Problem 10
Question
For the following problems, solve the equations. $$ (a-5)^{2}=0 $$
Step-by-Step Solution
Verified Answer
Answer: The solution to the equation is \(a=5\).
1Step 1: Apply the square root
Apply the square root to both sides of the equation:
$$\sqrt{(a-5)^2} = \sqrt{0}$$
2Step 2: Simplify square roots
Simplify the square roots:
$$a-5 = 0$$
3Step 3: Solve for a
Add 5 to both sides of the equation to solve for a:
$$a = 5$$
The solution for the given equation is \(a=5\).
Key Concepts
Quadratic EquationsSquare RootsAlgebraic Solutions
Quadratic Equations
Quadratic equations are a type of polynomial equation where the highest exponent of the variable is 2. These equations follow the standard form of \( ax^2 + bx + c = 0 \), where \( a \), \( b \), and \( c \) are known numbers, with \( a \) not equal to zero. Quadratic equations can graphically represent a parabola, which is a symmetrical curve. In many real-world situations, quadratic equations model scenarios like projectile motion, area problems, and more.
Solving quadratic equations can be done using several methods including:
Solving quadratic equations can be done using several methods including:
- Factoring: Express the equation as a product of its factors.
- Quadratic Formula: For any quadratic equation \( ax^2 + bx + c = 0 \), the solution can be found using \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \).
- Completing the Square: Rearrange the equation into a perfect square trinomial.
- Graphical Method: Plotting the equation and finding the roots where the graph intersects the x-axis.
Square Roots
Square roots are mathematical operations that find the number which, when multiplied by itself, gives the original number. For example, the square root of 9 is 3, written as \( \sqrt{9} = 3 \), since \( 3 \times 3 = 9 \).
In the context of equations, using square roots is a method to simplify and solve expressions. For the exercise, we used the square root to simplify \((a-5)^2 = 0\), resulting in \( \sqrt{(a-5)^2} = 0\). This becomes \( a-5 = 0 \), showing how square roots help isolate variables.
Square roots are vital in many areas of mathematics and science because:
In the context of equations, using square roots is a method to simplify and solve expressions. For the exercise, we used the square root to simplify \((a-5)^2 = 0\), resulting in \( \sqrt{(a-5)^2} = 0\). This becomes \( a-5 = 0 \), showing how square roots help isolate variables.
Square roots are vital in many areas of mathematics and science because:
- They are essential in geometry, particularly in finding distances.
- They factor into solving quadratic equations and polynomial identities.
- They appear in real-world problems involving proportions, physics, and engineering.
Algebraic Solutions
Algebraic solutions involve solving equations using algebraic manipulations and operations. When dealing with equations like \((a-5)^2 = 0\), the goal is to isolate the variable. This often means performing inverse operations to cancel parts of the equation.
In the exercise, we use the concept of inverse operations:
Key principles include:
In the exercise, we use the concept of inverse operations:
- Taking the Square Root: Applied to both sides to "undo" the square on \((a-5)\).
- Solving for the Variable: Once simplified, we find \(a = 5\) by adding 5 to both sides.
Key principles include:
- Identifying operations that cancel each other, like multiplication and division, addition and subtraction.
- Employing distributive, associative, and commutative properties as needed.
- Checking your solution to ensure it satisfies the original equation.
Other exercises in this chapter
Problem 9
Use the zero-factor property to solve each equation. $$ (x+5)(3 x-4)=0 $$
View solution Problem 9
Solve \((9 x+2)(7 x-3)=0\) using this mental method.
View solution Problem 10
The manufacturer of electronic fuel injectors determines that the number \(N\) of injectors sold is related to the price \(x\) per injector by \(N=22 x-x^{2}\).
View solution Problem 10
Solve each quadratic equation by factoring. $$ 2 x^{2}=-2-5 x $$
View solution