Problem 10
Question
For Problems 1-12, perform the indicated operations involving rational numbers. Be sure to express your answers in reduced form. \(\frac{2}{3}-\frac{7}{8}+\frac{1}{4}\)
Step-by-Step Solution
Verified Answer
The result is \( \frac{1}{24} \).
1Step 1: Find a common denominator
To perform the operations with fractions, we first need to find a common denominator. The denominators here are 3, 8, and 4. The least common multiple (LCM) of these numbers is 24.
2Step 2: Convert each fraction to have the common denominator
Convert \( \frac{2}{3} \) by multiplying both the numerator and the denominator by 8 to get \( \frac{16}{24} \). Convert \( \frac{7}{8} \) by multiplying both by 3 to get \( \frac{21}{24} \). Convert \( \frac{1}{4} \) by multiplying both by 6 to get \( \frac{6}{24} \).
3Step 3: Perform the subtraction and addition
Now, perform the operations using the common denominator: \( \frac{16}{24} - \frac{21}{24} + \frac{6}{24} \). Start by performing the subtraction: \( 16 - 21 = -5 \), so the result is \( \frac{-5}{24} \).
4Step 4: Add the next fraction
Next, add \( \frac{-5}{24} + \frac{6}{24} \). Add the numerators: \( -5 + 6 = 1 \), giving the result \( \frac{1}{24} \).
5Step 5: Simplify the fraction
The fraction \( \frac{1}{24} \) is already in its simplest form, as 1 and 24 have no common factors besides 1.
Key Concepts
Least Common MultipleFractions with Common DenominatorsSimplifying FractionsSubtraction and Addition of Fractions
Least Common Multiple
When dealing with fractions that have different denominators, finding a common denominator is crucial for performing operations like addition and subtraction. The least common multiple (LCM) is the smallest number that all denominators divide into without leaving a remainder.
To find the LCM of 3, 8, and 4, we list the multiples of each number:
To find the LCM of 3, 8, and 4, we list the multiples of each number:
- Multiples of 3: 3, 6, 9, 12, 15, 18, 21, 24...
- Multiples of 8: 8, 16, 24, 32...
- Multiples of 4: 4, 8, 12, 16, 20, 24...
Fractions with Common Denominators
Once we determine the LCM, the next step is converting each fraction to have this common denominator. This involves adjusting each fraction so its denominator matches the LCM while keeping the fraction equivalent.
For example, to convert \( \frac{2}{3} \) to a fraction with a denominator of 24:
For example, to convert \( \frac{2}{3} \) to a fraction with a denominator of 24:
- Multiply both the numerator and denominator by 8 (since 3 × 8 = 24), resulting in \( \frac{16}{24} \).
- Multiply both by 3 (as 8 × 3 = 24) to get \( \frac{21}{24} \).
- Multiply both by 6 (because 4 × 6 = 24), resulting in \( \frac{6}{24} \).
Simplifying Fractions
Simplifying a fraction means reducing it to its lowest terms. This involves dividing the numerator and the denominator by their greatest common divisor (GCD). A fraction is in its simplest form when the numerator and denominator can no longer be divided by any number other than 1.
For instance, consider \( \frac{16}{24} \). The GCD of 16 and 24 is 8. So, dividing both the numerator and denominator by 8 gives us \( \frac{2}{3} \). However, in our problem, the resulting fraction \( \frac{1}{24} \) is already in its simplest form since 1 and 24 have no common factors other than 1.
Always check your final answer to make sure it is simplified, as this is often a requirement in mathematical problems.
For instance, consider \( \frac{16}{24} \). The GCD of 16 and 24 is 8. So, dividing both the numerator and denominator by 8 gives us \( \frac{2}{3} \). However, in our problem, the resulting fraction \( \frac{1}{24} \) is already in its simplest form since 1 and 24 have no common factors other than 1.
Always check your final answer to make sure it is simplified, as this is often a requirement in mathematical problems.
Subtraction and Addition of Fractions
With all fractions now having a common denominator, you can perform subtraction and addition without any hassle.
Taking our fractions \( \frac{16}{24} - \frac{21}{24} + \frac{6}{24} \):
Taking our fractions \( \frac{16}{24} - \frac{21}{24} + \frac{6}{24} \):
- First, subtract \( \frac{21}{24} \) from \( \frac{16}{24} \): This becomes \( 16 - 21 = -5 \), so \( \frac{-5}{24} \).
- Next, add \( \frac{6}{24} \) to \( \frac{-5}{24} \): Add the numerators, \( -5 + 6 = 1 \), resulting in \( \frac{1}{24} \).
Other exercises in this chapter
Problem 10
Perform the indicated divisions of polynomials by monomials. $$ \frac{-27 a^{3} b^{4}-36 a^{2} b^{3}+72 a^{2} b^{5}}{9 a^{2} b^{2}} $$
View solution Problem 10
Perform the indicated operations, and express your answers in simplest form. $$ \frac{3 n}{n^{2}-36}-\frac{2}{5 n+30} $$
View solution Problem 10
For Problems 9-50, simplify each rational expression. \(\frac{21 x y}{35 x}\)
View solution Problem 11
Solve each equation. $$ \frac{2}{n-2}-\frac{n}{n+5}=\frac{10 n+15}{n^{2}+3 n-10} $$
View solution