Problem 10
Question
7–14 A matrix is given. (a) Determine whether the matrix is in row-echelon form. (b) Determine whether the matrix is in reduced row-echelon form. (c) Write the system of equations for which the given matrix is the augmented matrix. $$\left[\begin{array}{rrrr}{1} & {0} & {-7} & {0} \\ {0} & {1} & {3} & {0} \\\ {0} & {0} & {0} & {1}\end{array}\right]$$
Step-by-Step Solution
Verified Answer
(a) Yes, the matrix is in row-echelon form. (b) No, it is not in reduced row-echelon form. (c) The system is inconsistent: \(x - 7z = 0\), \(y + 3z = 0\), \(0 = 1\).
1Step 1: Identify row-echelon form (REF) criteria
To be in row-echelon form, a matrix must meet the following conditions:
1. All nonzero rows appear above any rows of all zeros.
2. Each leading entry of a row is strictly to the right of the leading entry of the row above it.
3. All entries in a column below a leading entry are zero.
2Step 2: Check matrix against REF criteria
Examine the given matrix:\[\begin{bmatrix}1 & 0 & -7 & 0 \0 & 1 & 3 & 0 \0 & 0 & 0 & 1\end{bmatrix}\]- The first condition is satisfied as there are no zero rows above nonzero rows.- The leading entry in each row appears to the right of the leading entry in the row above it.- All entries below each leading entry are zero. Thus, the matrix is in row-echelon form.
3Step 3: Identify reduced row-echelon form (RREF) criteria
To be in reduced row-echelon form, a matrix must meet all REF criteria, and additionally:
1. Every leading entry is 1.
2. Each leading 1 is the only nonzero entry in its column.
4Step 4: Check matrix against RREF criteria
Examine the given matrix again:\[\begin{bmatrix}1 & 0 & -7 & 0 \0 & 1 & 3 & 0 \0 & 0 & 0 & 1\end{bmatrix}\]- Every leading entry is 1.- However, the second column has an additional nonzero entry (3) in the first row, meaning column 3 has a nonzero entry (-7) not associated with a leading entry 1. Thus, it does not satisfy the criteria for reduced row-echelon form.
5Step 5: Write the system of equations from the augmented matrix
To express the matrix as a system of equations, treat each row as an equation. The matrix is augmented, so the last column will be the constants on the right side of the equations.1. First row: \( 1x + 0y - 7z = 0 \) simplifies to \( x - 7z = 0 \).2. Second row: \( 0x + 1y + 3z = 0 \) simplifies to \( y + 3z = 0 \).3. Third row: \( 0x + 0y + 0z = 1 \) which is inconsistent. In general practice, you would recognize this indicates no solution.
Key Concepts
Row-Echelon FormReduced Row-Echelon FormAugmented MatrixSystem of Equations
Row-Echelon Form
The row-echelon form (REF) of a matrix is a special configuration that simplifies solving systems of linear equations. This form is characterized by a unique arrangement where each row has a leading entry (first non-zero number) further to the right than the row above it. Let's break it down:
- Non-zero rows are arranged above any rows that are completely zeroes.
- The leading entry of each row is strictly to the right of the leading entry of the row above.
- All entries in each column below a leading entry must be zero.
Reduced Row-Echelon Form
Reduced row-echelon form (RREF) takes the conditions of row-echelon form and adds a few more to refine a matrix further. A matrix in RREF is even more methodically structured:
- Every leading entry is exactly 1, ensuring simplicity and ease of interpretation.
- Each leading 1 is the sole non-zero entry in its column, eliminating unnecessary entries for clearer solutions.
Augmented Matrix
An augmented matrix is a powerful tool that represents a system of linear equations. It includes the coefficients of the variables and the constants from the equations. Visually, you'll notice:
- The columns before the last contain the coefficients of the variables in the equations.
- The last column holds the constants, which would usually appear on the right side of the equal sign in standard equations.
System of Equations
A system of equations consists of multiple equations that are solved together for a common solution. By representing it with matrices, the complex relationships in multiple variables become easier to handle using linear algebra techniques. Here's what you need to know:
- Each row of the matrix represents a separate linear equation.
- By converting a matrix back into a system, you can interpret the solution, identify relationships among variables, or detect inconsistencies.
Other exercises in this chapter
Problem 10
Find the inverse of the matrix if it exists. \(\left[\begin{array}{rr}{-7} & {4} \\ {8} & {-5}\end{array}\right]\)
View solution Problem 10
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Solve the system, or show that it has no solution. If the system has infinitely many solutions, express them in the ordered-pair form given in Example 3. $$\lef
View solution Problem 10
Use back-substitution to solve the triangular system. $$ \left\\{\begin{aligned} 4 x+3 z &=10 \\ 2 y-z &=-6 \\ \frac{1}{2} z &=4 \end{aligned}\right. $$
View solution