Problem 10
Question
In \(3-14,\) write each expression as a single term using \(\sin \theta, \cos \theta,\) or both. $$ \tan \theta \sec \theta \cot \theta $$
Step-by-Step Solution
Verified Answer
The expression simplifies to \( \sec^2 \theta \).
1Step 1: Write in terms of sine and cosine
First, express each trigonometric function in terms of \( \sin \theta \) and \( \cos \theta \). We know that \( \tan \theta = \frac{\sin \theta}{\cos \theta} \), \( \sec \theta = \frac{1}{\cos \theta} \), and \( \cot \theta = \frac{\cos \theta}{\sin \theta} \).
2Step 2: Substitute the expressions
Substitute the expressions from Step 1 into the given expression. We have: \[ \tan \theta \sec \theta \cot \theta = \frac{\sin \theta}{\cos \theta} \cdot \frac{1}{\cos \theta} \cdot \frac{\cos \theta}{\sin \theta}. \]
3Step 3: Simplify the expression
Cancel out the terms in the numerator and the denominator. The \( \cos \theta \) in the numerator and denominator will cancel each other, as will the \( \sin \theta \), leaving us with \[ \frac{1}{\cos^2 \theta}. \]
4Step 4: Write in terms of secant
Recognize that \( \frac{1}{\cos^2 \theta} \) is \( \sec^2 \theta \). Thus, the expression simplifies to \( \sec^2 \theta \).
Key Concepts
Sine and CosineTrigonometric IdentitiesSimplification of Trigonometric Expressions
Sine and Cosine
Trigonometry often begins with understanding sine and cosine, the foundational trigonometric functions. These functions relate the angles and sides of a right triangle.
The unit circle is a circle centered at the origin of a coordinate plane with a radius of 1. It allows us to extend the definitions of sine and cosine to angles greater than 90 degrees and to negative angles.
In our exercise, expressing each trigonometric function in terms of \( \sin \theta \) and \( \cos \theta \) helps in simplifying the expression, as these are the basic and most easily manageable forms.
- The sine function, denoted as \( \sin \theta \), represents the ratio of the length of the side opposite angle \( \theta \) to the hypotenuse of the triangle.
- The cosine function, denoted as \( \cos \theta \), represents the ratio of the length of the adjacent side to the hypotenuse.
The unit circle is a circle centered at the origin of a coordinate plane with a radius of 1. It allows us to extend the definitions of sine and cosine to angles greater than 90 degrees and to negative angles.
In our exercise, expressing each trigonometric function in terms of \( \sin \theta \) and \( \cos \theta \) helps in simplifying the expression, as these are the basic and most easily manageable forms.
Trigonometric Identities
Trigonometric identities are equations that hold true for all values of the variable where they are defined. They are tools that simplify and solve trigonometric expressions and equations.
- The reciprocal identities, which allow us to express secant, cosecant, and cotangent in terms of sine and cosine, are crucial. In the exercise, we used the identities \( \sec \theta = \frac{1}{\cos \theta} \) and \( \cot \theta = \frac{\cos \theta}{\sin \theta} \).
- The Pythagorean identities, like \( \sin^2 \theta + \cos^2 \theta = 1 \), help in simplifying and transforming expressions further if needed.
Simplification of Trigonometric Expressions
Simplifying trigonometric expressions involves rewriting them in a simpler or more efficient form without changing the value. This often includes using trigonometric identities to eliminate terms and combine like terms.
- In the resolved exercise, we started by rewriting each trigonometric function using sine and cosine. This step is essential because the basic trigonometric functions are simpler to work with and provide a common base for manipulation.
- Next, we substituted these expressions into the original, leading to an expression that allows for straightforward simplification: \( \frac{\sin \theta}{\cos \theta} \cdot \frac{1}{\cos \theta} \cdot \frac{\cos \theta}{\sin \theta} \).
- Upon simplification, where terms cancel out, the expression results in \( \sec^2 \theta \). Recognizing \( \frac{1}{\cos^2 \theta} \) as \( \sec^2 \theta \) highlights the use of trigonometric identites to achieve this simplification.
Other exercises in this chapter
Problem 10
\(\ln 3-17,\) find the exact value of \(\sin (A-B)\) and of \(\sin (A+B)\) for each given pair of values. \(A=90^{\circ}, B=60^{\circ}\)
View solution Problem 10
In \(3-17,\) find the exact value of \(\cos (A+B)\) for each given pair of values. \(A=270^{\circ}, B=60^{\circ}\)
View solution Problem 10
In \(3-17,\) find the exact value of \(\cos (A-B)\) for each given pair of values. \(A=90^{\circ}, B=60^{\circ}\)
View solution Problem 11
In \(3-17,\) find the exact value of \(\tan (A+B)\) and of \(\tan (A-B)\) for each given pair of values. $$ A=120^{\circ}, B=60^{\circ} $$
View solution