Problem 10
Question
If \(f(1)=5,\) must \(\lim _{x \rightarrow 1} f(x)\) exist? If it does, then must \(\lim _{x \rightarrow 1} f(x)=5 ?\) Can we conclude anything about lim \(_{x \rightarrow 1} f(x) ?\) Explain.
Step-by-Step Solution
Verified Answer
The existence of \( \lim _{x \rightarrow 1} f(x) \) cannot be concluded just from \( f(1)=5 \); its value may not be 5.
1Step 1: Understanding the Limit Definition
The limit \( \lim _{x \rightarrow a} f(x) \) exists if as \( x \) approaches \( a \), the values of \( f(x) \) approach a particular single real number \( L \). This means that to conclude the limit exists, \( f(x) \) should be approaching the same value from both the left and right as \( x \) approaches \( a \). In this case, as \( x \rightarrow 1 \).
2Step 2: Check the Given Function Value
The problem states that \( f(1)=5 \). This tells us the exact value of the function at \( x=1 \), but it doesn't directly inform us about the behavior of the function as \( x \rightarrow 1 \). Thus, knowing the function's value at \( x=1 \) isn't sufficient to conclude the behavior around it.
3Step 3: Determine if Limit Must Exist
\( \lim _{x \rightarrow 1} f(x) \) will exist if \( f(x) \), approaching from both directions (left and right) towards \( x=1 \), tends to a single value. Given only \( f(1)=5 \), we don't have enough information about \( f(x) \) to conclusively determine that the limit exists as \( x \rightarrow 1 \). The existence of a limit depends on the continuity or behavior of \( f(x) \) around \( x = 1 \), which isn't provided.
4Step 4: Does Limit Equal the Function Value?
Even if the limit \( \lim _{x \rightarrow 1} f(x) \) does exist, it does not necessarily have to equal the function value \( f(1) = 5 \). For example, a function could approach 4 as \( x \rightarrow 1 \) but still have \( f(1) = 5 \). Without more information, we cannot assume \( \lim _{x \rightarrow 1} f(x) = 5 \).
5Step 5: Conclusion on the Limit
Based on the given information, we cannot make any definitive conclusion about \( \lim _{x \rightarrow 1} f(x) \). We need additional data regarding the function's behavior as it approaches \( x=1 \) from both sides to determine both the existence of the limit and its value.
Key Concepts
ContinuityLimit DefinitionFunction Behavior
Continuity
Continuity is like the smooth running of a movie. Just as each frame glides seamlessly into the next without any jumps, a function is continuous at a point if there are no interruptions or gaps in its behavior around that point. For a function to be continuous at a certain point, it needs to satisfy three conditions:
\( f(1) = 5 \), this only tells us that the function is defined at \( x = 1 \), but it doesn't inform us about the limit or whether the function is continuous as \( x \rightarrow 1 \).
- The function is defined at the point.
- The limit of the function exists as it approaches that point.
- The limit equals the function value at that point.
\( f(1) = 5 \), this only tells us that the function is defined at \( x = 1 \), but it doesn't inform us about the limit or whether the function is continuous as \( x \rightarrow 1 \).
Limit Definition
The concept of a limit captures the idea of a function approaching a particular value as the input gets closer and closer to a specific point. Let's break it down further:
- For \( \lim_{x \rightarrow a} f(x) \) to exist, the values of \( f(x) \) need to hone in on a single number \( L \) as \( x \) moves towards \( a \).
- This must happen regardless of whether \( x \) approaches \( a \) from the left or the right.
Function Behavior
A function's behavior as it approaches a particular point can reveal much about the existence and nature of a limit. Here are some scenarios to consider:
In the context of our exercise, despite knowing \( f(1) = 5 \), we lack information about how \( f(x) \) behaves when nearing \( x = 1 \). Without insights into this approaching behavior, we cannot conclusively pinpoint the existence or value of the limit.
- If \( f(x) \) approaches a single finite value from both directions as \( x \rightarrow 1 \), then the limit exists.
- Conversely, if \( f(x) \) behaves erratically or diverges from different sides, the limit does not exist.
In the context of our exercise, despite knowing \( f(1) = 5 \), we lack information about how \( f(x) \) behaves when nearing \( x = 1 \). Without insights into this approaching behavior, we cannot conclusively pinpoint the existence or value of the limit.
Other exercises in this chapter
Problem 10
Exercises \(5-10\) refer to the function $$f(x)=\left\\{\begin{array}{ccc}{x^{2}-1,} & {-1 \leq x
View solution Problem 10
Find the limits in Exercises \(9-12\) . $$\lim _{\theta \rightarrow-\infty} \frac{\cos \theta}{3 \theta}$$
View solution Problem 11
Find the limits in Exercises \(9-12\) . $$\lim _{t \rightarrow-\infty} \frac{2-t+\sin t}{t+\cos t}$$
View solution Problem 11
Find the limits in Exercises \(11-18\) $$\lim _{x \rightarrow-0.5} \sqrt{\frac{x+2}{x+1}}$$
View solution