Problem 10
Question
Differentiate the functions given in Problems with respect to the independent variable.$$ h(t)=\frac{1}{2} t^{2}-3 t+2 $$
Step-by-Step Solution
Verified Answer
The derivative of the function \( h(t) \) is \( h'(t) = t - 3 \).
1Step 1: Identify the Function to Differentiate
We are given the function \( h(t) = \frac{1}{2} t^2 - 3t + 2 \). Our task is to find its derivative with respect to \( t \).
2Step 2: Apply the Power Rule
The power rule states that the derivative of \( t^n \) is \( nt^{n-1} \). Apply this to each term separately. The derivative of \( \frac{1}{2}t^2 \) is \( 2 \times \frac{1}{2}t^{2-1} = t \).
3Step 3: Differentiate the Linear Term
For the linear term \(-3t\), the derivative is simply \(-3\). This follows from applying the power rule where \( n = 1 \).
4Step 4: Differentiate the Constant Term
The derivative of a constant like \( 2 \) is \( 0 \). Constants drop out when differentiating as their rate of change is zero.
5Step 5: Combine the Derivatives
Now combine all the derivatives: the derivative of the function \( h(t) \) is \( h'(t) = t - 3 + 0 \), which simplifies to \( h'(t) = t - 3 \).
Key Concepts
Power RuleDerivative of PolynomialDifferentiation Steps
Power Rule
The power rule is a fundamental tool in calculus for finding derivatives. It states: if you have a term in the form of \( t^n \), then the derivative of this term is \( nt^{n-1} \). This is particularly useful when dealing with polynomials, where each term can be independently differentiated using this rule. For example, when applying the power rule to the term \( \frac{1}{2}t^2 \), you treat \( n \) as \( 2 \). This means:
- Multiply the exponent by the coefficient: \( 2 \times \frac{1}{2} = 1 \).
- Decrease the exponent by 1: \( t^{2-1} = t^1 \).
Derivative of Polynomial
A polynomial is a sum of terms, each consisting of a coefficient and a variable raised to an exponent. Differentiating a polynomial is straightforward, as we can apply the power rule to each term. Consider a typical polynomial expression, such as \( h(t) = \frac{1}{2} t^2 - 3t + 2 \).
- First, apply the power rule to \( \frac{1}{2}t^2 \), giving \( t \) as its derivative.
- Next, consider the term \(-3t\). Using the power rule where the exponent is \( 1 \), it reduces to simply the coefficient: \(-3\).
- The constant \(2\) has a derivative of \(0\), as constants do not change with respect to the variable.
Differentiation Steps
The process of differentiation involves applying certain rules to find the rate of change of a function. Here's a structured approach to differentiate a polynomial like \( h(t) = \frac{1}{2} t^2 - 3t + 2 \):
- **Identify the function**: Start with the function you need to differentiate.
- **Apply the power rule**: Use it on terms with variables. The term \( \frac{1}{2}t^2 \) differentiates to \( t \).
- **Differentiate linear terms**: For a term like \(-3t\), the derivative is the coefficient \(-3\).
- **Handle constants**: Any constant term, such as \(2\), has a derivative of \(0\).
- **Combine the results**: Sum up all the derived terms to get the complete derivative, which for this function is \( t - 3 \).
Other exercises in this chapter
Problem 10
Differentiate the functions in Problems 1-52 with respect to the independent variable. $$ f(x)=2 x e^{-3 x} $$
View solution Problem 10
Use the product rule to find the derivative with respect to the independent variable. $$ f(x)=\left(4-2 x^{2}\right)^{2} $$
View solution Problem 11
Approximate \(f(x)\) at a by the linear approximation $$L(x)=f(a)+f^{\prime}(a)(x-a)$$ $$ f(x)=\frac{1}{1+x} \text { at } a=0 $$
View solution Problem 11
Find } c \text { so that } f^{\prime}(c)=0 . $$ $$ f(x)=(x-2)^{2} $$
View solution