Problem 10
Question
Let \(f: \mathbb{R} \rightarrow \mathbb{R}\) and \(g: \mathbb{R} \rightarrow \mathbb{R}\) be continuous functions. Suppose that for all rational numbers \(r, f(r)=g(r)\). Show that \(f(x)=g(x)\) for all \(x\).
Step-by-Step Solution
Verified Answer
Since both functions are continuous and equal on dense rationals, they are equal on all reals.
1Step 1: Understand Continuity
Both functions \( f \) and \( g \) are continuous on the real number line \( \mathbb{R} \). Continuity means that for any point \( x \) in the domain, the limit of \( f \) as it approaches \( x \) equals \( f(x) \), and similarly for \( g \).
2Step 2: Equal Values on Rational Numbers
We are given that for all rational numbers \( r \), \( f(r) = g(r) \). Recall that the set of rational numbers \( \mathbb{Q} \) is dense in \( \mathbb{R} \), meaning that in any interval of \( \mathbb{R} \), you can find a rational number.
3Step 3: Denseness and Limit Points
Given that the rationals are dense in \( \mathbb{R} \), for any real number \( x \), there exists a sequence of rational numbers \( \{r_n\} \) converging to \( x \). Because \( f \) and \( g \) are continuous, \( \lim_{n \to \infty} f(r_n) = f(x) \) and \( \lim_{n \to \infty} g(r_n) = g(x) \).
4Step 4: Conclude Equality Using Limits
Since \( f(r_n) = g(r_n) \) for every rational \( r_n \) in the sequence, by continuity of \( f \) and \( g \), the limits must also be equal. Thus, \( f(x) = g(x) \) for all real numbers \( x \).
Key Concepts
real numbersrational numberslimit points
real numbers
Real numbers are an expansive set that includes all the numbers we encounter on a continuous number line. They are composed of both rational and irrational numbers, making them incredibly important in mathematics.
**Key Characteristics of Real Numbers:**
**Key Characteristics of Real Numbers:**
- Real numbers can be positive, negative, or zero.
- They encompass all possible magnitudes and can have decimal or fractional expressions.
- The continuity of real numbers makes them a perfect domain for many functions in calculus and analysis.
rational numbers
Rational numbers are numbers that can be expressed as the quotient of two integers, where the denominator is not zero. Symbolically, rational numbers are represented by the set \( \mathbb{Q} \). Examples include 1/2, -3, and 4.5, which can be written as 9/2.
**Properties of Rational Numbers:**
**Properties of Rational Numbers:**
- They are closed under addition, subtraction, multiplication, and division (except by zero).
- Each rational number can be expressed in its simplest form, leading to an unending or repeating decimal expansion.
limit points
In mathematics, particularly in the area of analysis, a limit point (or accumulation point) of a sequence is a point that the sequence approaches as it progresses through its terms. It is vital in discussions about convergence and continuity.
**Understanding Limit Points:**
Thus, the identification with limit points confirms why functions equal at rationals may indeed be equal across all real numbers when continuity is present, as any real number can serve as a limit point of a sequence of rationals.
**Understanding Limit Points:**
- A sequence converges to a limit point if its terms get arbitrarily close to the point as it progresses.
- A limit point can lie within the set of points generated by the sequence or outside of it.
Thus, the identification with limit points confirms why functions equal at rationals may indeed be equal across all real numbers when continuity is present, as any real number can serve as a limit point of a sequence of rationals.
Other exercises in this chapter
Problem 9
(Challenging): Suppose \(f(x)\) is a bounded polynomial, in other words, there is an \(M\) such that \(|f(x)| \leq M\) for all \(x \in \mathbb{R}\). Prove that
View solution Problem 9
Let \(c_{1}\) be a cluster point of \(A \subset \mathbb{R}\) and \(c_{2}\) be a cluster point of \(B \subset \mathbb{R}\). Suppose \(f: A \rightarrow B\) and \(
View solution Problem 10
a) Find a continuous \(f:(0,1) \rightarrow \mathbb{R}\) and a sequence \(\left\\{x_{n}\right\\}\) in (0,1) that is Cauchy, but such that \(\left\\{f\left(x_{n}\
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Suppose \(f:[0,1] \rightarrow[0,1]\) is continuous. Show that \(f\) has a fixed point, in other words, show that there exists an \(x \in[0,1]\) such that \(f(x)
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