Problem 10
Question
Determine the distance between the given points. \((a, b)\) and \((b, a)\)
Step-by-Step Solution
Verified Answer
The distance is \\( \sqrt{2} \times |b-a| \\).
1Step 1: Recognize the Distance Formula
The distance between two points \( (x_1, y_1) \) and \( (x_2, y_2) \) in the coordinate plane can be found using the distance formula: \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \]
2Step 2: Identify the Coordinates
Identify the coordinates for the points \( (a, b) \) and \( (b, a) \). Here, \( x_1 = a, y_1 = b \) and \( x_2 = b, y_2 = a \).
3Step 3: Substitute the Coordinates into the Distance Formula
Substitute the identified coordinates into the distance formula: \[ d = \sqrt{(b - a)^2 + (a - b)^2} \]
4Step 4: Simplify the Expression
Notice that \( (b-a)^2 = (a-b)^2 \), since squaring negates signs. Therefore, simplify:\[ d = \sqrt{2(b-a)^2} \] Further simplify: \d = \sqrt{2} \times \lvert b-a \rvert \.
5Step 5: Final Calculation
The final distance can be represented as:\[ d = \sqrt{2} \times |b-a| \]
Key Concepts
Coordinate GeometryDistance Between PointsSquare Root Simplification
Coordinate Geometry
Coordinate geometry, also known as analytic geometry, is a branch of mathematics that uses a coordinate system to describe geometric shapes. It involves using coordinates on a plane to define the position of points and the relationships between them. In coordinate geometry, any point can be defined using an ordered pair of numbers, usually written as \(x, y\). These coordinates tell us where the point lies on the Cartesian plane.
When working with coordinate geometry, we can explore and solve various geometric problems by using algebraic methods. This field combines geometry and algebra, providing a way to study the properties and relationships of geometric figures through equations. It utilizes the x-axis and y-axis to plot points and visualize distances, lines, and shapes. This is especially useful for calculating distances between points, such as in the distance problem you're working on.
When working with coordinate geometry, we can explore and solve various geometric problems by using algebraic methods. This field combines geometry and algebra, providing a way to study the properties and relationships of geometric figures through equations. It utilizes the x-axis and y-axis to plot points and visualize distances, lines, and shapes. This is especially useful for calculating distances between points, such as in the distance problem you're working on.
Distance Between Points
Calculating the distance between two points in a coordinate plane involves understanding and applying a specific formula. The distance formula is derived from the Pythagorean Theorem and it helps to find the length of the line segment connecting two points in a coordinate system.
For any two points, say \(x_1, y_1\) and \(x_2, y_2\), the distance \(d\) can be calculated using the formula:
In your problem, the points are \(a, b\) and \(b, a\). Substitute these into the formula to find the distance, which simplifies variously through understanding symmetry and properties of the squaring operation.
For any two points, say \(x_1, y_1\) and \(x_2, y_2\), the distance \(d\) can be calculated using the formula:
- \(d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\)
In your problem, the points are \(a, b\) and \(b, a\). Substitute these into the formula to find the distance, which simplifies variously through understanding symmetry and properties of the squaring operation.
Square Root Simplification
Simplifying square roots involves finding the simplest form of a square root expression. During the distance calculation, you may encounter the need to simplify the square root, which makes it easier to interpret or calculate the answer. This process involves identifying perfect squares within the expression and simplifying them.
Taking the expression \(\sqrt{2(b-a)^2}\), the simplification occurs by recognizing that the expression inside the square root simplifies. Since \((b-a)^2\) means squaring the difference, it doesn't matter whether it's \(b-a\) or \(a-b\) because squaring makes it positive. Thus, \((b-a)^2 \) and \(2(b-a)^2\) helps extract the square root partly which gives:
Taking the expression \(\sqrt{2(b-a)^2}\), the simplification occurs by recognizing that the expression inside the square root simplifies. Since \((b-a)^2\) means squaring the difference, it doesn't matter whether it's \(b-a\) or \(a-b\) because squaring makes it positive. Thus, \((b-a)^2 \) and \(2(b-a)^2\) helps extract the square root partly which gives:
- \(\sqrt{2} \times |b-a|\)
Other exercises in this chapter
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