Problem 10
Question
Exercises \(7-10:\) Find the formula for a linear function \(f\) that models the data in the table exactly. $$ \begin{array}{rrrr} x & 15 & 30 & 45 \\ f(x) & 40 & 30 & 20 \end{array} $$
Step-by-Step Solution
Verified Answer
The linear function is \( f(x) = -\frac{2}{3}x + 50 \).
1Step 1: Identify the form of a linear function
A linear function can be written in the form \( f(x) = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept.
2Step 2: Calculate the slope (m)
To find the slope \( m \), use the formula \( m = \frac{f(x_2) - f(x_1)}{x_2 - x_1} \). Let's choose two points from the table, say \((15, 40)\) and \((30, 30)\). Plug these into the slope formula:\[m = \frac{30 - 40}{30 - 15} = \frac{-10}{15} = -\frac{2}{3}\]
3Step 3: Calculate the y-intercept (b)
We can find the y-intercept \( b \) using one of the points and the slope we found. Let's use point \((15, 40)\). Substitute \( m = -\frac{2}{3} \), \( x = 15 \), and \( f(x) = 40 \) into the linear equation:\[40 = -\frac{2}{3} \cdot 15 + b\]Solve for \( b \):\[40 = -10 + b \b = 40 + 10 = 50\]
4Step 4: Write the linear function
Substitute the slope \( m = -\frac{2}{3} \) and the y-intercept \( b = 50 \) into the linear equation:\( f(x) = -\frac{2}{3}x + 50\)
5Step 5: Verify the linear function with remaining data points
Check the function \( f(x) = -\frac{2}{3}x + 50 \) with the other points from the table to ensure it fits all data:1. For \( x=45, f(x) = -\frac{2}{3} \cdot 45 + 50 = -30 + 50 = 20 \) which matches the table value.Confirmation means the function is correct.
Key Concepts
Slope CalculationY-InterceptLinear Equation FormData Modeling
Slope Calculation
Slope is an important part of any linear equation. It's what tells us how steep a line is; imagine it's like the "tilt" of the line. To find the slope, mathematical language uses the letter \( m \).
This tells us how much \( y \) (the vertical line) changes for every change in \( x \) (the horizontal line).
If you have two points, like \((x_1, y_1)\) and \((x_2, y_2)\), you can find the slope with this easy formula:
This tells us how much \( y \) (the vertical line) changes for every change in \( x \) (the horizontal line).
If you have two points, like \((x_1, y_1)\) and \((x_2, y_2)\), you can find the slope with this easy formula:
- \( m = \frac{f(x_2) - f(x_1)}{x_2 - x_1} \)
- \( m = \frac{30 - 40}{30 - 15} = -\frac{10}{15} = -\frac{2}{3} \)
Y-Intercept
The y-intercept is where our line crosses the y-axis. Think of it as the starting point of a line when \( x \) is zero.
In a linear equation \( f(x) = mx + b \), \( b \) is the y-intercept. It's like the starting value of the line before it starts to "tilt" by the amount of the slope.
To find \( b \), use one of the points from your data and the slope you calculated.
For example, with \((15, 40)\) and using the slope \(-\frac{2}{3}\), plug into the equation:
This means the line starts at a value of 50 on the y-axis.
In a linear equation \( f(x) = mx + b \), \( b \) is the y-intercept. It's like the starting value of the line before it starts to "tilt" by the amount of the slope.
To find \( b \), use one of the points from your data and the slope you calculated.
For example, with \((15, 40)\) and using the slope \(-\frac{2}{3}\), plug into the equation:
- \( 40 = -\frac{2}{3} \cdot 15 + b \)
- \( 40 = -10 + b \)
This means the line starts at a value of 50 on the y-axis.
Linear Equation Form
Now that we have both the slope and the y-intercept, we can form the linear equation. A linear equation models the relationship between two variables with a straight line.
It's written as:
Linear equations are simple but powerful as they precisely describe data with straight lines.
It's written as:
- \( f(x) = mx + b \)
- \( f(x) = -\frac{2}{3}x + 50 \)
Linear equations are simple but powerful as they precisely describe data with straight lines.
Data Modeling
Data modeling with a linear function involves using math to describe real-world data with an equation
By identifying patterns in the data, we can use a linear function to predict, explain, or understand relationships.
The linear equation we formed, \( f(x) = -\frac{2}{3}x + 50 \), professionally models the data from the table.
In this context, it tells us that as \( x \) increases by a certain amount, \( f(x) \) will decrease consistently based on the slope.
You can test this model by checking if the outcome matches other data points. For example, with \( x = 45 \):
By identifying patterns in the data, we can use a linear function to predict, explain, or understand relationships.
The linear equation we formed, \( f(x) = -\frac{2}{3}x + 50 \), professionally models the data from the table.
In this context, it tells us that as \( x \) increases by a certain amount, \( f(x) \) will decrease consistently based on the slope.
You can test this model by checking if the outcome matches other data points. For example, with \( x = 45 \):
- Calculate \( f(x) = -\frac{2}{3} \times 45 + 50 \)
- The answer is 20, which matches the given table, confirming the accuracy
Other exercises in this chapter
Problem 10
Determine whether the equation is linear or nonlinear by trying to write it in the form ax \(+b=0\) $$ 4 x^{3}-7=0 $$
View solution Problem 10
Solve the inequality symbolically. Express the solution set in set-builder or interval notation. $$ -4 x-3
View solution Problem 11
Graph by hand. (a) Find the \(x\) -intercept. (b) Determine where the graph is increasing and where it is decreasing. $$ y=|2 x-3| $$
View solution Problem 11
Determine whether the equation is linear or nonlinear by trying to write it in the form ax \(+b=0\) $$ 7 x-5=3(x-8) $$
View solution