Problem 10
Question
Exer. 1-40: Solve the inequality, and express the solutions in terms of intervals whenever possible. $$ x(3 x-1) \leq 4 $$
Step-by-Step Solution
Verified Answer
The solution is \([-1, \frac{4}{3}]\).
1Step 1: Expand the Inequality
Start by expanding the left side of the inequality. The inequality is originally given as \(x(3x-1) \leq 4\). Distribute the \(x\) through the parenthesis to get \(3x^2 - x \leq 4\).
2Step 2: Rearrange to Standard Quadratic Form
Rearrange the inequality into standard quadratic form \(ax^2 + bx + c \leq 0\). Subtract 4 from both sides to obtain \(3x^2 - x - 4 \leq 0\).
3Step 3: Find Roots of the Quadratic Equation
To solve the inequality \(3x^2 - x - 4 = 0\), use the quadratic formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\). For this equation, \(a=3\), \(b=-1\), and \(c=-4\). Calculate the discriminant \(b^2 - 4ac = (-1)^2 - 4(3)(-4) = 1 + 48 = 49\). The square root of 49 is 7.
4Step 4: Calculate the Roots
Substitute the values into the quadratic formula:\[x = \frac{-(-1) \pm 7}{2 \cdot 3}\]This simplifies to:\[x = \frac{1 \pm 7}{6}\]The two roots are \(x = \frac{8}{6} = \frac{4}{3}\) and \(x = \frac{-6}{6} = -1\).
5Step 5: Test Intervals for Solutions
Since the inequality is \(3x^2 - x - 4 \leq 0\), we are looking for intervals where the parabola is non-positive. The roots divide the number line into intervals: \((-\infty, -1)\), \([-1, \frac{4}{3}]\), and \((\frac{4}{3}, \infty)\). Choose test points from each interval to determine where the inequality holds:- For \(x = -2 \in (-\infty, -1)\), \(3(-2)^2 - (-2) - 4 = 12 + 2 - 4 = 10\) (not \(\leq 0\)).- For \(x = 0 \in [-1, \frac{4}{3}]\), \(3(0)^2 - 0 - 4 = -4\) (\(\leq 0\)).- For \(x = 2 \in (\frac{4}{3}, \infty)\), \(3(2)^2 - 2 - 4 = 12 - 2 - 4 = 6\) (not \(\leq 0\)).
6Step 6: Write the Solution as an Interval
Based on the test results, the solution to the inequality is within the interval \([-1, \frac{4}{3}]\) where the inequality \(3x^2 - x - 4 \leq 0\) holds true.
Key Concepts
Quadratic EquationsInterval NotationQuadratic Formula
Quadratic Equations
Quadratic equations are equations of the form \(ax^2 + bx + c = 0\), where \(a\), \(b\), and \(c\) are constants, and \(x\) represents an unknown variable. The graph of a quadratic equation is a parabola. This means it can either open upwards or downwards, depending on the sign of \(a\):
- If \(a > 0\), the parabola opens upwards.
- If \(a < 0\), it opens downwards.
Interval Notation
Interval notation is a convenient way to describe a range of numbers on the number line. It is especially useful in expressing the solutions of inequalities. In the context of solving quadratic inequalities, after finding the roots, we split the number line into intervals to test which satisfy the inequality.For example, the solution of the inequality \(3x^2 - x - 4 \leq 0\) in the form of interval notation is
- \([-1, \frac{4}{3}]\)
Quadratic Formula
The quadratic formula is a powerful tool for solving quadratic equations. It provides the solutions or "roots" of any quadratic equation in the form \(ax^2 + bx + c = 0\) and is given by:\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]This formula comes in handy when the quadratic equation cannot be factored easily. It automatically produces the roots by substituting the values of \(a\), \(b\), and \(c\). In the solution provided, the quadratic formula was used to determine the roots \(x = -1\) and \(x = \frac{4}{3}\), which help in solving the inequality by identifying critical points where the function changes its sign.The term under the square root sign, \(b^2 - 4ac\), is called the discriminant:
- If it's positive, there are two distinct real roots.
- If zero, there's exactly one real root.
- If negative, the roots are complex and not real.
Other exercises in this chapter
Problem 10
A city government has approved the construction of an \(\$ 800\) million sports arena. Up to \(\$ 480\) million will be raised by selling bonds that pay simple
View solution Problem 10
Solve the equation. $$1.5 x-0.7=0.4(3-5 x)$$
View solution Problem 10
Exer. 3-12: Express the inequality as an interval, and sketch its graph. $$ -3
View solution Problem 10
Exer. 1-50: Solve the equation. $$ 15 x^{5}-20 x^{4}=6 x^{3}-8 x^{2} $$
View solution