Problem 10
Question
Find the sum \(\mathbf{u}+\mathbf{v}\), the difference \(\mathbf{u}-\mathbf{v}\), and the magnitudes \(\|\mathbf{u}\|\) and \(\|\mathbf{v}\|\) $$ \mathbf{u}=\langle 0,0\rangle, \mathbf{v}=\langle-3,4\rangle $$
Step-by-Step Solution
Verified Answer
The sum is \( \langle -3, 4 \rangle \), the difference is \( \langle 3, -4 \rangle \), \( \|\mathbf{u}\| = 0 \), \( \|\mathbf{v}\| = 5 \).
1Step 1: Find the Sum \( \mathbf{u} + \mathbf{v} \)
To find the sum of two vectors, add their respective components. The vector \( \mathbf{u} = \langle 0,0 \rangle \) and the vector \( \mathbf{v} = \langle -3,4 \rangle \). Thus, \( \mathbf{u} + \mathbf{v} = \langle 0+(-3), 0+4 \rangle = \langle -3, 4 \rangle \).
2Step 2: Find the Difference \( \mathbf{u} - \mathbf{v} \)
To find the difference between two vectors, subtract their respective components. We again use \( \mathbf{u} = \langle 0,0 \rangle \) and \( \mathbf{v} = \langle -3,4 \rangle \). Thus, \( \mathbf{u} - \mathbf{v} = \langle 0 - (-3), 0 - 4 \rangle = \langle 3, -4 \rangle \).
3Step 3: Calculate Magnitude of \( \mathbf{u} \)
Magnitude of a vector \( \langle a, b \rangle \) is calculated as \( \sqrt{a^2 + b^2} \). For \( \mathbf{u} = \langle 0,0 \rangle \), the magnitude is \( \|\mathbf{u}\| = \sqrt{0^2 + 0^2} = 0 \).
4Step 4: Calculate Magnitude of \( \mathbf{v} \)
Similarly, calculate the magnitude of \( \mathbf{v} = \langle -3,4 \rangle \) using the formula \( \sqrt{a^2 + b^2} \). The magnitude is \( \|\mathbf{v}\| = \sqrt{(-3)^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5 \).
Key Concepts
Vector AdditionVector SubtractionVector MagnitudeVectors in Mathematics
Vector Addition
Vector addition is the process of combining two vectors to create a new vector. You simply add the corresponding components of the vectors. If you have two vectors, say \( \mathbf{u} = \langle u_1, u_2 \rangle \) and \( \mathbf{v} = \langle v_1, v_2 \rangle \), their sum is:
- \( \mathbf{u} + \mathbf{v} = \langle u_1 + v_1, u_2 + v_2 \rangle \)
- Given \( \mathbf{u} = \langle 0,0 \rangle \) and \( \mathbf{v} = \langle -3,4 \rangle \), the sum \( \mathbf{u} + \mathbf{v} \) becomes \( \langle 0 + (-3), 0 + 4 \rangle = \langle -3, 4 \rangle \).
Vector Subtraction
Vector subtraction is similar to vector addition but involves taking away one vector from another. For vectors \( \mathbf{u} = \langle u_1, u_2 \rangle \) and \( \mathbf{v} = \langle v_1, v_2 \rangle \), their difference is:
- \( \mathbf{u} - \mathbf{v} = \langle u_1 - v_1, u_2 - v_2 \rangle \)
- For \( \mathbf{u} = \langle 0,0 \rangle \) and \( \mathbf{v} = \langle -3,4 \rangle \), the difference, \( \mathbf{u} - \mathbf{v} \), results in \( \langle 0 - (-3), 0 - 4 \rangle = \langle 3, -4 \rangle \).
Vector Magnitude
The magnitude of a vector is one of its key characteristics and reflects the vector's length. Mathematically, for a vector \( \mathbf{a} = \langle a_1, a_2 \rangle \), its magnitude \( \|\mathbf{a}\| \) is calculated using the formula:
- \( \|\mathbf{a}\| = \sqrt{a_1^2 + a_2^2} \)
- For \( \mathbf{u} = \langle 0,0 \rangle \), the magnitude is \( \|\mathbf{u}\| = \sqrt{0^2 + 0^2} = 0 \).
- The magnitude is \( \|\mathbf{v}\| = \sqrt{(-3)^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5 \).
Vectors in Mathematics
Vectors are essential tools in mathematics, helpful in expressing quantities with both direction and magnitude. Unlike simple numbers, vectors offer complex data, commonly displayed as ordered pairs or triplets. **Essentials of Understanding Vectors:**
- Vectors are denoted in component form: \( \langle a, b \rangle \).
- They are visualized as arrows with direction and length, where length corresponds to magnitude.
- Vectors are widely used in physics, engineering, and graphics.
Other exercises in this chapter
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