Problem 10
Question
Find the inverse of the matrix if it exists. $$\left[\begin{array}{ll} 3 & 4 \\ 7 & 9 \end{array}\right]$$
Step-by-Step Solution
Verified Answer
The inverse of the matrix is \(\begin{bmatrix} -9 & 4 \\ 7 & -3 \end{bmatrix}\).
1Step 1: Check if the Matrix is Invertible
First, we need to check if the matrix is invertible by calculating its determinant. For a 2x2 matrix \(\begin{bmatrix} a & b \ c & d \end{bmatrix}\), the determinant is given by \(ad - bc\). For the matrix \(\begin{bmatrix} 3 & 4 \ 7 & 9 \end{bmatrix}\), the determinant is calculated as follows: \(3 \cdot 9 - 4 \cdot 7 = 27 - 28 = -1\). Since the determinant is not zero, the matrix is invertible.
2Step 2: Find the Adjugate of the Matrix
The next step is to find the adjugate (adjoint) of the matrix. For a 2x2 matrix \(\begin{bmatrix} a & b \ c & d \end{bmatrix}\), the adjugate is \(\begin{bmatrix} d & -b \ -c & a \end{bmatrix}\). Thus, the adjugate of \(\begin{bmatrix} 3 & 4 \ 7 & 9 \end{bmatrix}\) is \(\begin{bmatrix} 9 & -4 \ -7 & 3 \end{bmatrix}\).
3Step 3: Calculate the Inverse of the Matrix
To find the inverse of a matrix, we divide the adjugate by the determinant. The formula is: \[ A^{-1} = \frac{1}{\text{det}} \begin{bmatrix} d & -b \ -c & a \end{bmatrix} \] Therefore, the inverse of \(\begin{bmatrix} 3 & 4 \ 7 & 9 \end{bmatrix}\) is \[ \frac{1}{-1} \begin{bmatrix} 9 & -4 \ -7 & 3 \end{bmatrix} = \begin{bmatrix} -9 & 4 \ 7 & -3 \end{bmatrix} \]. Thus, the inverse is \(\begin{bmatrix} -9 & 4 \ 7 & -3 \end{bmatrix}\).
Key Concepts
Determinant of a MatrixAdjugate of a MatrixInvertible Matrix
Determinant of a Matrix
The determinant of a matrix is a special number that can be calculated from a square matrix. It is vital in determining whether a matrix is invertible or not. For a 2x2 matrix, \[ \begin{bmatrix} a & b \ c & d \end{bmatrix} \], the determinant is calculated as \( ad - bc \).
- If the determinant is zero, the matrix is not invertible and doesn't have an inverse.
- If the determinant is non-zero, the matrix is invertible, and we can find its inverse.
Adjugate of a Matrix
The adjugate of a matrix, sometimes called the adjoint, is crucial when calculating the inverse of a matrix. For a 2x2 matrix, \[ \begin{bmatrix} a & b \ c & d \end{bmatrix} \], the adjugate is formed by swapping the positions of \( a \) and \( d \), and changing the signs of \( b \) and \( c \). This results in the matrix: \[ \begin{bmatrix} d & -b \ -c & a \end{bmatrix} \]. Applying this to our matrix \[ \begin{bmatrix} 3 & 4 \ 7 & 9 \end{bmatrix} \], we swap \( 3 \) and \( 9 \), and change the signs for \( 4 \) and \( 7 \), giving us the adjugate matrix: \[ \begin{bmatrix} 9 & -4 \ -7 & 3 \end{bmatrix} \]. The adjugate is an essential step before computing the inverse, as we'll divide this matrix by the determinant in the next step.
Invertible Matrix
An invertible matrix, also known as a nonsingular or non-degenerate matrix, is one that has an inverse. For a matrix to be invertible, its determinant must be non-zero. The inverse of a matrix is the matrix that, when multiplied with the original matrix, yields the identity matrix. The identity matrix for a 2x2 matrix looks like \[ \begin{bmatrix} 1 & 0 \ 0 & 1 \end{bmatrix} \]. To find the inverse of an invertible matrix \[ \begin{bmatrix} a & b \ c & d \end{bmatrix} \], we use the formula: \[ A^{-1} = \frac{1}{\text{det}} \begin{bmatrix} d & -b \ -c & a \end{bmatrix} \]. For our matrix \[ \begin{bmatrix} 3 & 4 \ 7 & 9 \end{bmatrix} \], with a determinant of \(-1\), its inverse is calculated as:\[ \frac{1}{-1} \begin{bmatrix} 9 & -4 \ -7 & 3 \end{bmatrix} = \begin{bmatrix} -9 & 4 \ 7 & -3 \end{bmatrix} \]. The resulting inverse matrix can be verified by multiplying it with the original matrix to see if the identity matrix is obtained, ensuring correctness of our inversion.
Other exercises in this chapter
Problem 9
Perform the matrix operation, or if it is impossible, explain why. $$3\left[\begin{array}{rr} 1 & 2 \\ 4 & -1 \\ 1 & 0 \end{array}\right]$$
View solution Problem 9
Use back-substitution to solve the triangular system. $$\left\\{\begin{aligned} x+2 y+z &=7 \\ -y+3 z &=9 \\ 2 z &=6 \end{aligned}\right.$$
View solution Problem 10
Graph the inequality. $$3 x+4 y+12>0$$
View solution Problem 10
Use the elimination method to find all solutions of the system of equations. $$\left\\{\begin{array}{l} 3 x^{2}+4 y=17 \\ 2 x^{2}+5 y=2 \end{array}\right.$$
View solution