Problem 10
Question
(a) What is the difference between adding a subscript 2 to the end of the formula for \(\mathrm{CO}\) to give \(\mathrm{CO}_{2}\) and adding a coefficient in front of the formula to give 2 CO? (b) Is the following chemical equation, as written, consistent with the law of conservation of mass? \(3 \mathrm{Mg}(\mathrm{OH})_{2}(\mathrm{~s})+2 \mathrm{H}_{3} \mathrm{PO}_{4}(a q) \longrightarrow \mathrm{Mg}_{3}\left(\mathrm{PO}_{4}\right)_{2}(s)+6 \mathrm{H}_{2} \mathrm{O}(l)\) Why or why not?
Step-by-Step Solution
Verified Answer
(a) Adding a subscript 2 to the end of the formula for \(\mathrm{CO}\) to give \(\mathrm{CO}_2\) changes the composition of the molecule, creating carbon dioxide. Adding a coefficient 2 in front of the formula to give \(2\mathrm{CO}\) means there are two molecules of carbon monoxide. (b) The given chemical equation is consistent with the law of conservation of mass, as the number of atoms of each element is equal on both sides of the equation.
1Step 1: Part (a) - Difference between adding a subscript and adding a coefficient
In a chemical formula, a subscript indicates the number of atoms of a specific element in a molecule, while a coefficient specifies the number of molecules involved in the reaction.
When a subscript is added to a chemical formula, such as adding a subscript 2 to the end of the formula for \(\mathrm{CO}\) to give \(\mathrm{CO}_2\), it changes the composition of the molecule. In this case, the molecule would now consist of one carbon atom and two oxygen atoms, forming carbon dioxide.
On the other hand, adding a coefficient in front of a chemical formula, such as adding 2 in front of the formula \(\mathrm{CO}\) to give \(2\mathrm{CO}\), signifies that there are two molecules of carbon monoxide, each consisting of one carbon atom and one oxygen atom.
2Step 2: Part (b) - Checking if the chemical equation is consistent with the law of conservation of mass
We can check if the given chemical equation is consistent with the law of conservation of mass by counting the number of atoms of each element on both sides of the equation and making sure they are equal.
The given chemical equation is: \[3 \mathrm{Mg(OH)_2(s)}+2 \mathrm{H_3PO_4(aq)} \longrightarrow \mathrm{Mg_3(PO_4)_2(s)}+6 \mathrm{H_2O(l)}\]
Let's count the atoms of each element on both sides of the equation:
Left-hand side of the equation:
- Mg: \(3\) (from \(\mathrm{Mg(OH)_2}\))
- O: \(6\) (from \(\mathrm{Mg(OH)_2}\))
- H: \(12\) (from \(\mathrm{Mg(OH)_2}\)) + \(6\) (from \(\mathrm{H_3PO_4}\)) = \(18\)
- P: \(2\) (from \(\mathrm{H_3PO_4}\))
Right-hand side of the equation:
- Mg: \(3\) (from \(\mathrm{Mg_3(PO_4)_2}\))
- O: \(8\) (from \(\mathrm{Mg_3(PO_4)_2}\)) + \(6\) (from \(\mathrm{H_2O}\)) = \(14\)
- H: \(12\) (from \(\mathrm{H_2O}\))
- P: \(2\) (from \(\mathrm{Mg_3(PO_4)_2}\))
Comparing the number of atoms of each element on both sides, we can see that they are equal. Therefore, the given chemical equation is consistent with the law of conservation of mass.
Key Concepts
Subscripts in ChemistryCoefficients in ReactionsConservation of Mass
Subscripts in Chemistry
In chemistry, subscripts are used to indicate the number of atoms of a particular element within a molecule. They are written as small numbers to the right and slightly below the chemical symbols in a formula. For example, in the molecule \( \text{CO}_2 \), the subscript 2 suggests that there are two oxygen atoms bonded with one carbon atom to form carbon dioxide.
This small number is crucial because it tells us the actual composition of the molecule, confirming what substances are present and in what proportion.
When the subscript is altered, it changes the nature of the molecule completely. For instance, \( \text{CO} \) (carbon monoxide) contains one carbon and one oxygen, while \( \text{CO}_2 \) indicates a different compound—carbon dioxide—due to the subscript.
This small number is crucial because it tells us the actual composition of the molecule, confirming what substances are present and in what proportion.
When the subscript is altered, it changes the nature of the molecule completely. For instance, \( \text{CO} \) (carbon monoxide) contains one carbon and one oxygen, while \( \text{CO}_2 \) indicates a different compound—carbon dioxide—due to the subscript.
- Subscripts are part of the molecular structure.
- They help determine the molecule's identity and properties.
Coefficients in Reactions
Coefficients in chemical reactions denote the number of molecules or moles involved in a reaction. They are written as regular-sized numbers in front of chemical formulas in an equation. For example, the equation \( 3 \text{H}_2 + \text{O}_2 \rightarrow 2 \text{H}_2\text{O} \) shows coefficients 3, 1 (implied), and 2 respectively.
The coefficient informs us about the ratio in which reactants combine and products form. It's vital for balancing chemical equations and ensuring that the equation adheres to the law of conservation of mass.
The coefficient informs us about the ratio in which reactants combine and products form. It's vital for balancing chemical equations and ensuring that the equation adheres to the law of conservation of mass.
- Coefficients are not part of the molecular structure; they belong to the reaction as a whole.
- They provide a means to balance the equation and reflect real-world conditions.
Conservation of Mass
The law of conservation of mass is a fundamental principle in chemistry, stating that mass in a closed system must remain constant over time. Consequently, in any chemical reaction, the mass of the reactants must equal the mass of the products.
This principle is crucial for writing and balancing chemical equations, ensuring that atoms are neither lost nor gained but simply rearranged.
This principle is crucial for writing and balancing chemical equations, ensuring that atoms are neither lost nor gained but simply rearranged.
- Mass is conserved in chemical reactions.
- Balancing equations respects this law by equalizing atom counts on both sides.
Other exercises in this chapter
Problem 9
(a) What scientific principle or law is used in the process of balancing chemical equations? (b) In balancing equations, why should you not change subscripts in
View solution Problem 11
Balance the following equations: (a) \(\mathrm{CO}(\mathrm{g})+\mathrm{O}_{2}(\mathrm{~g}) \longrightarrow \mathrm{CO}_{2}(\mathrm{~g})\) (b) \(\mathrm{N}_{2} \
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Balance the following equations: (a) \(\mathrm{Li}(s)+\mathrm{N}_{2}(g) \longrightarrow \mathrm{Li}_{3} \mathrm{~N}(s)\) (b) \(\mathrm{La}_{2} \mathrm{O}_{3}(s)
View solution Problem 13
Write balanced chemical equations to correspond to each of the following descriptions: (a) Solid calcium carbide, \(\mathrm{CaC}_{2}\), reacts with water to for
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