Problem 10
Question
(a) Find the second degree Taylor polynomial generated by sec \(x\) at \(x=0\). (b) Graph \(P_{2}(x)\) and sec \(x\) on the same set of axes.
Step-by-Step Solution
Verified Answer
The second degree Taylor polynomial generated by sec \(x\) at \(x=0\) is \(1 + 1/2 x^2\). To graph \(P_{2}(x)\) and sec \(x\), mark the point of x = 0 and draw the graphs of sec \(x\) and the polynomial.
1Step 1: Calculate the derivatives
Firstly, calculate the first and second derivative of sec x. The first derivative of sec x is \(sec(x)tan(x)\) and the second derivative is \(sec(x)(tan^2(x) + sec^2(x))\)
2Step 2: Evaluate at x = 0
Next, evaluate the function and its derivatives at x = 0. At x = 0, sec(0) = 1, \(sec(0)tan(0) = 0\) and \(sec(0)(tan^2(0) + sec^2(0)) = 1\)
3Step 3: Construct the Taylor polynomial
The second degree Taylor polynomial is given by \(f(0) + f'(0)(x - 0) + f''(0)(x - 0)^2/2 = 1 + 0 + 1/2 x^2 = 1 + 1/2 x^2\)
4Step 4: Graph the function and the polynomial
For part (b), the function sec x and the Taylor polynomial can be graphed on the same set of axes. Mark the point x = 0 on the x-axis, and draw the graphs of sec x and the polynomial.
Key Concepts
Secant FunctionSecond DerivativeGraphing Functions
Secant Function
The secant function, denoted as \( \sec x \), is one of the six fundamental trigonometric functions. It can be defined as the reciprocal of the cosine function. Thus, \( \sec x = \frac{1}{\cos x} \). This function has certain properties and values that are important in calculus, especially when finding derivatives for use in Taylor series.The function \( \sec x \) helps in studying angles and their relationships in triangles, often involved when working with periodic phenomena. For those learning calculus, understanding how \( \sec x \) behaves is critical for both derivative calculations and subsequent function approximation through Taylor Series.Key points to know about the secant function:
- The function \( \sec x \) is undefined wherever \( \cos x = 0 \). This leads to vertical asymptotes at odd multiples of \( \frac{\pi}{2} \).
- Its range is \(( -\infty, -1 ] \cup [ 1, \infty)\).
- When graphing, \( \sec x \) has a repeating pattern every \( 2\pi \), which means it's periodic like other trigonometric functions.
Second Derivative
The second derivative of a function provides important information about the concavity or curvature of the graph of the function. In calculus, the second derivative is fundamentally a measure of how the rate of change (expressed by the first derivative) itself changes.When specifically dealing with \( \sec x \), we first derive the first derivative which is \( \sec(x)\tan(x) \). The second derivative involves finding the derivative of this expression:\[ \frac{d}{dx}(\sec(x)\tan(x)) = \sec(x)(\tan^2(x) + \sec^2(x)) \]This derivative gives us the second term to use in forming the Taylor Series. Evaluating this at a point allows us to incorporate it into the polynomial. For \( x = 0 \):
- The first derivative evaluated at \( x = 0 \) is 0, as \( \tan(0) = 0 \).
- The second derivative evaluated at \( x = 0 \) becomes 1, since \( \sec(0) = 1 \) and \( \tan^2(0) + \sec^2(0) = 1 \).
Graphing Functions
Graphing functions serves as a crucial step for visual understanding of mathematical concepts. When we graph the second degree Taylor polynomial of \( \sec x \) alongside the actual function, it helps to see how well the approximation fits around the point of expansion.Here's how one approaches this process:
- Begin by marking the essential point of approximation, which is \( x = 0 \) in this case.
- The second degree Taylor polynomial derived is \( P_2(x) = 1 + \frac{1}{2}x^2 \). This polynomial is graphed along with the original \( \sec x \) function.
- At \( x = 0 \), both \( \sec x \) and the polynomial will meet since the Taylor polynomial is designed to reflect the value of the original function and its derivatives at \( x = 0 \).
- Pay attention to how the polynomial deviates as you move away from the point of approximation, showing the intervals where the approximation remains accurate.
Other exercises in this chapter
Problem 10
Determine whether the series converges or diverges. It is possible to solve Problems 4 through 19 without the Limit Comparison, Ratio, and Root Tests. \(\sum_{k
View solution Problem 10
Is it possible for a geometric series to converge conditionally? If it is possible, produce an example.
View solution Problem 11
Determine whether the series converges or diverges. It is possible to solve Problems 4 through 19 without the Limit Comparison, Ratio, and Root Tests. \(\sum_{k
View solution Problem 11
A hyena is loping down a straight path away from a stream. The hyena is \(6 \mathrm{~m}\) from the stream, moving at a rate of \(2 \mathrm{~m} / \mathrm{s}\) an
View solution