Problem 10
Question
Find a polynomial function \(P(x)\) of degree 3 with real coefficients that satisfies the given conditions. Do not use a calculator. Zeros of \(2,5,\) and \(-3 ; \quad P(1)=-4\)
Step-by-Step Solution
Verified Answer
The polynomial is \( P(x) = -\frac{1}{4}x^3 + x^2 + \frac{11}{4}x - \frac{15}{2} \).
1Step 1: Express the Polynomial in Factored Form
Since the given polynomial has zeros at 2, 5, and -3, we know that it can be written in the factored form: \( P(x) = a(x-2)(x-5)(x+3) \), where \( a \) is a constant to be determined.
2Step 2: Use Given Point to Find 'a'
We know from the problem that \( P(1) = -4 \). Substitute 1 into the polynomial: \( -4 = a(1-2)(1-5)(1+3) \). This simplifies to \( -4 = a(-1)(-4)(4) \).
3Step 3: Solve for 'a'
Calculate the expression: \(-4 = 16a\). Divide both sides by 16 to find \( a \): \( a = \frac{-4}{16} = -\frac{1}{4} \).
4Step 4: Write the Polynomial in Standard Form
Substitute \( a = -\frac{1}{4} \) back into the polynomial: \( P(x) = -\frac{1}{4}(x-2)(x-5)(x+3) \). Expand the expression to its standard form, combining terms and simplifying: First, expand \((x-2)(x-5)\): \\((x-2)(x-5) = x^2 - 5x - 2x + 10 = x^2 - 7x + 10\).Next, multiply by \((x+3)\): \[ (x^2 - 7x + 10)(x + 3) = x^3 + 3x^2 - 7x^2 - 21x + 10x + 30 = x^3 - 4x^2 - 11x + 30 \]Now multiply by \(-\frac{1}{4}\) as determined earlier: \[ P(x) = -\frac{1}{4}(x^3 - 4x^2 - 11x + 30) = -\frac{1}{4}x^3 + x^2 + \frac{11}{4}x - \frac{30}{4} \].Simplify further: \[ P(x) = -\frac{1}{4}x^3 + x^2 + \frac{11}{4}x - \frac{15}{2} \].
Key Concepts
Factored FormPolynomial RootsStandard Form
Factored Form
The factored form of a polynomial is a way of expressing the polynomial as a product of its factors. In the case of the polynomial function given in the exercise, the zeros or roots were provided: 2, 5, and -3. These zeros indicate where the polynomial function intersects the x-axis. By using these zeros, the polynomial can be expressed in the factored form as:
- For the zero at 2, the factor is \(x - 2\).
- For the zero at 5, the factor is \(x - 5\).
- For the zero at -3, the factor is \(x + 3\).
Polynomial Roots
The roots or zeros of a polynomial are the values of \(x\) that make the polynomial equal to zero. These are critical because they reveal where the graph of the polynomial function crosses the x-axis.Given the zeros 2, 5, and -3, these are the solutions to the equations:
To find the complete polynomial function, it is important to express it in terms of these roots, often through the factored form. Consequently, the polynomial can be expressed as a product of these factors multiplied by a constant.
In the exercise, the next step was to find the value of \(a\) using a given condition, \(P(1) = -4\). This helps in customizing the polynomial to fit specific conditions.
- \(x - 2 = 0\)
- \(x - 5 = 0\)
- \(x + 3 = 0\)
To find the complete polynomial function, it is important to express it in terms of these roots, often through the factored form. Consequently, the polynomial can be expressed as a product of these factors multiplied by a constant.
In the exercise, the next step was to find the value of \(a\) using a given condition, \(P(1) = -4\). This helps in customizing the polynomial to fit specific conditions.
Standard Form
The standard form of a polynomial is a way of writing it as a sum rather than as a product. It is the expanded form of the polynomial that lists all terms in descending order of power.From the factored form \(P(x) = -\frac{1}{4}(x-2)(x-5)(x+3)\), we expanded it to find the standard form. Expanding means carrying out the multiplication:
- First, calculate the multiplication of two factors, such as \((x-2)(x-5)\) to get \((x^2 - 7x + 10)\).
- Next, multiply the result by \((x+3)\) to obtain \((x^3 - 4x^2 - 11x + 30)\).
- Finally, multiply by the constant \(-\frac{1}{4}\) to achieve \(-\frac{1}{4}x^3 + x^2 + \frac{11}{4}x - \frac{15}{2}\).
Other exercises in this chapter
Problem 9
Find all real solutions. Do not use a calculator. $$12 x^{3}=17 x^{2}+5 x$$
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Describe the end behavior of the graph of each function. Do not use a calculator. $$P(x)=-\sqrt{7} x^{3}-4 x^{2}+2 x-1$$
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Use the intermediate value theorem to show that each function has a real zero between the two numbers given. Then, use a calculator to approximate the zero to t
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Find all real solutions. Do not use a calculator. $$3 x^{3}+3 x=10 x^{2}$$
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