Problem 10
Question
Find the limit. $$\lim _{x \rightarrow-\infty} \frac{x^{2}+2}{x^{3}+x+1}$$
Step-by-Step Solution
Verified Answer
The limit is 0.
1Step 1: Identify the Dominant Terms
When considering the limit as \( x \to -\infty \), we need to identify the dominant terms in both the numerator and the denominator. For the numerator \( x^2 + 2 \), the dominant term is \( x^2 \). For the denominator \( x^3 + x + 1 \), the dominant term is \( x^3 \).
2Step 2: Rewrite the Expression with Dominant Terms
Rewrite the original expression \( \frac{x^2 + 2}{x^3 + x + 1} \), focusing on the dominant terms identified earlier. This gives us the simplified expression \( \frac{x^2}{x^3} \).
3Step 3: Simplify the Expression
Simplify \( \frac{x^2}{x^3} \) by canceling out common powers of \( x \). The expression simplifies to \( \frac{1}{x} \).
4Step 4: Evaluate the Simplified Limit
Determine the limit of the simplified expression \( \frac{1}{x} \) as \( x \to -\infty \). As \( x \) becomes very large negatively, \( \frac{1}{x} \) approaches 0.
Key Concepts
Dominant TermsSimplifying ExpressionsEvaluating Limits
Dominant Terms
When evaluating limits, especially as the variable approaches very large numbers or infinity, identifying the dominant terms becomes crucial. In an expression like \( \frac{x^2 + 2}{x^3 + x + 1} \), dominant terms are the ones that grow fastest as \( x \) approaches infinity or negative infinity.
- For the numerator \( x^2 + 2 \), the dominant term is \( x^2 \) because \( x^2 \) will grow much larger than the constant 2 as \( x \) increases in magnitude.
- In the denominator \( x^3 + x + 1 \), the dominant term is \( x^3 \) since it grows faster than both \( x \) and the constant 1.
Simplifying Expressions
Simplifying expressions, especially when dealing with limits, is all about making complex expressions easier to work with by keeping only the essential parts. Once we've identified the dominant terms, the next step is restructuring the expression while keeping the dominant terms at the forefront.
To simplify \( \frac{x^2 + 2}{x^3 + x + 1} \):
To simplify \( \frac{x^2 + 2}{x^3 + x + 1} \):
- Focus on \( \frac{x^2}{x^3} \), as these are the dominant terms both in the numerator and the denominator.
- The expression simplifies to \( \frac{1}{x} \) after canceling the common term \( x^2 \) from both the top and bottom, transforming it into a much simpler form.
Evaluating Limits
Once the expression is simplified, evaluating the limit becomes straightforward. The simplified form of the expression \( \frac{1}{x} \) is now ready for limit evaluation as \( x \to -\infty \).
Here’s how you evaluate:
Here’s how you evaluate:
- As \( x \to -\infty \), the denominator \( x \) becomes very large negatively, meaning \( \frac{1}{x} \) approaches zero.
- The negative sign indicates the direction of infinity, but since \( \frac{1}{x} \) only depends on approaching large magnitudes, the ultimate result remains zero.
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