Problem 10
Question
\(\bullet\) A negative charge of \(-0.550 \mu C\) exerts an upward 0.200 \(\mathrm{N}\) force on an unknown charge 0.300 \(\mathrm{m}\) directly below it. (a) What is the unknown charge (magnitude and sign)? (b) What are the magnitude and direction of the force that the unknown charge exerts on the - 0.550\(\mu \mathrm{C}\) charge?
Step-by-Step Solution
Verified Answer
(a) The unknown charge is approximately +1.21 × 10⁻⁵ C.
(b) The force is 0.200 N, directed downward.
1Step 1: Understand the given data
We are given that a negative charge \(-0.550 \mu C\) exerts a force of \(0.200 \mathrm{N}\) upward on another unknown charge 0.300 m directly below it. We need to find the magnitude and sign of the unknown charge.
2Step 2: Apply Coulomb’s Law to find the unknown charge
Coulomb's Law states that the force between two charges is \( F = k \frac{|q_1 q_2|}{r^2} \), where \( k = 8.99 \times 10^9 \, \mathrm{N \cdot m^2/C^2} \), \( q_1 \) and \( q_2 \) are the charges in question, and \( r \) is the distance between them. Given that the force \( F = 0.200 \, \mathrm{N} \) and the distance \( r = 0.300 \, \mathrm{m} \), we start by listing the known values. We know \( q_1 = -0.550 \times 10^{-6} \, \mathrm{C} \), so we solve for \( q_2 \): \[0.200 = 8.99 \times 10^9 \frac{|-0.550 \times 10^{-6} q_2|}{(0.300)^2}\]Solve for \( q_2 \) to find the magnitude of the unknown charge.
3Step 3: Calculate the unknown charge
Rearrange the equation to solve for \( q_2 \):\[|-0.550 \times 10^{-6} q_2| = \frac{0.200 \times (0.300)^2}{8.99 \times 10^9} \approx 6.66 \times 10^{-12}\]Then solving for \( q_2 \):\[|q_2| = \frac{6.66 \times 10^{-12}}{0.550 \times 10^{-6}} \approx 1.21 \times 10^{-5} \, \mathrm{C} \]The charge is positive because the force is upward, indicating repulsion with the negative charge.
4Step 4: Confirm the sign and find the direction of forces
Since the force is upward and the charge below is unknown, the force’s direction is due to repulsive interaction from a positive charge. Thus, the unknown charge is positive \(+ 1.21 \times 10^{-5} \mathrm{C}\).
5Step 5: Apply Newton's Third Law to find the force on the known charge
Newton's third law states that every action has an equal and opposite reaction. Thus, the force that the unknown charge \(q_2\) exerts on \(-0.550 \mu C\) is equal in magnitude and opposite in direction to the initial force \(0.200 \, \mathrm{N}\). So, the magnitude is also \(0.200 \, \mathrm{N}\) but directed downward.
Key Concepts
Electric ChargeForce InteractionNewton's Third Law
Electric Charge
Electric charge is a fundamental property of matter. It comes in two types: positive and negative.
- Electrons carry a negative charge, while protons carry a positive charge.
- Like charges repel each other, while opposite charges attract.
Force Interaction
When we discuss force interaction, we're talking about how two charges exert forces on each other due to their electric fields. Coulomb's Law quantifies this interaction. It states that the force between two charges is directly proportional to the product of the absolute values of the charges and inversely proportional to the square of the distance between them: \[F = k \frac{|q_1 q_2|}{r^2}\], where \(k\) is the Coulomb’s constant.
- It allows us to calculate the force between two point charges.
- The direction of force aligns with the principles of charge interaction: attraction or repulsion.
Newton's Third Law
Newton's Third Law of Motion is a cornerstone of classical mechanics. It states that for every action, there is an equal and opposite reaction.
In the context of our exercise, this law is applicable in the analysis of the force exchanging between the charges.
- When one charge exerts a force on another, the second charge exerts an equal and opposite force back on the first.
- This means if one charge is pushing up, the other is pushing down with the same force magnitude.
Other exercises in this chapter
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