Problem 10
Question
For Problems 1-12, find the equation of the line that contains the given point and has the given slope. Express equations in the form \(A x+B y=C\), where \(A, B\), and \(C\) are integers. $$ (0,0), m=\frac{5}{11} $$
Step-by-Step Solution
Verified Answer
The equation of the line is \(5x - 11y = 0\).
1Step 1: Understand Point-Slope Formula
To find the equation of the line, we start with the point-slope form of the equation, which is given by \(y - y_1 = m(x - x_1)\), where \(m\) is the slope and \((x_1, y_1)\) is a point on the line.
2Step 2: Substitute Given Values
Substitute the point \((0, 0)\) and the slope \(m = \frac{5}{11}\) into the point-slope form: \(y - 0 = \frac{5}{11}(x - 0)\). This simplifies to \(y = \frac{5}{11}x\).
3Step 3: Eliminate Fractions
To express the equation in the form \(Ax + By = C\), we eliminate the fraction by multiplying through by 11: \(11y = 5x\).
4Step 4: Rearrange to Standard Form
Rearrange the equation to get it in the desired form \(Ax + By = C\). Move all terms to one side: \(5x - 11y = 0\).
Key Concepts
Point-Slope FormSlope-Intercept FormStandard Form of a Line
Point-Slope Form
The point-slope form is a versatile method for writing the equation of a line. It comes handy when you are equipped with a point on the line and the slope of the line. The formula for the point-slope form looks like this: \( y - y_1 = m(x - x_1) \). In this formula:
- \( (x_1, y_1) \) represents a specific point on the line.
- \( m \) is the slope of the line.
Slope-Intercept Form
The slope-intercept form is probably the most commonly used equation of a line form because of its intuitive understanding. It looks like this: \(y = mx + b\). This form explicitly shows:
- The slope \(m\), which tells you how steep the line is.
- The y-intercept \(b\), which indicates where the line crosses the y-axis.
Standard Form of a Line
The standard form of a line's equation is \(Ax + By = C\), where \(A\), \(B\), and \(C\) are integers, and \(A\) should preferably be non-negative. This form is particularly useful for certain algebraic techniques and for clearly understanding relationships in linear programming and systems of equations.
To reach the standard form from the slope-intercept form \(y = \frac{5}{11}x\), we first eliminate any fractions by multiplying the entire equation by 11. This gives us \(11y = 5x\). Rearranging terms, we arrive at \(5x - 11y = 0\). The standard form tidy ups the equation into integer values, which is often required for short answer questions or standardized tests. Remember, although each form might present the equation differently, they all represent the same line.
To reach the standard form from the slope-intercept form \(y = \frac{5}{11}x\), we first eliminate any fractions by multiplying the entire equation by 11. This gives us \(11y = 5x\). Rearranging terms, we arrive at \(5x - 11y = 0\). The standard form tidy ups the equation into integer values, which is often required for short answer questions or standardized tests. Remember, although each form might present the equation differently, they all represent the same line.
Other exercises in this chapter
Problem 9
Find the slope of the line determined by each pair of points. $$(4,-1),(-4,-7)$$
View solution Problem 10
Find the equation of the line that contains the given point and has the given slope. Express equations in the form \(A x+B y=C\), where \(A, B\), and \(C\) are
View solution Problem 10
For Problems 1-36, graph each linear equation. (Objective 2) $$ 2 x-y=-4 $$
View solution Problem 10
Use the elimination-by-addition method to solve each system. $$\left(\begin{array}{l}4 x+3 y=-4 \\ 3 x-7 y=34\end{array}\right)$$
View solution