Problem 10
Question
For the following exercises, determine whether the relation represents \(y\) as a function of \(x\). $$ x=y^{2} $$
Step-by-Step Solution
Verified Answer
The relation does not represent \(y\) as a function of \(x\) because \(x = y^2\) results in two possible \(y\) values for one \(x\).
1Step 1: Understanding the Relation
The given relation is \(x = y^2\). Here, \(x\) is written in terms of \(y\). To check if this relation represents \(y\) as a function of \(x\), we need to understand how \(y\) behaves for each \(x\).
2Step 2: Analyzing the Equation
For any given \(x \geq 0\), the equation \(x = y^2\) can have two solutions for \(y\), which are \(y = \sqrt{x}\) and \(y = -\sqrt{x}\). This means \(y\) can have two values for one \(x\) when \(x\) is non-negative.
3Step 3: Determine if Each Input Has Exactly One Output
For \(y\) to be a function of \(x\), there should be exactly one \(y\) value for each \(x\) value. Since for \(x = 4\), \(y\) can be \(2\) or \(-2\), \(y\) does not have a unique output for every \(x\). Therefore, this relation is not a function.
Key Concepts
RelationOne-to-One CorrespondenceFunction of a VariableMathematical Analysis
Relation
A relation in mathematics is a connection between two sets of values, where each element of one set is paired with one or more elements of another set. In the given exercise, the relation is expressed by the equation \(x = y^2\). Here, values of \(x\) are related to values of \(y\). The challenge is to identify if this relation can act as a function.To better understand relations:
- A relation can exist between numbers, shapes, or even colors.
- Relations are often represented using ordered pairs \((x, y)\).
- A relation displays how elements from one set are associated with elements from another set.
One-to-One Correspondence
One-to-one correspondence is a specific type of function where each input has a unique output, and each output has a single input. However, this contrast sharply with the relation \(x = y^2\) given in the exercise.In our relation:
- The equation \(x = y^2\) shows that for a given \(x\), there might be multiple \(y\) values, specifically, \(y = \sqrt{x}\) and \(y = -\sqrt{x}\).
- This means that \(x = 4\) could correspond to both \(y = 2\) and \(y = -2\). Hence, it fails to be a one-to-one correspondence.
Function of a Variable
A function of a variable is a relation that assigns exactly one output for every input. For \(y\) to be a function of \(x\), each outcome in the set of \(x\) values must map to only one \(y\) value.Consider the equation \(x = y^2\):
- For this equation to depict \(y\) as a function of \(x\), every value of \(x\) would need to relate to exactly one \(y\) value.
- However, as analyzed, values like \(x = 4\) lead to two different \(y\) values (\(2\) and \(-2\)).
Mathematical Analysis
Mathematical analysis involves studying functions and their properties, and understanding their underlying principles.In examining this relation \(x = y^2\), mathematical analysis helps us:
- Break down how the elements of the relation relate to each other.
- Conclude that the relation cannot be a function due to the multiple \(y\) outputs for a single \(x\) input.
Other exercises in this chapter
Problem 10
For the following exercises, determine the domain for each function in interval notation. Given \(f(x)=\sqrt{x}\) and \(g(x)=|x-3|,\) find \(\frac{g}{f}\)
View solution Problem 10
For the following exercises, find the average rate of change of each function on the interval specified for real numbers \(b\) or \(h\) in simplest form. $$ g(x
View solution Problem 10
For the following exercises, find the domain of each function using interval notation. $$ f(x)=\sqrt{4-3 x} $$
View solution Problem 11
For the following exercises, find \(f^{-1}(x)\) for each function. $$ f(x)=\frac{x}{x+2} $$
View solution