Problem 10
Question
In Exercises \(7-14,\) use \(\log 2 \approx 0.3010, \log 5 \approx 0.6990,\) and \(\log 7 \approx 0.8451\) to evaluate each logarithm without using a calculator. Then check your answer using a calculator. $$\log \frac{5}{7}$$
Step-by-Step Solution
Verified Answer
The value of \(\log \frac{5}{7}\) is approximately -0.1461
1Step 1: Understand the Quotient Rule
In logarithmic computations, the quotient rule is a useful tool. It states that \(\log\frac{a}{b} = \log a - \log b\). This rule has to be followed for this exercise.
2Step 2: Apply the Quotient Rule
Applying the quotient rule to the given logarithm, we find that \(\log \frac{5}{7} = \log 5 - \log 7\).
3Step 3: Substitute Values
Using provided values for \(\log 5\) (which is approximately 0.6990) and \(\log 7\) (which is approximately 0.8451), we substitute these into the equation. Therefore, \(\log \frac{5}{7} = 0.6990 - 0.8451\).
4Step 4: Perform Subtraction
The subtraction results in -0.1461.
Key Concepts
Quotient Rule for LogarithmsLogarithmic PropertiesEvaluating Logarithms Without a Calculator
Quotient Rule for Logarithms
Understanding the quotient rule for logarithms is pivotal for solving logarithmic equations where division is involved. This property essentially simplifies the process by breaking down complex expressions. The rule is straightforward: for any positive numbers a and b where both a and b do not equal 1, and for any base b, the logarithm of a quotient is the difference between the logarithm of the numerator and the logarithm of the denominator. Mathematically, it is expressed as
\[\log_b\left(\frac{a}{c}\right) = \log_b(a) - \log_b(c)\].
By extracting and subtracting individual logarithms, this facilitates mental arithmetic or paper calculations without the immediate need for a calculator. Applying this rule to the given exercise,
\[\log \left(\frac{5}{7}\right) = \log(5) - \log(7)\]
leads to a simplified form that can be manually computed using familiar logarithm values.
\[\log_b\left(\frac{a}{c}\right) = \log_b(a) - \log_b(c)\].
By extracting and subtracting individual logarithms, this facilitates mental arithmetic or paper calculations without the immediate need for a calculator. Applying this rule to the given exercise,
\[\log \left(\frac{5}{7}\right) = \log(5) - \log(7)\]
leads to a simplified form that can be manually computed using familiar logarithm values.
Logarithmic Properties
Grasping the various logarithmic properties not only aids in computation but also enriches the conceptual understanding of logarithms. Beyond the quotient rule, there are other significant properties to know:
- Product Rule: For any positive numbers a and b, \(\log_b(ab) = \log_b(a) + \log_b(b)\).
- Power Rule: For any positive number a, \(\log_b(a^c) = c \cdot \log_b(a)\), where c is a real number.
- Change of Base Formula: For any positive numbers a and b, with b not equal to 1, you can change to a different base by using \(\log_b(a) = \frac{\log_c(a)}{\log_c(b)}\), where c is the new base you are converting to.
- Logarithm of 1: For any positive base b where b is not equal to 1, \(\log_b(1) = 0\).
- Logarithm of Base: For any positive base b, \(\log_b(b) = 1\).
Evaluating Logarithms Without a Calculator
In scenarios where a calculator is not available, understanding how to evaluate logarithms without a calculator becomes indispensable. It requires familiarity with common log values, the use of logarithmic properties, and sometimes estimation and pattern recognition. In the step-by-step solution presented in this exercise, known values of \(\log(2)\), \(\log(5)\), and \(\log(7)\) are employed to solve for \(\log\left(\frac{5}{7}\right)\). By substituting the given values – \(\log(5) \approx 0.6990\) and \(\log(7) \approx 0.8451\) – manual subtraction reveals the answer as -0.1461, showcasing a practical application of logarithmic evaluation.
Estimation plays a key role too, especially when dealing with logs to bases other than 10 or e (the natural logarithm). You can use patterns, like knowing that \(\log_b(b^n) = n\), to extrapolate unknown values from known ones. Also, recall that any log to the base of its number is 1, and the log of 1 to any base is 0. Integrating these simple tips can significantly ease the manual computation of logarithms in various contexts.
Estimation plays a key role too, especially when dealing with logs to bases other than 10 or e (the natural logarithm). You can use patterns, like knowing that \(\log_b(b^n) = n\), to extrapolate unknown values from known ones. Also, recall that any log to the base of its number is 1, and the log of 1 to any base is 0. Integrating these simple tips can significantly ease the manual computation of logarithms in various contexts.
Other exercises in this chapter
Problem 10
Use \(f(t)=10 e^{-t}\). For what value of \(t\) will \(f(t)=2 ?\)
View solution Problem 10
Solve the exponential equation. Round to three decimal places, when needed. $$6^{x}=\frac{1}{216}$$
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Write 1,360,000,000,000 in scientific notation.
View solution Problem 10
Verify that the given functions are inverses of each other. $$f(x)=x+7 ; g(x)=x-7$$
View solution