(0)^{2}-(1)^{2}) = (0, -1)\)
3Step 3: Find the shape of the image of S in the xy-plane
Now that we have found the images of the vertices of S under the transformation T, we will connect the points to determine the shape of the image of S in the xy-plane.
- The image of Vertex A connects to the image of Vertex B: Connect point (0, 0) to (0, 1).
- The image of Vertex B connects to the image of Vertex C: Connect point (0, 1) to (2, 0).
- The image of Vertex C connects to the image of Vertex D: Connect point (2, 0) to (0, -1).
- The image of Vertex D connects back to the image of Vertex A: Connect point (0, -1) to (0, 0).
Upon connecting these points, we can see that the image of S in the xy-plane is a right-angled trapezoid with vertices at (0, 0), (0, 1), (2, 0), and (0, -1).
Key Concepts
Unit SquareVerticesTrapezoidxy-plane
Unit Square
A unit square is a square with sides of length one. It’s a fundamental shape often used in geometry to understand transformations. In the context of this exercise:
- The unit square is defined in the uv-plane with corners determined by the values of \(u\) and \(v\).
- Since both \(u\) and \(v\) can range from 0 to 1, the unit square will have sides parallel to the axis.
- The corners of the square are calculated by combining the minimum and maximum values of \(u\) and \(v\).
Vertices
Vertices are the corner points of geometric shapes. For the unit square in this problem:
- Vertex \(A\) is \( (0, 0) \)
- Vertex \(B\) is \( (1, 0) \)
- Vertex \(C\) is \( (1, 1) \)
- Vertex \(D\) is \( (0, 1) \)
- The transformation maps the original points to new locations in the xy-plane.
- This mapping visualizes how each corner moves, giving insight into the resulting shape.
Trapezoid
A trapezoid is a four-sided figure with at least one pair of parallel sides. In this exercise, the transformed unit square becomes a right-angled trapezoid:
- The vertices after transformation are \( (0, 0), (0, 1), (2, 0), \) and \( (0, -1) \).
- Connecting these points, we see one pair of parallel sides, forming the trapezoid.
- This shape is useful for visual interpretation of the transformation’s impact on the unit square.
xy-plane
The xy-plane is the standard two-dimensional plane used in coordinate geometry:
- In this exercise, the xy-plane is the space where the transformed unit square is represented.
- Axes \(x\) and \(y\) are used to plot points and visualize transformations.
- The transformation \(T\) moves points from the uv-plane to new locations on this plane, showing the effect of the transformation.
Other exercises in this chapter
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