Problem 10
Question
Convert the following Kelvin temperatures to the Celsius and Fahrenheit scales: (a) the midday temperature at the surface of the moon \((400 \mathrm{K}) ;(\mathrm{b})\) temperature at the tops of the clouds in the atmosphere of Saturn \((95 \mathrm{K}) ;(\mathrm{c})\) the temperature at the center of the \(\operatorname{sun}\left(1.55 \times 10^{7} \mathrm{K}\right) .\)
Step-by-Step Solution
Verified Answer
(a) 126.85°C, 260.33°F; (b) -178.15°C, -288.67°F; (c) 1.54999728×10⁷°C, 2.789995104×10⁷°F.
1Step 1: Convert from Kelvin to Celsius
To convert a temperature from Kelvin (K) to Celsius (°C), use the formula: \[ °C = K - 273.15 \]. Let's apply this formula to the given temperatures: (a) 400 K, (b) 95 K, (c) 1.55 \times 10^7 K.(a) \[400 \, \mathrm{K} - 273.15 = 126.85 \, ^{\circ} \mathrm{C}\](b) \[95 \, \mathrm{K} - 273.15 = -178.15 \, ^{\circ} \mathrm{C}\](c) \[1.55 \times 10^7 \, \mathrm{K} - 273.15 = 1.54999728 \times 10^7 \, ^{\circ} \mathrm{C}\]
2Step 2: Convert from Celsius to Fahrenheit
To convert from Celsius (°C) to Fahrenheit (°F), use the formula: \[ °F = °C \times \frac{9}{5} + 32 \]. Apply this to the Celsius values found in Step 1:(a) \[126.85 \, ^{\circ} \mathrm{C} \times \frac{9}{5} + 32 = 260.33 \, ^{\circ} \mathrm{F} \](b) \[-178.15 \, ^{\circ} \mathrm{C} \times \frac{9}{5} + 32 = -288.67 \, ^{\circ} \mathrm{F} \](c) \[1.54999728 \times 10^7 \, ^{\circ} \mathrm{C} \times \frac{9}{5} + 32 = 2.789995104 \times 10^7 \, ^{\circ} \mathrm{F} \]
Key Concepts
Kelvin to CelsiusCelsius to FahrenheitTemperature Scales
Kelvin to Celsius
The Kelvin and Celsius temperature scales are both widely used in scientific contexts. The Kelvin scale is the absolute temperature scale and has its zero point at absolute zero. To convert a temperature from Kelvin to Celsius, you need to know a simple formula: \[ °C = K - 273.15 \]
- Subtract 273.15 from the Kelvin temperature to get the Celsius equivalent.
- This conversion is straightforward as both scales use the same size for their degrees.
- 400 K - 273.15 gives us 126.85 °C, equivalent to the moon's midday temperature.
- 95 K, representing the temperature at Saturn's cloud tops, becomes -178.15 °C.
- Finally, the extremely high temperature at the sun's center, 1.55 \times 10^7 K, converts to approximately 1.55 \times 10^7 °C.
Celsius to Fahrenheit
Once you have temperatures in Celsius, converting them to Fahrenheit involves another simple formula. Fahrenheit is often used in everyday settings, especially in the United States. The conversion formula between Celsius and Fahrenheit is: \[ °F = °C \times \frac{9}{5} + 32 \]
- To convert, multiply the Celsius value by \( \frac{9}{5} \) and then add 32 to the result.
- This formula reflects the different sizes of degrees and zero points in the two scales.
- 126.85 °C becomes approximately 260.33 °F for the lunar surface temperature.
- -178.15 °C converts to about -288.67 °F at Saturn's cloud tops.
- 1.55 \times 10^7 °C results in roughly 2.79 \times 10^7 °F for the sun's core.
Temperature Scales
To appreciate the conversions, it's crucial to understand the concept of temperature scales. Different scales are used depending on the context and geographic location:
- Kelvin: The Kelvin scale is used primarily in science, particularly for thermodynamic calculations. It starts at absolute zero, where all molecular movement stops.
- Celsius: Widely used in most parts of the world for everyday temperature measurement. It sets the freezing and boiling points of water at 0 °C and 100 °C, respectively.
- Fahrenheit: Used primarily in the United States for weather forecasts and other applications. It places the freezing point of water at 32 °F and the boiling point at 212 °F.
Other exercises in this chapter
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