Problem 10
Question
For each polynomial function, list the zeros of the polynomial and state the multiplicity of each zero. $$h(x)=(x-\sqrt{2})^{13}(x+\sqrt{2})^{7}$$
Step-by-Step Solution
Verified Answer
The zeros of the polynomial \(h(x)\) are \(\sqrt{2}\) and \(-\sqrt{2}\). The multiplicity of the zero \(\sqrt{2}\) is 13, and the multiplicity of the zero \(-\sqrt{2}\) is 7.
1Step 1: Identify the Zeros
The zeros of the polynomial are the solutions of the equation \(h(x) = 0\). Looking at the polynomial, we have \(h(x)=(x-\sqrt{2})^{13}(x+\sqrt{2})^{7}\). If we set each factor equal to zero, we get zero at \(x=\sqrt{2}\) and at \(x=-\sqrt{2}\)
2Step 2: Identify the Multiplicity
The multiplicity of a zero is given by the exponent on its term. In \(h(x)=(x-\sqrt{2})^{13}(x+\sqrt{2})^{7}\), the zero \(\sqrt{2}\) as a multiplicity of 13, and the zero \(-\sqrt{2}\) has a multiplicity of 7
Key Concepts
Zeros of PolynomialMultiplicityFactoring Polynomials
Zeros of Polynomial
The zeros of a polynomial are the values of the variable which make the polynomial equal to zero. In other words, zeros are the solutions to the equation that is formed when you set the polynomial equal to zero. Finding these zeros is essential, as they tell us where the graph of the polynomial intersects the x-axis. Consider the polynomial given in the example: \[h(x)=(x-\sqrt{2})^{13}(x+\sqrt{2})^7\]To find the zeros, we set each factor equal to zero:
- First factor: \[(x-\sqrt{2}) = 0\]Solving gives us \[x = \sqrt{2}\]
- Second factor: \[(x+\sqrt{2}) = 0\]Solving gives us \[x = -\sqrt{2}\]
Multiplicity
Multiplicity refers to the number of times a particular zero appears in the polynomial. In mathematical terms, it is the exponent of the factor that corresponds to the zero.In our polynomial \[h(x)=(x-\sqrt{2})^{13}(x+\sqrt{2})^7\], we observe:
- The zero \( x = \sqrt{2} \) is associated with the factor \((x-\sqrt{2})^{13}\). Here, 13 is the exponent, so the multiplicity is 13.
- The zero \( x = -\sqrt{2} \) is associated with the factor \((x+\sqrt{2})^7\). Here, 7 is the exponent, so the multiplicity is 7.
Factoring Polynomials
Factoring polynomials is the process of breaking down a polynomial into a product of its simplest polynomial components, or factors. It's akin to finding the building blocks of your polynomial, showing which numbers multiply together to give you the entire expression.Consider the polynomial we are dealing with:\[h(x)=(x-\sqrt{2})^{13}(x+\sqrt{2})^7\]This polynomial is already factored into its component binomials \((x-\sqrt{2})\) and \((x+\sqrt{2})\) raised to the respective powers. Factoring offers us several insights:
- It reveals the zeros of the polynomial.
- Shows us the multiplicity as observed in the exponents.
- Helps in taking apart complex formulas to simplify calculation and analysis.
Other exercises in this chapter
Problem 9
Complete them to review topics relevant to the remaining exercises. The graph of \(f(x)=x^{2}+3\) is the graph of \(y=x^{2}\) shifted __________ 3 units.
View solution Problem 10
Solve the polynomial inequality. $$x^{3}-9 x>0$$
View solution Problem 10
For each polynomial, determine which of the numbers listed next to it are zeros of the polynomial. $$(x)=x^{3}+2 x^{2}-2 x-4 ; x=\sqrt{2},-\sqrt{3}$$
View solution Problem 10
Find the domain and the vertical and horizontal asymptotes (if any). $$f(x)=\frac{2}{x^{2}-9}$$
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